... HSM is said to be: ã High Cutting Speed (v c ) Machining ã High Spindle Speed (n) Machining ã High Feed (v f ) Machining ã High Speed and Feed Machining ã High Productive Machining Metalworking ... pressure and flow. Metalworking World Simpo PDF Merge and Split Unregistered Version - http://www.simpopdf.com Reprint from Metalworking World High speed...
Ngày tải lên: 27/06/2014, 14:20
... HSM is said to be: ã High Cutting Speed (v c ) Machining ã High Spindle Speed (n) Machining ã High Feed (v f ) Machining ã High Speed and Feed Machining ã High Productive Machining Metalworking ... from Metalworking World High speed machining and conventional die and mould machining Metalworking World The question that should be asked is, “Wh...
Ngày tải lên: 27/06/2014, 23:20
High speed machining Part 1 pptx
... G 13 P (u) P 12 , G 12 P 21 , G 21 P 31 , G 31 P 41 , G 41 P (v) P¡ = (P 0 , P 1 , P 2 , P 3 ) G¡ = (G 0 , G 1 , G 2 , G 3 ) K¡ = (K 0 , K 1 , K 2 , K 3 , K 4 , K 5 , K 6 , K 7 , K 8 ) P 11 , G 12 ,P 13 … P 21 , ... K 8 ) P 11 , G 12 ,P 13 … P 21 , G 22 ,P 23 … P 31 , G 32 ,P 33 … G 11 , G 12 ,G 13 … G 21 , G 22 ,G 23 … G 31 , G 32 ,G...
Ngày tải lên: 05/08/2014, 11:20
High speed machining Part 2 ppt
... Sandvik Coromant regarding die and mould machining, the focus will be shifted somewhat from the high speed machining trend to the more basic planning stage of the machining process. Which of course ... spindle 25 Metalworking World the feed rate as it is dependent on the spindle speed for a certain cutting speed. If using the nominal diameter value of the tool, when calculatin...
Ngày tải lên: 05/08/2014, 11:20
windows speed secrets phần 2 pdf
... dialog box, click Windows Vista Basic, and then click OK. Or, if you prefer a Windows 20 00-style interface, click Windows Standard, and then click OK. 23 Vista Speed Secret #10: ... Uncheck Remote Differential Compression 7. Click OK 24 Vista Speed Secret #11: Shut-Off Windows Hibernation Windows hibernation background services use a very large...
Ngày tải lên: 10/08/2014, 13:20
SIMULATION AND THE MONTE CARLO METHOD Episode 2 pdf
... a random sample X1, . . . , XN from the pdf of X and defining the indicators 2, = J{x,2y), i = 1,. . . , N . The estimator d thus defined is called the crude Monte Carlo ... Thus, by the uniqueness property, M + N - Poi(p + v). 32 PRELIMINARIES the distance between the joint pdf f of X and Y and the product of their marginal pdf...
Ngày tải lên: 12/08/2014, 07:22
The gauge block handbook Episode 2 pdf
... only the 30 to 60 mm of the block near the surfaces. For blocks under 100 mm this is the entire block, and there is no problem. For longer blocks, there is a variable amount of the block in the ... If there is a burr on the block or platen, if there is particle of dust between the block and platen, or if the block is seriously warped, the entire face of the...
Ngày tải lên: 12/08/2014, 08:21
Extractive Metallurgy of Copper 4th ed. W. Davenport et. al. (2002) Episode 2 pdf
... pm 22 % ore recycle through two 525 kW crushers 7. 82 30%H20 ball mills 4 6x9 5600 0. 522 2 1. 52 x 2. 26 375 at -600 RF'M 0.15 6 ball mills 12 5 x 7.3 4000 -13.8 32 80% ... E, F, TBRC 20 0 180 shut 320 60 130 170 30 22 0 shut 70 28 5 535 160 160 80 150 115 380 20 0 20 140 20 23 0 24 0 50 29 0 75 370 350 120 140 150...
Ngày tải lên: 13/08/2014, 05:20
High Speed Machining Episode 1 potx
... HSM is said to be: ã High Cutting Speed (v c ) Machining ã High Spindle Speed (n) Machining ã High Feed (v f ) Machining ã High Speed and Feed Machining ã High Productive Machining Metalworking ... World High speed machining and conventional die and mould machining 2 Historical background The term High Speed Machining (HSM) commonly refers to end...
Ngày tải lên: 13/08/2014, 05:20
High Speed Machining Episode 2 pdf
... G 12 ,P 13 … P 21 , G 22 ,P 23 … P 31 , G 32 ,P 33 … G 11 , G 12 ,G 13 … G 21 , G 22 ,G 23 … G 31 , G 32 ,G 33 … K 11 , K 12 ,K 13 … K 21 , K 22 ,K 23 … K 31 , K 32 ,K 33 … P u,v ... G 13 P (u) P 12 , G 12 P 21 , G 21 P 31 , G 31 P 41 , G 41 P (v) P¡ = (P 0 , P 1 , P 2 , P 3 ) G¡ = (G 0 , G 1 , G 2 , G 3 ) K¡ = (K 0 , K 1 , K 2 , K...
Ngày tải lên: 13/08/2014, 05:20
High Speed Machining Episode 3 potx
... Sandvik Coromant regarding die and mould machining, the focus will be shifted somewhat from the high speed machining trend to the more basic planning stage of the machining process. Which of course ... dependent on the spindle speed for a certain cutting speed. If using the nominal diameter value of the tool, when calculating cutting speed, the effective or true cutting speed...
Ngày tải lên: 13/08/2014, 05:20
High Speed Machining Episode 4 potx
... both continous tool paths and commands of feed and speed rates, it is possible to drive the mechanic functions of a machine tool to much higher speeds, accelerations and decelerations. This can ... permits very high table feeds. These cutters are suitable for machining interrupted cast-iron surfaces, roughing cast-iron and small depth of cut in steel. Also in materials where the cuttin...
Ngày tải lên: 13/08/2014, 05:20
Volume 01 - Properties and Selection Irons, Steels, and High-Performance Alloys Episode 2 docx
... High-chromium iron 7. 3-7 .5 0 .26 4- 0 .27 1 9. 4-9 .9 5. 2- 5 .5 . . . . . . . . . High-nickel gray iron 7. 4-7 .6 0 .26 7- 0 .27 5 8. 1-1 9.3 4. 5-1 0.7. 1.0 (d) 3 8-4 0 2 2- 2 3 High-nickel ductile iron 7.4 0 .26 7 ... Martensitic nickel-chromium iron 7. 6-7 .8 0 .27 5- 0 .28 2 8-9 (c) 4. 4-5 (c) 0.80 30 (d) 17 (d) Corrosion-resistant iro...
Ngày tải lên: 13/08/2014, 05:21
Volume 01 - Properties and Selection Irons, Steels, and High-Performance Alloys Episode 11 pdf
... >0.3 8-0 .41 >0 .015 -0 .016 212 4-2 330 30 8-3 38 >0.4 1-0 .43 >0 .016 -0 .017 211 0-2 317 30 6-3 36 >0.4 3-0 .46 >0 .017 -0 .018 209 6-2 303 30 4-3 34 >0.4 6-0 .51 >0 .018 -0 .020 ... the dry-drawn finishes. >0.3 0-0 .33 >0 .012 -0 .013 216 5-2 372 31 4-3 44 >0.3 3-0 .36 >...
Ngày tải lên: 13/08/2014, 05:21
MODELLING OF MECHANICAL SYSTEM VOLUME 2 Episode 2 pdf
... that: λ +2G(cos θ) 2 G = λ +2G(1 −(sin θ) 2 ) G = λ +2G(1 −(γ sin β) 2 ) G = γ 2 (1 2( sin β) 2 ) = γ 2 cos 2 The system [1.1 12] is thus transformed into: γ cos 2 −sin 2 sin 2 γcos 2 R C = −γ ... 2 R C = −γ cos 2 sin 2 [1.113] which has the non-trivial solution: R = sin 2 sin 2 −(γ cos 2 ) 2 sin 2 sin 2 +(γ cos 2 ) 2 ; C = 2 sin 2 cos...
Ngày tải lên: 13/08/2014, 05:22