Designing Capable and Reliable Products Episode 2 pptx
Designing Capable and Reliable Products Episode 2 pptx
... the
potential risks of failure and their consequences, both from normal use and fore-
seeable misuse, is a key element in designing capable and reliable products (Wright,
1989).
1.5 Designing for quality
The ... FMEA input into designing capable and reliable products
Designing for quality 25
published in the ®eld of Design for Quality (DFQ) compared to Design for...
Designing Capable and Reliable Products Episode 2 Part 2 pptx
... ÿ4 .28 35
105 2. 6 26 40 0.0397 4.6540 ÿ3 .20 62
135 2. 4 24 64 0.0637 4.9053 2. 720 8
165 4.4 44 108 0.1077 5.1059 2. 1 720
195 6.4 64 1 72 0.1716 5 .27 30 ÿ1.6700
22 5 6.9 69 24 1 0 .24 06 5.4161 ÿ1 .29 02
255 ... 0.7494 6.0753 0. 324 9
465 5 .2 52 8 02 0.8014 6.1 420 0.48 02
495 3.5 35 837 0.8364 6 .20 46 0.5935
525 2. 9 29 866 0.8654 6 .26 34 0.6959
555 2. 7 27 893 0.8...
Designing Capable and Reliable Products Episode 2 Part 1 ppsx
... stress
are shown below and involve all three principal stresses (Dowling, 1993):
C
1
1
2
s
1
ÿ s
2
jj
Su
c
ÿ 2Su
Su
c
s
1
s
2
!
4:59
C
2
1
2
s
2
ÿ s
3
jj
Su
c
ÿ 2Su
Su
c
s
2
s
3
!
4:60
C
3
1
2
s
3
ÿ ... L, for the stress system.
2Sy
2
s
1
ÿ s
2
2
s
2
ÿ s
3
2
s
3
ÿ s
1
2
4:57
where s
1
, s
2
, s
3
are the principal stresse...
Designing Capable and Reliable Products Episode 2 Part 3 docx
... MPa
Su
3:45
2
Á
2
HB
0:1 52
2
Á
2
HB
0:1 52
2
Á
2
HB
0:5
3:45
2
 4:31
2
0:1 52
2
 150:07
2
0:1 52
2
 4:31
2
0:5
Su
27 :2 MPa
Therefore:
Su $ N517:7; 27 :2 MPa
Typically ... 0 .20 4
150.3 19 0.6 129 0 .28 7
150.3 20 0.64 52 0.3 72
151.3 21 0.6774 0.460
1 52. 8 22 0.7097 0.5 52
1 52. 8 23 0.7419 0.649
1 52. 8 24 0.77 42 0.753
1 52....
Designing Capable and Reliable Products Episode 2 Part 4 ppt
... process and designing
capable and reliable products that have been highlighted through industrial
collaboration.
Introduction 25 5
. Changing the role of design engineers
. Utilizing new and existing ... 1996):
. Gather and present facts about products and processes
. Clarify and analyse relationships between products and processes
. Measure performance
. Highlight...
Designing Capable and Reliable Products Episode 2 Part 5 doc
... process of designing
capable and reliable products. For example, an important aspect of the use of CA
Figure 5.14
Techniques for redesigning products and processes (Huang, 1996)
Summary 27 5
and is ... gives:
407, 415, 420 , 424 , 426 , 428 , 433, 433, 436, 438, 440, 4 42, 443, 444, 445, 447, 447, 449,
450, 450, 451, 4 52, 4 52, 453, 453, 454, 455, 456, 459, 460, 4 62, 466, 46...
Designing Capable and Reliable Products Episode 2 Part 6 ppsx
... Occurrence, Severity and Detectability
29 6 Appendix III
distribution for comparison:
y
Nw
2
p
exp
ÿ
x ÿ
2
2
2
50 Â 18
23 :45
2
p
exp
ÿ
x ÿ 457:76
2 23 :45
2
2
To ®nd ... ÿ49:98
2
7 Â49:97 ÿ49:98
2
10 Â49:98 ÿ49:98
2
8 Â49:99 ÿ 49:98
2
6 Â50 ÿ49:98
2
2 Â50:01 ÿ49:98
2
1 Â50: 02 ÿ49:98
2
40
v
u
u
u
u
u
t
0...
Designing Capable and Reliable Products Episode 2 Part 7 pdf
... processes
Sand casting ± Steel and iron
Sand casting ± Copper alloys
Sand casting ± Aluminium and magnesium alloys
Shell moulding ± Steel, iron and copper alloys
Shell moulding ± Aluminium and magnesium ... suppliers and possibly fewer quality problems
. Systematic component costing and process selection
. Improved yields
. Lower component and assembly costs
. Standardize compon...
Designing Capable and Reliable Products Episode 2 Part 8 pdf
... Calculation of q
m
Drawing number FQ2186 m
p
1 Â 1 :2 1 :2
g
p
1 Â1 Â 1:7 Â 1 Â1 Â1 :2 2: 04
Adjusted tolerance
Design tolerance
m
p
 g
p
Æ0 :25
1 :2 Â 2: 04
Æ0:1 02
t
p
9 Â 1 9
s
p
1 Â 1 ... Calculation of q
m
Drawing number FF476 m
p
1 Â 1 :2 1 :2
g
p
1 Â1 Â 1 Â 1 Â1 Â1 :2 1 :2
Adjusted tolerance
Design tolerance
m
p
 g
p
Æ0 :25
1 :2 Â 1 :2
Æ...
Designing Capable and Reliable Products Episode 2 Part 9 ppsx
... mean () and standard deviation ()
Lognormal distribution
exp
2
2
exp 2 2
2
ÿexp 2
2
0:5
2- parameter Weibull distribution
% Á ÿ
1
1
!
% Á
ÿ0: 926
See ... 1:5Â1:05
0:0 32 mm
The standard deviation for one half of the tolerance can be estimated by:
H
b
%
T
2
Á q
2
m
12
0: 025 Â 2: 5
2
12
0:013 mm
Using the algebr...
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