Engineering Mathematics 4 Episode 1 ppsx

Engineering Mathematics 4 Episode 1 ppsx

Engineering Mathematics 4 Episode 1 ppsx

... 10 17 10 0 01 21 11 18 10 010 22 12 19 10 011 23 13 20 10 100 24 14 21 1 010 1 25 15 22 10 110 26 16 23 10 111 27 17 24 11 000 30 18 25 11 0 01 31 19 26 11 010 32 1A 27 11 011 33 1B 28 11 100 34 1C 29 11 1 01 ... 0 0 1 00 01 1 1 2 0 010 2 2 3 0 011 3 3 4 010 0 4 4 5 010 1 5 5 6 011 0 6 6 7 011 1 7 7 8 10 00 10 8 9 10 01 11 9 10 10 10 12...

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Engineering Mathematics 4 Episode 6 ppsx

Engineering Mathematics 4 Episode 6 ppsx

... 34. 3 m (d) 94. 0 m 32. (7, 14 1 ° ) in Cartesian co-ordinates is: (a) (5 .44 , 4. 41) (b) (5 .44 , 4. 41) (c) (5 .44 , 4. 41) (d) (5 .44 , 4. 41) 33. If tanA D 1 .42 76, sec A is equal to: (a) 0. 819 0 (b) 0.5737 ... resultant OA D p 17 257 D 13 1.4V Applying the sine rule: 13 1 .4 sin 13 5 ° D 10 0 sin AOB from which, sin AOB D 10 0 sin 13 5 ° 13 1 .4 D 0.53 81 Hence ang...

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Engineering Mathematics 4 Episode 7 ppsx

Engineering Mathematics 4 Episode 7 ppsx

... each equation as shown below. x 10 1 3x  1 4 12 2 34 ENGINEERING MATHEMATICS (c) y D4x C 4 x 3 2 10 123 y 16 12 8 4 0 4 8 (d) y D4x  5 x 3 2 10 1 2 3 y 73 1 5 9 13 17 Each of the graphs ... shown below. t 10 20 30 40 50 60 80 10 0 s 4. 9 7.6 11 .1 15 .4 20 .4 26 .4 40.6 58.0 s 3 t 0 .19 0.23 0.27 0. 31 0.35 0.39 0 .47 0.55 240 ENGINEERING MATHEMA...

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Engineering Mathematics 4 Episode 10 ppsx

Engineering Mathematics 4 Episode 10 ppsx

... Y 3.5 2 41 6.57 69.9 5.0 318 5.07 14 6 .9 7.0 1 74 3.07 2.9 10 11 0 0.07  61. 1 12 14 7 1. 93  24. 1 15 12 2 4. 93 49 .1 18 86 7.93 85 .1  X D 70.5, X D 70.5 7 D 10 .07  Y D 11 98, Y D 11 98 7 D 17 1 .1 xy ... x 2 y 2 45 9.2 43 .2 48 86  744 .8 25.7 215 80 8.9 9 .4 8 4. 3 0 3733 46 .5 3.7 5 81  242 .1 24. 3 2 41 1 6 74. 8 62.9 7 242  xy D 217 2 ...

Ngày tải lên: 13/08/2014, 09:20

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Engineering Mathematics 4 Episode 2 docx

Engineering Mathematics 4 Episode 2 docx

... equations: 1. 2 C 3 4 y D 1 C 2 3 y C 5 6 [ 2 ] 2. 1 4 2x 1 C3 D 1 2  4 1 2  3. 1 5 2f  3 C 1 6 f 4 C 2 15 D 0[2] 4. 1 3 3m6 1 4 5mC4C 1 5 2m9 D3 [12 ] 5. x 3  x 5 D 2 [15 ] 6. 1 ... sides by 5x gives: 5x  3 x  D 5x  4 5  Cancelling gives: 15 D 4x 1 15 4 D 4x 4 i.e. x D 15 4 or 3 3 4 Check: LHS D 3 3 3 4 D 3 15 4 D 3 ...

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Engineering Mathematics 4 Episode 3 pptx

Engineering Mathematics 4 Episode 3 pptx

... D  11  š   11  2  4 3 4 23 D C 11 š p 12 1 C 48 6 D 11 š p 16 9 6 D 11 š 13 6 D 11 C 13 6 or 11  13 6 Hence x = 24 6 = 4 or 2 6 = − 1 3 (as in Problem 1( b)). Problem 10 . Solve 4x 2 C ... base 10 of both sides gives: log 10 x 3.2 D log 10 41 .15 3.2log 10 x D log 10 41 .15 Hence log 10 x D log 10 41 .15 3.2 D 0.5 044 9 Thus x D antil...

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Engineering Mathematics 4 Episode 4 potx

Engineering Mathematics 4 Episode 4 potx

... frequency, f 1 D 1 2  k 1 I 1 D 1 2 k 1 2 1 I  1 2 1 D 1 2 [ 1 C0. 04 k] 1 2 [ 1 0.02I]  1 2 D 1 2 1 C0. 04 1 2 k 1 2 1 0.02  1 2 I  1 2 D 1 2 k 1 2 I  1 2 1 C0. 04 1 2 1 0.02  1 2 i.e. f 1 D f 1 C0. 04 1 2 1 0.02  1 2 ³ ... true? (a) 1 4 x 2 D 1  4  1  x 4  2 D 1 4 2  1  x 4  2 D...

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Engineering Mathematics 4 Episode 5 pptx

Engineering Mathematics 4 Episode 5 pptx

... cot 1 2 .12 73 (a) sec 1 2. 31 64 D cos 1  1 2. 31 64  D cos 1 0 .43 17 D 64. 42 ° or 64 ° 25  or 1. 1 24 radians (b) cosec 1 1 .17 84 D sin 1  1 1 .17 84  D sin 1 0. 848 6 D 58.06 ° or 58 ° 4  or 1. 013 radians (c) ... 1. 0724x 0. 344 3x C 0. 344 3 12 0 D 1. 0724x 0. 344 3 12 0 D 1. 07 24 0. 344 3x 41 . 316 D 0.7281x x D 41 . 316 0.72 81...

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Engineering Mathematics 4 Episode 8 docx

Engineering Mathematics 4 Episode 8 docx

... Cj5 4 D [ p 74 6 14 4 .46 ° ] 4 D p 74 4 6 4 ð 14 4 .46 ° D 547 6 6 577. 84 ° D 547 6 66 217 . 84 ° or 547 6 66 217 ° 15  in polar form. Since r 6  D r cos  C jr sin Â, 547 6 6 217 . 84 ° D 547 6 cos 217 . 84 ° C ... theorem D 219 7 6 742 . 14 ° D 219 7 6 382. 14 ° since 742 . 14 Á 742 . 14 °  360 ° D 382. 14 °  D 219 7 66 22. 14 ° since 382. 14...

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Engineering Mathematics 4 Episode 9 pptx

Engineering Mathematics 4 Episode 9 pptx

... 20 12 20 D 9 15 10 0 11 0 14 11 5 95 20 14 20 D 10 1 2 15 12 0– 14 0 4 14 5 11 5 30 4 30 D 2 15 15 0 17 0 2 17 5 14 5 30 2 30 D 1 15 PRESENTATION OF STATISTICAL DATA 311 Now try the following exercise Exercise 12 9 Further ... classes for these data. 80 90 70 11 0 90 16 0 11 0 80 14 0 30 90 50 10 0 11 0 60 10 0 80 90 11 0 80 10 0 90 12 0 70 13 0 17 0 80...

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