Castings 2 Episode 9 pps
Castings 2 Episode 9 pps
... 1063 1 495 1083 1453 327 1536 181 97 64 303 321 65 1 420 787 156 23 2 27 1 63 1 1410 23 68 17 380 7750 793 8 7 790 IO 665 7035 528 92 7 827 II 20 0 799 8 1 590 6577 ... 7017 698 6 IO 034 6 493 25 25 25 50 18 28 0 8180 83 82 821 0 11 020 726 5 - - - - - 1655 6646 7166 97 0 1 6535 - - - 7.14 5.47 5 .26 5.30 5.1...
Ngày tải lên: 13/08/2014, 08:21
MACHINERY''''S HANDBOOK 27th CD 2 Episode 9 pps
... 11.40 27 .10 43.70 48.00 54 .20 62. 40 40:1 8.60 20 .40 32. 90 36.10 40 .90 47.00 50:1 6 .90 16.40 26 .40 29 .00 32. 80 37.80 60:1 5.76 13.70 22 .10 24 .20 27 .40 31.60 70:1 4 .94 11.70 18 .90 20 .80 23 .50 27 .10 12- Inch ... 23 .10 52. 10 82. 70 90 .10 99 .10 … 30:1 19. 40 43.70 69. 40 75.70 83 .20 … 40:1 14.60 32. 90 52. 20 57.00 62. 70 … 50:1 11.70 26 .40 41 .90 45.80 50....
Ngày tải lên: 13/08/2014, 05:20
MODELLING OF MECHANICAL SYSTEM VOLUME 2 Episode 9 pps
... Z ε xx =−z ∂ 2 Z ∂x 2 + 1 2 ∂Z ∂x 2 + z 2 2 ∂ 2 Z ∂x 2 2 + ∂ 2 Z ∂x∂y 2 ε xy =−z ∂ 2 Z ∂x∂y + z 2 2 ∂ 2 Z ∂x∂y ∂ 2 Z ∂x 2 + ∂ 2 Z ∂y 2 + 1 2 ∂Z ∂x ∂Z ∂y ε yy =−z ∂ 2 Z ∂y 2 + 1 2 ∂Z ∂y 2 + z 2 2 ∂ 2 Z ∂y 2 2 + ∂ 2 Z ∂x∂y 2 [6. 89] In ... are: D ∂ 4 Z ∂x 4 + 2 ∂ 4 Z ∂x 2 ∂y 2 + ∂ 4 Z ∂y 4 ...
Ngày tải lên: 13/08/2014, 05:22
Castings 2 Episode 5 pps
... "C 1570 1 o 1 620 I 10 500 E E 400 $ 300 5 20 0 0 2 4 6 8 Strip thickness, mm a LM2511.5 mm 0 LM25 12. 5 mm A LM2513.5 mm A LM2516.5 mm 0 LM2516.5 mm GR + A17Si/l.5 ... K 2 300 5 m K 2. - .= 20 0 -0 - .,- a, 0 = W c a, 100 0 99 .7 AI Data from 6 x 12 test AA Data from 3 x 12 test 0 Data from 1.5 x 12 test A...
Ngày tải lên: 13/08/2014, 08:21
Castings 2 Episode 7 ppsx
... equilibrium eutectic liquid (data points in brackets) (Campbell 196 9).
Ngày tải lên: 13/08/2014, 08:21
Castings 2 Episode 10 ppsx
... over 2 4 8 16 32 64 25 0 1000 10 20 40 80 160 scales) decades at 20 %. Data from Street Years at 20 °C ( 197 7). Days at 20 °C ZA 27 alloy Data from 20 °C - Data from 95 °C 5 ... cavity are summarized in Figure 7 .26 . Without exception, all 22 0 Castings 16°C 20 -33°C 35°C (a) (b) (c) Figure 7.15 Cross-section of 25 mm diameter wax castings inject...
Ngày tải lên: 13/08/2014, 08:21
Castings 2 Episode 12 pps
... 194 6 A AI alloy RR 56 Jelm and Herres 194 6 results for steels IBF 194 8 results for iron: ASM handbook 199 6 pp 1 89- 191 and 20 2 -20 4 70 interpolated 3 hour 8 60 ? 1? 50 0 2 ... by Cibula in 195 5 have been repeatedly confirmed in Canadian research; Sahoo and Worth ( 199 0), Fasoyinu et al. (1 99 8), Popescu et al. ( 199 8) and Sadayappan et al. ( 19...
Ngày tải lên: 13/08/2014, 08:21
Dimensioning and Tolerancing Handbook Episode 2 Part 9 pps
... Model: ( ) ( ) ( ) 2 13 2 12 2 11 2 eScSaST ASM δδδ ++= ( ) ( )( )( ) ( )( )( ) ) 790 9 32( )4500 82( 2 ) 790 9 32( 2 2 222 627 221 018 696 45008 646 92 0 14 92 2 7 790 93 627 22 )0004)(548310()646 92 ( )017453( ./. ./ da ... 0.0005 0.00 12 0.600-0 .99 9 0.046 821 58 0.5654 92 0.0006 0.0015 1.000-1. 499 0.0 420 49 92 0.6 021 191 0.0008 0.0 02 1.500 -2. 799 0.048 096 84 0....
Ngày tải lên: 21/07/2014, 15:20
Mechanics 1 of materials hibbeler 6th Episode 2 Part 9 ppsx
Ngày tải lên: 21/07/2014, 17:20
Engineering Mechanics - Statics Episode 2 Part 9 ppsx
... F H w 2h a 2 ⎛ ⎜ ⎝ ⎞ ⎟ ⎠ 2 = tan θ max () wa 2F H = cos θ max () 2F H 4 F H 2 wa() 2 + = T max F H cos θ max () = F H 2 wa() 2 4 += wa 2 a 2 16h 2 1+= Guess h 1 m= Given T max wa 2 a 2 16h 2 1+= h Find h()= h 7. 09 m= Problem ... y−()= Σ M = 0; Mwy y 2 ⎛ ⎜ ⎝ ⎞ ⎟ ⎠ + wb b 2 ⎛ ⎜ ⎝ ⎞ ⎟ ⎠ + wa a 2 ⎛ ⎜ ⎝ ⎞ ⎟ ⎠ + wby− 0= My() wby 1 2 wy 2 − 1 2 wb 2 − 1 2...
Ngày tải lên: 21/07/2014, 17:20