Engineering Mathematics 4 Episode 14 pdf
... 32. (d) 33. (d) 34. (a) 35. (b) 36. (a) 37. (d) 38. (c) 39. (b) 40 . (d) 41 . (d) 42 . (a) 43 . (d) 44 . (b) 45 . (b) 46 . (c) 47 . (b) 48 . (c) 49 . (c) 50. (c) 51. (c) 52. (d) 53. (b) 54. (a) 55. (b) 56. ... 32. (a) 33. (a) 34. (d) 35. (d) 36. (c) 37. (c) 38. (a) 39. (d) 40 . (b) 41 . (b) 42 . (c) 43 . (a) 44 . (c) 45 . (d) 46 . (b) 47 . (d) 48 . (a) 49 . (d) 50. (a) 51....
Ngày tải lên: 13/08/2014, 09:20
Engineering Mathematics 4 Episode 1 ppsx
... using algebraic substitutions 41 4 48 .1 Introduction 41 4 48 .2 Algebraic substitutions 41 4 48 .3 Worked problems on integration using algebraic substitutions 41 4 48 .4 Further worked problems on integration using ... 20 1A4E 16 D 1 ð16 3 C A ð16 2 C 4 ð16 1 C E ð16 0 D 1 ð16 3 C 10 ð16 2 C 4 ð16 1 C 14 ð16 0 D 1 40 96 C 10 ð256 C 4 ð16 C 14 ð1 D 40 96 C2560 C 64 C 14...
Ngày tải lên: 13/08/2014, 08:21
Engineering Mathematics 4 Episode 2 docx
... sides by 5x gives: 5x 3 x D 5x 4 5 Cancelling gives: 15 D 4x1 15 4 D 4x 4 i.e. x D 15 4 or 3 3 4 Check: LHS D 3 3 3 4 D 3 15 4 D 3 4 15 D 12 15 D 4 5 D RHS (Note that when there is ... ð10 3 (b) 0.375 m 2 (c) 240 ð10 3 Pa 60 ENGINEERING MATHEMATICS Check: LHS D 3 4 2 D 3 6 D 1 2 RHS D 4 3 4 C 4 D 4 12 C4 D 4 8 D 1 2 Hence the solution t...
Ngày tải lên: 13/08/2014, 08:21
Engineering Mathematics 4 Episode 3 pptx
... D 2u C 2a1 Substituting s D 144 , t D 4intos D ut C 1 2 at 2 gives: 144 D 4u C 1 2 a 4 2 i.e. 144 D 4u C 8a2 Multiplying equation (1) by 2 gives: 84 D 4u C 4a3 Subtracting equation (3) ... (a) 1 7 e 3 .46 29 (b) 8.52e 1.2651 (c) 5e 2.6921 3e 1.1171 (a) 4. 55 848 (b) 2 .40 444 (c) 8.051 24 6. (a) 5.6823 e 2.1 347 (b) e 2.1127 e 2.1127 2 (c) 4 e 1.7295 1 e 3.6817...
Ngày tải lên: 13/08/2014, 08:21
Engineering Mathematics 4 Episode 4 potx
... 1 or n P r = n! .n − r /! Thus, 4 P 2 D 4 3 D 12 or 4 P 2 D 4! 4 2! D 4! 2! D 4 ð3 ð2 2 D 12 Problem 19. Evaluate: (a) 7 C 4 (b) 10 C 6 (a) 7 C 4 D 7! 4! 7 4 ! D 7! 4! 3! D 7 ð6 ð5 4 ð3 ð2 4 ð3 ð23 ð2 D ... decimal places. [2. 742 , 4. 742 ] 2. 3x 3 10x D 14, correct to 4 significant figures. [2.313] 3. x 4 3x 3 C 7x D 12, correct to 3 decimal places. [...
Ngày tải lên: 13/08/2014, 08:21
Engineering Mathematics 4 Episode 5 pptx
... 1.0724x 0. 344 3x C 0. 344 3120 D 1.0724x 0. 344 3120 D 1.07 24 0. 344 3x 41 .316 D 0.7281x x D 41 .316 0.7281 D 56. 74 m From equation (2), height of building, h D 1.0724x D 1.07 24 56. 74 D 60 .85 ... theorem: 41 2 D 9 2 CYZ 2 from which YZ D p 41 2 9 2 D 40 units. Thus, sin X = 40 41 ,tanX = 40 9 = 4 4 9 , cosec X = 41 40 = 1 1 40 ,secX = 41 9 = 4 5 9...
Ngày tải lên: 13/08/2014, 08:21
Engineering Mathematics 4 Episode 6 ppsx
... is: (a) 2 74. 7 m (b) 36 .4 m (c) 34. 3 m (d) 94. 0 m 32. (7, 141 ° ) in Cartesian co-ordinates is: (a) (5 .44 , 4. 41) (b) (5 .44 , 4. 41) (c) (5 .44 , 4. 41) (d) (5 .44 , 4. 41) 33. If tanA D 1 .42 76, sec ... x D 6.3680 3.7588 D 1.6 942 i.e. tan x D 1.6 942 , and x D tan 1 1.6 942 D 59 .44 9 ° or 59 ° 27 [Check: LHS D 4sin59. 44 9 ° 20 ° D 4sin39 .44 9 ° D 2. 542 RHS D 5c...
Ngày tải lên: 13/08/2014, 08:21
Engineering Mathematics 4 Episode 7 ppsx
... below. t 10 20 30 40 50 60 80 100 s 4. 9 7.6 11.1 15 .4 20 .4 26 .4 40.6 58.0 s 3 t 0.19 0.23 0.27 0.31 0.35 0.39 0 .47 0.55 240 ENGINEERING MATHEMATICS Stress s N/cm 2 8 .46 8. 04 7.78 Temperature ... 2x 2 3x 4and y D 2 4x y D 2x 2 3x 4 is a parabola and a table of values is drawn up as shown below: x 2 1012 3 2x 2 8202818 3x 6303 6 9 4 4 4 4 4 4 4 y 10 1 4...
Ngày tải lên: 13/08/2014, 08:21
Engineering Mathematics 4 Episode 8 docx
... 2197 6 742 . 14 ° D 2197 6 382. 14 ° since 742 . 14 Á 742 . 14 ° 360 ° D 382. 14 ° D 2197 66 22. 14 ° since 382. 14 ° Á 382. 14 ° 360 ° D 22. 14 ° Problem 2. Determine the value of 7 Cj5 4 , expressing ... [ p 74 6 144 .46 ° ] 4 D p 74 4 6 4 ð 144 .46 ° D 547 6 6 577. 84 ° D 547 6 66 217. 84 ° or 547 6 66 217 ° 15 in polar form. Since r 6 Â...
Ngày tải lên: 13/08/2014, 08:21