ADVANCED MECHANICS OF COMPOSITE MATERIALS Episode 4 ppt

ADVANCED MECHANICS OF COMPOSITE MATERIALS Episode 4 ppt

ADVANCED MECHANICS OF COMPOSITE MATERIALS Episode 4 ppt

... The dependence of σ + 1 on v f is shown in Fig. 3 .44 . For very 92 Advanced mechanics of composite materials The first of these equations specifies the apparent longitudinal modulus of the ply and corresponds ... First-order microstructural model of a hybrid unidirectional ply. 1 24 Advanced mechanics of composite materials Here, v (1) f and v (2) f are volume frac...

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ADVANCED MECHANICS OF COMPOSITE MATERIALS Episode 1 ppt

ADVANCED MECHANICS OF COMPOSITE MATERIALS Episode 1 ppt

... Layer 183 4. 4.1. Linear Elastic Model 1 84 4 .4. 2. Nonlinear Models 187 4. 4.3. Two-Matrix Composites 201 4. 4 .4. Composites with Controlled Cracks 207 4. 5. Angle-Ply Orthotropic Layer 208 4. 5.1. Linear ... Loading 40 0 7.3 .4. Impact Loading 40 8 7 .4. Manufacturing Effects 41 9 7 .4. 1. Circumferential Winding and Tape Overlap Effect 42 0 7 .4. 2. Warping and Bending of Lam...

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ADVANCED MECHANICS OF COMPOSITE MATERIALS Episode 3 ppt

ADVANCED MECHANICS OF COMPOSITE MATERIALS Episode 3 ppt

... 82 Advanced mechanics of composite materials −0.1 −0.08 −0.06 −0. 04 −0.02 0 0 5 10 15 20 25 30 35 40 45 50 x t n s Fig. 3.22. Distribution of shear stresses along the fibers for k = 4, E f = ... material. Fig. 3.31. Testing of the matrix specimen. 86 Advanced mechanics of composite materials 3.3. Micromechanics of a ply Consider a unidirectional composite ply...

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ADVANCED MECHANICS OF COMPOSITE MATERIALS Episode 6 ppt

ADVANCED MECHANICS OF COMPOSITE MATERIALS Episode 6 ppt

... 4 A 12 =−S 1 +S 2 −S 4 cos 4 A 14 = S 3 sin 2φ +S 4 sin 4 A 22 = S 1 +S 2 − 2S 3 cos 2φ +S 4 cos 4 A 24 = S 3 sin 2φ −S 4 sin 4 A 44 = S 1 −S 4 cos 4 A 55 = S 5 +S 6 cos 2φ A 56 = 4S 6 sin 2φ A 66 = ... constant of integration. Then, substituting this result into Eq. (4. 1 04) and eliminating ε 2 with the aid of Eq. (4. 106), we have θ 2 +v  2 = C 1 ahB 44...

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ADVANCED MECHANICS OF COMPOSITE MATERIALS Episode 13 pptx

ADVANCED MECHANICS OF COMPOSITE MATERIALS Episode 13 pptx

... I.V. (1991). Fatigue failure of laminated carbon-fiber-reinforced plastic. Mechanics of Composite Materials, 27(1), 58–62. 42 0 Advanced mechanics of composite materials 7 .4. 1. Circumferential winding ... effects 42 9 A 44 γ 0 xyT − h 4 (A 14 κ xT +A 24 κ yT ) = 0 −A 14 γ 0 xyT + h 3 (A 11 κ xT +A 12 κ yT ) = 0 −A 24 γ 0 xyT + h 3 (A 12 κ xT +A 22 κ yT ) = 0...

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ADVANCED MECHANICS OF COMPOSITE MATERIALS Episode 2 ppsx

ADVANCED MECHANICS OF COMPOSITE MATERIALS Episode 2 ppsx

... form { σ } = [ S ] { ε } (2 .46 ) where { σ } = ⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩ σ x σ y σ z τ xy τ xz τ yz ⎫ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎬ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎭ { ε } = ⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩ ε x ε y ε z γ xy γ xz γ yz ⎫ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎬ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎭ [ S ] = ⎡ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎣ S 11 S 12 S 13 S 14 S 15 S 16 S 21 S 22 S 23 S 24 S 25 S 26 S 31 S 32 S 33 S 34 S 35 S 36 S 41 S 42 S 43 S 44 S 45 S 46 S 5...

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ADVANCED MECHANICS OF COMPOSITE MATERIALS Episode 5 potx

ADVANCED MECHANICS OF COMPOSITE MATERIALS Episode 5 potx

... (19 84) . Failure of the aluminum–boron plastic in static and cyclic tensile loading. Mechanics of Composite Materials, 20(1), 44 –52. Mileiko, S.T. (1982). Mechanics of metal-matrix fibrous composites. ... on Composite Materials (ICCM-10), Vol. 4, Characterization and Ceramic Matrix Composites , Canada, 1995, pp. 171–178. Chapter 4. Mechanics of a composite layer 155...

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ADVANCED MECHANICS OF COMPOSITE MATERIALS Episode 7 potx

ADVANCED MECHANICS OF COMPOSITE MATERIALS Episode 7 potx

... C 12 ε 1 +C 22 ε 2 −C 22 ω 2 , τ 12 = C 44 γ 12 −C 44 ω 12 (4. 151) in which C 11 = c 22 c ,C 22 = c 11 c ,C 44 = 1 c 44 ,C 12 =− c 12 c ,c= c 11 c 22 −c 2 12 Repeating the derivation of Eqs. (4. 145 ) but using this time Eqs. (4. 151) ... curve correspond to Figs. 4. 48 and 4. 49). 206 Advanced mechanics of composite materials 0 100 200 300 40 0 500 0 0 .4 0.8 1.2 1....

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ADVANCED MECHANICS OF COMPOSITE MATERIALS Episode 8 doc

ADVANCED MECHANICS OF COMPOSITE MATERIALS Episode 8 doc

... B 11 ε 0 x +B 12 ε 0 y +B 14 γ 0 xy +C 11 κ x +C 12 κ y +C 14 κ xy N y = B 21 ε 0 x +B 22 ε 0 y +B 24 γ 0 xy +C 21 κ x +C 22 κ y +C 24 κ xy N xy = B 41 ε 0 x +B 42 ε 0 y +B 44 γ 0 xy +C 41 κ x +C 42 κ y +C 44 κ xy M x = ... C 11 ε 0 x +C 12 ε 0 y +C 14 γ 0 xy +D 11 κ x +D 12 κ y +D 14 κ xy M y = C 21 ε 0 x +C 22 ε 0 y +C 24 γ 0 xy +D 21 κ x +D 22 κ y +D 24 κ xy M x...

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ADVANCED MECHANICS OF COMPOSITE MATERIALS Episode 9 potx

ADVANCED MECHANICS OF COMPOSITE MATERIALS Episode 9 potx

... (5 .44 ), we get S = B 44 γ 0 xy +C 44 κ xy ,H= C 44 γ 0 xy +D 44 κ xy (5.68) in which, in accordance with Eqs. (5.28) and (5 .41 ), B 44 = I (0) 44 ,C 44 = I (1) 44 −eI (0) 44 ,D 44 = I (2) 44 −2eI (1) 44 +e 2 I (0) 44 (5.69) Chapter ... A 12 ,A (1) 22 = A (2) 22 = A 22 , A (1) 14 =−A (2) 14 = A 14 ,A (1) 24 =−A (2) 24 = A 24 ,A (1) 44 = A (2) 44 = A...

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