COMPUTATIONAL MATERIALS ENGINEERING Episode 4 potx

... quantitatively compare the speed-up algorithms with the vanilla code. 80 COMPUTATIONAL MATERIALS ENGINEERING FIGURE 3- 14 Snapshot of circle shrinking under curvature on a 2D triangular lattice, ... such a system simulated using the Potts model. Instead of bubbles we have domains 64 COMPUTATIONAL MATERIALS ENGINEERING will each do so using incorrect information about neighborin...

Ngày tải lên: 13/08/2014, 08:21

... COMPUTATIONAL MATERIALS ENGINEERING and for the stress field, σ 13 = − b 3 2π  C 44 C 55 − C 2 45  1/2  C 45 x 1 − C 55 x 2 C 44 x 2 1 − 2 C 45 x 1 x 2 + C 55 x 2 2  σ 23 = − b 3 2π  C 44 C 55 − ... displacement field, u 3 = − b 3 2π arctan  (C 44 C 55 − C 2 45 ) 1/2 x 2 C 44 x 1 − C 2 45 x 2  (8.108) 288 COMPUTATIONAL MATERIALS ENGINEERING 8 .4. 2 Newtoni...

Ngày tải lên: 13/08/2014, 08:21

... Conducting Discussions 1 14 CHAPTER 7: NONTECHNOLOGICAL ALTERNATIVES TO LECTURES Teaching Engineering - Wankat & Oreovicz CHAPTER 7 NONTECHNOLOGICAL ALTERNATIVES TO LECTURE 1 14 The lecture method ... as brief breaks in a lecture class. Engineering students are generally very task oriented, so give the students a task. For example, “We have discussed the engineering and political...

Ngày tải lên: 12/08/2014, 08:22

... Multiple Components and Phases 241 7 .4. 1 Model Formulation 241 7 .4. 2 Entropy Density Contributions 242 7 .4. 3 Evolution Equations 245 7 .4. 4 Nondimensionalization 248 7 .4. 5 Finite Difference Discretization ... Stored Energy 77 3.3.7 Summary 80 3 .4 Speed-Up Algorithms 80 3 .4. 1 The Boundary-Site Algorithm 81 3 .4. 2 The N-Fold Way Algorithm 82 3 .4. 3 Parallel Algorithm 84 3 .4...

Ngày tải lên: 13/08/2014, 08:21

... site fractions on each sublattice we have  i y s i =1 (2. 94) and 0 ≤ y s i ≤ 1 (2.95) 34 COMPUTATIONAL MATERIALS ENGINEERING Equations (2. 94) and (2.95) can be viewed as constraints of the thermodynamic ... dilute solution limit. 28 COMPUTATIONAL MATERIALS ENGINEERING Mole Fraction Mo Activity a 0 1 0 0.2 0 .4 0.6 0. 81 Fe Mo Liquid Mole Fraction Mo Mo Fe Solid (bcc) 0 0....

Ngày tải lên: 13/08/2014, 08:21

... -17368 .44 1+170.73*T- 24. 3*T*LN(T) -4. 723E- 04* T**2+2562600*T**(-1)-2. 643 E+08*T**(-2)+1.2E+10*T**(-3); 6.00000E+03 N ! FUNCTION GHSERCR 2.98 140 E+02 -8856. 94+ 157 .48 *T-26.908*T*LN(T) +.0018 943 5*T**2-1 .47 721E-06*T**3+139250*T**(-1); ... -8856. 94+ 157 .48 *T-26.908*T*LN(T) +.0018 943 5*T**2-1 .47 721E-06*T**3+139250*T**(-1); 2.18000E+03 Y - 348 69. 344 + 344 .18*T-50*T*LN(T)-2.8...

Ngày tải lên: 13/08/2014, 08:21

... algorithm for the Potts model. 86 COMPUTATIONAL MATERIALS ENGINEERING 0.05 0 −0.05 0 2000 40 00 6000 8000 1 × 10 4 Time (MCS) dp/dt Simulation Theory FIGURE 3 -40 Time rate of change in the size ... basic cellular automata. 110 COMPUTATIONAL MATERIALS ENGINEERING Particle Dimple Boundary Grain B Grain A r ρ y o θ γ BP γ AP (a) 55 50 45 40 35 30 25 10 15 20 25 30 40 35 X...

Ngày tải lên: 13/08/2014, 08:21

... each 128 COMPUTATIONAL MATERIALS ENGINEERING κ =15−  k ∈ 1st nn k ∈ 2nd nn φ k ε k (4. 14) which returns 0 for a locally flat grain boundary. Combining equation (4. 14) with Algorithm 4- 4 leads ... given in the text is indicated. 130 COMPUTATIONAL MATERIALS ENGINEERING FIGURE 4- 11 Figure 4- 10 continued. Corrected (Probabilistic) Moore 0.971 74 0. 545 406 FIGURE 4- 12 A c...

Ngày tải lên: 13/08/2014, 08:21

... [ZWZ + 03], Guillemot (20 04) [GGCH 04] , Janssens (20 04) [JHF 04] , Khvastunkov (20 04) [KL 04] , Lan (20 04) [LLHL 04] , Li (20 04) [LA 04] , Raabe (20 04) [Raa04a, Raa04a], Saunier (20 04) [SCSB 04] , Lan (2006) [LLL06]. Lattice ... 1 − 1 −3 9 4 +1+1+1+1 +4 16 [(1/16) · 64] 1/2 +1 − 1+1+1 +2 4 = (4) 1/2 +1+1− 1+1 +2 4 +1+1+1− 1+2 4 +1 − 1 − 1+1 0 0 +1 − 1+1− 10 0 +1+1− 1 − 10 0...

Ngày tải lên: 13/08/2014, 08:21

... (Length) c(x)/c 0 0 246 810 sqrt (4 Dt) = 100 2 1 0.5 0 0.2 0 .4 0.6 1.0 0.8 5 20 FIGURE 5-8 Solutions to Fick’s second law for semi-inifinite sample. 1 64 COMPUTATIONAL MATERIALS ENGINEERING c i,t+∆t = ... with µ = 0 µ + RT ln a (5 .43 ) and with the definition of the activity coefficient a = fX [compare equation (2.67)] we obtain ∇µ = RT (∇ln f + ∇ln X) (5 .44 ) Equation (5 .44 ) can...

Ngày tải lên: 13/08/2014, 08:21