The boundary element method with programming for engineers and scientists - phần 2 pptx

...  >@  >@  >@ , G , G , G v E v E v E zxzxyzyzxyxy yxzz zxyy zyxx WJWJWJ VVVH VVVH VVVH 111 1 1 1     v E G  12 22 2 123 22 2 11 1 2 3 22 2 123 12 23 13 12 1 2 2 3 1 3 12 23 13 11 22 33 21 1 1 2 2 3 3 11 2 2 33 22 2 22 2 22 2 xxx yyy zzz xx xx xx yy yy yy zz zz zz xy ... linear elements (c) one quadratic element 40 The Boundar...

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... References 20 2 8 Element- by -element techniques and Parallel Programming 20 3 8.1 Introduction 20 3 8.1 The Element by Element Concept 20 4 8.1.1 Element- by -element storage requirements 20 6 8 .2 PROGRAM ... iterative solution 20 6 8 .2. 1 Sample input file 21 1 8 .2. 2 Sample output file 21 2 8.3 PROGRAM 8 .2 : Replacing assembly by element- by -eleme...

Ngày tải lên: 13/08/2014, 08:21

... 0. -4 .5 0. -4 . 0. -3 .5 0. -3 . 0. -2 .5 0. -2 . 0. -1 .5 BOUNDARY INTEGRAL EQUATIONS 117 or in discretised form using line segments (5.51) where (5. 52) The flows at P a in x- and y-directions ...  FluxtNt Potential/eTemperaturuNu GeometryN e nn e nn e nn [[ [[ [[ ¦ ¦ ¦ xx 1 2 3 4 5 6 7 8 1 1 u 1 2 3 4 5 6 7 8 2 1 1 2 uu 2 2 u 94 The...

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Ngày tải lên: 13/08/2014, 08:21

... -0 . 022 36 0.00079 0.00079 -0 .00787 -0 .00 123 - 0.00787 -0 .00508 -0 .00508 -0 .00508 -0 .00787 - 0.00787 -0 .00 123 -1 0.00000 0.00000 0.00000 -1 0.00000 0.00000 0.00000 -1 0.00000 0.00000 0.00000 -1 0.00000 ... distinguish between values inside the domain and on the boundary. For the computation of results the integral equatio...

Ngày tải lên: 13/08/2014, 08:21

... 0.00 -2 .986810 0.00 -0 .28 1030 0.00 -2 . 121 320 Results, Element 1 u= 0.00000 -0 .00060 0.00 029 0.00000 0.00 021 -0 .00041 t= 0.00000 -2 .98681 0.00000 -0 .28 103 0.00000 -2 . 121 32 The input ... Results, Element 12 u= 0.000 0.000 0.000 0.000 0.000 0.000 t= -2 98.8 92 6 .27 7 29 8.8 92 6 .27 7 0.000 11.876 The input file for this p...

Ngày tải lên: 13/08/2014, 08:21

... IF(nreg==1)THEN ! right xsi= (1 d2) /2. + Glcor(m) * (1.+d2) /2. dxdxb= (1.+d2) /2. ELSE IF(nreg= =2) THEN ! left xsi= (-1 d2) /2. + Glcor(m) * (1 d2) /2 dxdxb= (1 d2) /2 END IF CASE (2) ! Node2 ... 2 3 2 1 3 4 I t 10 I t 20 II t 20 II t 10 I t 11 I t 12 I t 21 I t 22 II t 22 II t 21 II t 12 II t 11 1 1 I u 2 1 II u 2 0 I u 1 1 II u 1 0 I u 2...

Ngày tải lên: 13/08/2014, 08:21

... aQe Z  ˆ (,) 1/ 2 (,) it uQt aQ e d Z SZ   ³ \ \ 22 2 2 222 0 uuu ku F xyz www  www 2 (,) (,) (,) 0uQ kuQ FQ ZZZ '  394 The Boundary Element Method with Programming The integral ... Analysis with Boundary Elements 8: 10 9-1 12. 4 . Aliabadi M. H. (20 02) The Boundary Element Method (Volume 2) . J. Wiley. 5. Stroud, A.H. and Secrest...

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... 2 3 2 3 2x t 1 2 1 2 3 1x t F x2 1 2 x u G 2 2x t 2 1x t dS t x dS x u G S 1 2 3 4 5 BE Region I F x3 F y3 3 2 1 3 2x t 3 2y t 1 2 1 2 3 1x t F x2 F x1 F y2 F y1 4 32 The Boundary ... previously if the point a P is not one of the cell nodes. If P a coincides with the nodes of cells, then the integrand tends to infinity with o(r...

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Ngày tải lên: 13/08/2014, 08:21