Mixed Boundary Value Problems Episode 1 pps

Tài liệu Two Point Boundary Value Problems part 1 pptx

Tài liệu Two Point Boundary Value Problems part 1 pptx

... the n 2 component values. In other words, (17 .0.2) converts to a prescription y i (x 1 )=y i (x 1 ;V 1 , ,V n 2 ) i =1, ,N (17 .1. 1) Below, the function that implements (17 .1. 1) will be called ... satisfied. At x 1 , the solution is supposed to satisfy B 1j (x 1 ,y 1 ,y 2 , ,y N )=0 j =1, ,n 1 (17 .0.2) while at x 2 , it is supposed to satisfy B 2k (x 2 ,y 1 ,y 2 , ,y N )=0...

Ngày tải lên: 24/12/2013, 12:16

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Báo cáo hóa học: " On nonlocal three-point boundary value problems of Duffing equation with mixed nonlinear forcing terms" potx

Báo cáo hóa học: " On nonlocal three-point boundary value problems of Duffing equation with mixed nonlinear forcing terms" potx

... terms. Boundary Value Problems 2 011 2 011 :47. Alsaedi and Aqlan Boundary Value Problems 2 011 , 2 011 :47 http://www.boundaryvalueproblems.com/content/2 011 /1/ 47 Page 11 of 11 and β n (t )= ˆ h 1 (β n (σ ... β 0 ), Alsaedi and Aqlan Boundary Value Problems 2 011 , 2 011 :47 http://www.boundaryvalueproblems.com/content/2 011 /1/ 47 Page 4 of 11 where η =(N 1 + N...

Ngày tải lên: 20/06/2014, 22:20

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Báo cáo sinh học: " Research Article Approximation of Solution of Some m-Point Boundary Value Problems on Time Scales Rahmat Ali Khan1 and Mohammad Rafique2 1" pot

Báo cáo sinh học: " Research Article Approximation of Solution of Some m-Point Boundary Value Problems on Time Scales Rahmat Ali Khan1 and Mohammad Rafique2 1" pot

... that v n 1  0   0,v n 1  σ 2  1    m 1  i 1 α i v n 1  η i  . 3. 21 Hindawi Publishing Corporation Advances in Difference Equations Volume 2 010 , Article ID 8 416 43, 11 pages doi :10 .11 55/2 010 /8 416 43 Research ... solution w 1 ∈ C 2 rd 0,σ 2 1  T of 3 .12  such that w 0  t  ≤ w 1  t  ≤ β  t  , on  0,σ 2  1   T . 3 .14  Using 3 .11  and the f...

Ngày tải lên: 21/06/2014, 16:20

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Báo cáo hóa học: "SINGULAR SECOND-ORDER MULTIPOINT DYNAMIC BOUNDARY VALUE PROBLEMS WITH MIXED DERIVATIVES" docx

Báo cáo hóa học: "SINGULAR SECOND-ORDER MULTIPOINT DYNAMIC BOUNDARY VALUE PROBLEMS WITH MIXED DERIVATIVES" docx

... Focal boundary value problems for singular difference equa- tions, Computers & Mathematics with Applications 36 (19 98), no. 10 12 , 1 10 . [12 ] J. Henderson and W. Yin, Focal boundary- value problems ... m-point boundary value problems, Journal of Mathematical Analysis and Applications 3 01 (2005), no. 1, 12 4 13 4. [17 ] J. Mawhin, Topological Degree Methods in N...

Ngày tải lên: 22/06/2014, 22:20

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Tài liệu Two Point Boundary Value Problems part 2 pdf

Tài liệu Two Point Boundary Value Problems part 2 pdf

... the n 2 component values. In other words, (17 .0.2) converts to a prescription y i (x 1 )=y i (x 1 ;V 1 , ,V n 2 ) i =1, ,N (17 .1. 1) Below, the function that implements (17 .1. 1) will be called ... nbad,nok; float h1,hmin=0.0,*y; y=vector (1, nvar); kmax=0; h1=(x2-x1) /10 0.0; load(x1,v,y); odeint(y,nvar,x1,x2,EPS,h1,hmin,&nok,&nbad,derivs,rkqs); score(x2,y,f); free_vector(y...

Ngày tải lên: 24/12/2013, 12:16

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Tài liệu Two Point Boundary Value Problems part 3 docx

Tài liệu Two Point Boundary Value Problems part 3 docx

... prescription load1(x1,v1,y) for mapping V (1) into a y that satisfies the boundary conditions at x 1 , y i (x 1 )=y i (x 1 ;V (1) 1 , ,V (1) n 2 ) i =1, ,N (17 .2 .1) Likewise we can define an n 1 -vector ... i,nbad,nok; float h1,hmin=0.0,*f1,*f2,*y; f1=vector (1, nvar); f2=vector (1, nvar); y=vector (1, nvar); kmax=0; h1=(x2-x1) /10 0.0; load1(x1,v,y); Path from x1 to xf with be...

Ngày tải lên: 24/12/2013, 12:16

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Tài liệu Two Point Boundary Value Problems part 4 ppt

Tài liệu Two Point Boundary Value Problems part 4 ppt

... details.) 1 1   1 X X X 1 X X X  1   1    1     1 X X X X X 1 X X X X X  1   1    1     1  X X X X X 1    1    1     1 X X X X X 1 X X X X X  1 V V V V V V V V V V V V V V V V V V V V B B B B B B B B B B B B B B B B B B B B X X X X X  1 Figure ......

Ngày tải lên: 24/12/2013, 12:16

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Tài liệu Two Point Boundary Value Problems part 5 pptx

Tài liệu Two Point Boundary Value Problems part 5 pptx

... =0are S 3,4 =1, n−modd S 3,5 =1, n−meven (17 .4.32) At x =1we have E 1, M +1 = y 2,M − y 3,M − c 2 2(m +1) y 1, M (17 .4.33) E 2,M +1 = y 1, M − γ (17 .4.34) Thus S 1, 4 = − y 3,M − c 2 2(m +1) ,S 1, 5 =1, S 1, 6 =− y 1, M 2(m +1) (17 .4.35) S 2,4 =1, S 2,5 =0,S 2,6 =0 ... runs from 1 to 3fory j at k − 1 andfrom4to6fory j at k. Thus equation (17 .4.23) gives S 1, 1 = 1...

Ngày tải lên: 21/01/2014, 18:20

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