ADVANCED MECHANICS OF COMPOSITE MATERIALS Episode 1 ppt

... (GPa) Specific gravity Wood 15 –20 16 0 23 1. 5 Bamboo 15 –30 550 36 0.8 Jute 10 –50 580 22 1. 5 Cotton 15 –40 540 28 1. 5 Wool 75 17 0 5.9 1. 32 Coir 10 –20 250 5.5 1. 5 Bagasse 25 18 0 9 1. 25 Rice 5 15 10 0 6 1. 24 Natural silk 15 ... 12 3 3.6. Composites with High Fiber Fraction 12 7 3.7. Phenomenological Homogeneous Model of a Ply 12 9 3.8. References 13 1 Chapter 4...

Ngày tải lên: 13/08/2014, 08:20

... study ε 1 = σ 1 E 1 −ν 12 σ 2 E 2 ε 2 = σ 2 E 2 −ν 21 σ 1 E 1 (3.58) γ 12 = 1 G 12 τ 12 The inverse form of these equations is σ 1 =  E 1 (ε 1 +ν 12 ε 2 ) σ 2 =  E 2 (ε 2 +ν 21 ε 1 ) (3.59) τ 12 = G 12 γ 12 where  E 1, 2 = E 1, 2 1 −ν 12 ν 21 and the ... Bundle number 12 345 10 .60.70.85 0.90.95 20.80.90.90.85 0.95 31. 01. 21. 11. 00.95...

Ngày tải lên: 13/08/2014, 08:20

... 2 .1 1.55 1. 6 1. 32 2 .1 2.65 1. 75 3.45 Longitudinal modulus, E 1 (GPa) 60 14 0 14 0 95 210 260 17 0 260 Transverse modulus, E 2 (GPa) 13 11 10 5 .1 19 14 0 19 15 0 Shear modulus, G 12 (GPa) 3.4 5.5 5 .1 ... under constant stress σ 1 = σ (1) 1 . As follows from Fig. 3.69, the final strain is ε ∗ 1 = σ (1) 1 E ∗ 1 110 Advanced mechanics of composite ma...

Ngày tải lên: 13/08/2014, 08:20

... we get 1 +ν 21 E 1 < 1 +ν 12 E 2 ≤ 1 2G 12 or 1 +ν 21 E 1 < 1 2G 12 Chapter 4. Mechanics of a composite layer 16 3 −300 −250 −200 15 0 10 0 −50 50 10 0 15 0 −2 1. 8 1. 6 1. 4 1. 2 1 −0.8 ... 11 00 σ (2) x 225 690 11 25 590 840 400 10 0 520 ε 1 3 1. 43 1. 5 2.63 0.62 0.50 0.47 0.27 ε 2 0. 31 0.45 0.75 0.2 0.37 0 .1 0.05 0 .13 ε 1 /ε 2 9.7 3...

Ngày tải lên: 13/08/2014, 08:20

... 0 κ xyT = A 14 (A T 11 A 22 −A T 22 A 12 ) +A 24  A T 22 A 11 −A T 11 A 12  −A T 12 h  A 3 A 44 + 1 4  2A 14 A 24 A 12 −A 2 14 A 22 −A 2 24 A 11   where A = A 11 A 22 −A 2 12 . Thus, the ... (7.88)–(7. 91) yield u = T x E 1 +E 2  E 1 α 1 +E 2 α 2 +6(E 1 −E 2 ) E 1 E 2 (α 2 −α 1 ) E 2 1 +14 E 1 E 2 −E 2 2  v = T y E 1 +E 2  E 1 α 1 +...

Ngày tải lên: 13/08/2014, 08:21

... i.e., cos α = dx 1 dx  1 +dy 1 dy  1 +dz 1 dz  1 ds 1 ds  1 (2.23) Here, dx 1 ,dy 1 , and dz 1 are specified with Eq. (2 .17 ), ds 1 can be found from Eq. (2 .18 ), and dx  1 =  1 + ∂u x ∂x  dx  + ∂u x ∂y dy  + ∂u x ∂z dz  (x,y,z) ds  1 = ... form { σ } = [ S ] { ε } (2.46) where { σ } = ⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩ σ x σ y σ z τ xy τ xz τ yz ⎫ ⎪ ⎪ ⎪ ⎪...

Ngày tải lên: 13/08/2014, 08:20

... (4 .15 ), (4.27) and (4. 61) –(4.63) yield ε 1 =a 1 σ 1 +d 1 σ 2 +nσ n 1  1 R 1 (b 11 σ 1 +c 12 σ 2 )+ 1 R 2 2  d 11 σ 2 1 +2e 12 σ 1 σ 2 +e 21 σ 2 2   ε 2 =b 1 σ 2 +d 1 σ 1 +nσ n 1  1 R 1 (b 22 σ 2 +c 12 σ 1 )+ 1 R 2 2  d 22 σ 2 2 +2e 21 σ 2 σ 1 +e 12 σ 2 1   (4.64) γ 12 =c 1 τ 12 +2nσ n 1 b 12 R 1 τ 12 where σ ......

Ngày tải lên: 13/08/2014, 08:20

... C 11 ε 1 +C 12 ε 2 −C 12 ω 2 ,σ 2 = C 12 ε 1 +C 22 ε 2 −C 22 ω 2 , τ 12 = C 44 γ 12 −C 44 ω 12 (4 .15 1) in which C 11 = c 22 c ,C 22 = c 11 c ,C 44 = 1 c 44 ,C 12 =− c 12 c ,c= c 11 c 22 −c 2 12 Repeating ... +ε 2 ) [ (1 +ε y ) 2 − (1 + ε x ) 2 ] 1 +ε  2 = (1 +ε x ) (1 +ε y ) 1 +ε 1 sin φ  = 1 +ε y 1 +ε 1 sin φ, cos φ  = 1 +ε x 1 +ε 1...

Ngày tải lên: 13/08/2014, 08:20

... 4  l 2 x1 l x2 l x3 E 1 + l 2 y1 l y2 l y3 E 2 + l 2 z1 l z2 l z3 E 3 − ν 12 E 2 (l x3 l y2 +l x2 l y3 )l x1 l y1 − ν 13 E 3 (l x2 l z3 +l z2 l x3 )l x1 l z1 − ν 23 E 3 (l y2 l z3 +l y3 l z2 )l y1 l z1  + 1 G 12 (l x1 l y3 +l x3 l y1 )(l x1 l y2 +l x2 l y1 ) + 1 G 13 (l x1 l z3 +l x3 l z1 )(l x1 l z2 +l x2 l z1 ) + 1 G 23 (l y1 l z3 +l y3 l z1 )(l y1 l z2 +l y2 l z1 ) (1, 2,...

Ngày tải lên: 13/08/2014, 08:21

... G 12 h, I (1) 11 = δ 2 2 E 1 p  j =1 [4j (1 +α) − (3 +α)], I (1) 22 = δ 2 2 E 1 p  j =1 [4j (1 +α) − (3α + 1) ],I (1) 12 = 1 2 E 1 ν 12 h 2 , I (1) 44 = 1 2 G 12 h 2 , I (2) 11 = δ 3 3 E 1 p  j =1  12 j 2 (1 ... (5.44) B 11 = B 22 = h 2  E 1 +E 2  ,B 12 = E 1 ν 12 h, B 44 = G 12 h, C 11 =−C 22 = h 2 8  E 2 −E 1  ,C 12 = 0,C 44 =...

Ngày tải lên: 13/08/2014, 08:21