COMPUTATIONAL MATERIALS ENGINEERING Episode 4 potx
COMPUTATIONAL MATERIALS ENGINEERING Episode 4 potx
... quantitatively compare the speed-up
algorithms with the vanilla code.
80 COMPUTATIONAL MATERIALS ENGINEERING
FIGURE 3- 14 Snapshot of circle shrinking under curvature on a 2D triangular lattice, ... such a system simulated using the Potts model. Instead of bubbles we have domains
64 COMPUTATIONAL MATERIALS ENGINEERING
will each do so using incorrect information about neighborin...
COMPUTATIONAL MATERIALS ENGINEERING Episode 13 potx
... COMPUTATIONAL MATERIALS ENGINEERING
and for the stress field,
σ
13
= −
b
3
2π
C
44
C
55
− C
2
45
1/2
C
45
x
1
− C
55
x
2
C
44
x
2
1
− 2 C
45
x
1
x
2
+ C
55
x
2
2
σ
23
= −
b
3
2π
C
44
C
55
− ... displacement field,
u
3
= −
b
3
2π
arctan
(C
44
C
55
− C
2
45
)
1/2
x
2
C
44
x
1
− C
2
45
x
2
(8.108)
288 COMPUTATIONAL MATERIALS ENGINEERING
8 .4. 2 Newtoni...
Wankat & Oreovicz - Teaching Engineering Episode 4 potx
... Conducting Discussions
1 14
CHAPTER 7: NONTECHNOLOGICAL ALTERNATIVES TO LECTURES
Teaching Engineering - Wankat & Oreovicz
CHAPTER 7
NONTECHNOLOGICAL
ALTERNATIVES TO LECTURE
1 14
The lecture method ... as brief breaks in a lecture class.
Engineering students are generally very task oriented, so give the students a task. For
example, “We have discussed the engineering and political...
COMPUTATIONAL MATERIALS ENGINEERING Episode 1 pptx
... Multiple Components and Phases 241
7 .4. 1 Model Formulation 241
7 .4. 2 Entropy Density Contributions 242
7 .4. 3 Evolution Equations 245
7 .4. 4 Nondimensionalization 248
7 .4. 5 Finite Difference Discretization ... Stored Energy 77
3.3.7 Summary 80
3 .4 Speed-Up Algorithms 80
3 .4. 1 The Boundary-Site Algorithm 81
3 .4. 2 The N-Fold Way Algorithm 82
3 .4. 3 Parallel Algorithm 84
3 .4...
COMPUTATIONAL MATERIALS ENGINEERING Episode 2 pot
... site fractions on each sublattice we have
i
y
s
i
=1 (2. 94)
and
0 ≤ y
s
i
≤ 1 (2.95)
34 COMPUTATIONAL MATERIALS ENGINEERING
Equations (2. 94) and (2.95) can be viewed as constraints of the thermodynamic ... dilute solution limit.
28 COMPUTATIONAL MATERIALS ENGINEERING
Mole Fraction Mo
Activity a
0
1
0
0.2
0
.4 0.6 0.
81
Fe
Mo
Liquid
Mole Fraction Mo
Mo
Fe
Solid (bcc)
0
0....
COMPUTATIONAL MATERIALS ENGINEERING Episode 3 doc
... -17368 .44 1+170.73*T- 24. 3*T*LN(T)
-4. 723E- 04* T**2+2562600*T**(-1)-2. 643 E+08*T**(-2)+1.2E+10*T**(-3);
6.00000E+03 N !
FUNCTION GHSERCR 2.98 140 E+02 -8856. 94+ 157 .48 *T-26.908*T*LN(T)
+.0018 943 5*T**2-1 .47 721E-06*T**3+139250*T**(-1); ... -8856. 94+ 157 .48 *T-26.908*T*LN(T)
+.0018 943 5*T**2-1 .47 721E-06*T**3+139250*T**(-1); 2.18000E+03 Y
- 348 69. 344 + 344 .18*T-50*T*LN(T)-2.8...
COMPUTATIONAL MATERIALS ENGINEERING Episode 5 pot
... algorithm for the Potts model.
86 COMPUTATIONAL MATERIALS ENGINEERING
0.05
0
−0.05
0 2000 40 00 6000 8000 1
×
10
4
Time (MCS)
dp/dt
Simulation
Theory
FIGURE 3 -40 Time rate of change in the size ... basic cellular automata.
110 COMPUTATIONAL MATERIALS ENGINEERING
Particle
Dimple
Boundary
Grain B
Grain A
r
ρ
y
o
θ
γ
BP
γ
AP
(a)
55
50
45
40
35
30
25
10 15 20 25 30 40 35
X...
COMPUTATIONAL MATERIALS ENGINEERING Episode 6 pdf
... each
128 COMPUTATIONAL MATERIALS ENGINEERING
κ =15−
k ∈ 1st nn
k ∈ 2nd nn
φ
k
ε
k
(4. 14)
which returns
0 for a locally flat grain boundary.
Combining equation (4. 14) with Algorithm 4- 4 leads ... given in the text is indicated.
130 COMPUTATIONAL MATERIALS ENGINEERING
FIGURE 4- 11 Figure 4- 10 continued.
Corrected (Probabilistic) Moore
0.971 74 0. 545 406
FIGURE 4- 12 A c...
COMPUTATIONAL MATERIALS ENGINEERING Episode 7 doc
... [ZWZ
+
03], Guillemot (20 04) [GGCH 04] , Janssens (20 04) [JHF 04] ,
Khvastunkov (20 04) [KL 04] , Lan (20 04) [LLHL 04] , Li (20 04) [LA 04] , Raabe (20 04) [Raa04a,
Raa04a], Saunier (20 04) [SCSB 04] , Lan (2006) [LLL06].
Lattice ... 1 − 1 −3 9
4
+1+1+1+1 +4 16 [(1/16) · 64]
1/2
+1 − 1+1+1 +2 4 = (4)
1/2
+1+1− 1+1 +2 4
+1+1+1− 1+2 4
+1 − 1 − 1+1 0 0
+1 − 1+1− 10 0
+1+1− 1 − 10 0...
COMPUTATIONAL MATERIALS ENGINEERING Episode 8 doc
... (Length)
c(x)/c
0
0
246 810
sqrt (4
Dt) = 100
2
1
0.5
0
0.2
0 .4
0.6
1.0
0.8
5
20
FIGURE 5-8 Solutions to Fick’s second law for semi-inifinite sample.
1 64 COMPUTATIONAL MATERIALS ENGINEERING
c
i,t+∆t
= ... with
µ =
0
µ + RT ln a (5 .43 )
and with the definition of the activity coefficient
a = fX [compare equation (2.67)] we obtain
∇µ = RT (∇ln f + ∇ln X) (5 .44 )
Equation (5 .44 ) can...
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