Modern Analytical Cheymistry - Chapter 1 pps

... Voltammetry 514 11 D.5 Voltammetric Techniques 515 11 D.6 Quantitative Applications 520 11 D.7 Characterization Applications 527 11 D.8 Evaluation 5 31 11E Key Terms 532 11 F Summary 532 11 G Suggested ... Applications 506 11 C.5 Evaluation 507 11 D Voltammetric Methods of Analysis 508 11 D .1 Voltammetric Measurements 509 11 D.2 Current in Voltammetry 510 11 D.3 Shape of Voltamm...

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... analyte Macro Micro Meso Ultramicro Major 10 10 % 10 –9 % 10 –8 % 10 –7 % 10 –6 % 10 –5 % 10 –4 % 10 –3 % 10 –2 % 0 .1% 1% 10 % 10 0% –log(% analyte as %w/w) –log(Weight of sample) 1 0 .1 0. 01 0 .1 0. 01 0 .1 0. 01 100 10 1 100 10 0 10 10 1 1 14 00-CH03 9/8/99 3: 51 PM Page 43 40 Modern ... Chem. 19 93, 65, 781A–787A. 9. Valcárcel, M.; Ríos, A. Ana...

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... 626 10 3 00 10 589 10 337 10 34 8 9 19 J s) ( m/s) m J Eh hc hc = = = ν λ ν ν λ == × ×=× − − 11 589 10 17 0 10 9 41 m 1 m 10 0 cm cm. ν λ == × × =× − − c 300 10 589 10 509 10 8 9 14 1 . . ... Equation 10 .11 can be written in terms of moles, n, by using the relationship 10 .15 where V is the total solution volume. Substituting equation 10 .15 into 10...

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... 0 .14 92 0 .14 69 0 .14 46 0 .14 23 0 .14 01 0 .13 79 1. 1 0 .13 57 0 .13 35 0 .13 14 0 .12 92 0 .12 71 0 .12 51 0 .12 30 0 .12 10 0 .11 90 0 .11 70 1. 2 0 .11 51 0 .11 31 0 .11 12 0 .10 93 0 .10 75 0 .10 56 0 .10 38 0 .10 20 0 .10 03 0.0985 1. 3 ... 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 1 Sequence 20 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 UCL UWL CL...

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... outlined earlier. 10 1 99 10 2= . 22 91 015 2 16 302 0 213 61 0 214 . × == 14 Modern Analytical Chemistry 14 00-CH02 9/8/99 3:48 PM Page 14 20 Modern Analytical Chemistry 0 .12 0 .10 0.08 0.06 0.04 0.02 0.00 [H + ] ... figures. a. 4.5 91 + 0.2309 + 67 .1 = b. 313 – 273 .15 = c. 712 × 8.6 = d. 1. 43/0.026 = e. (8. 314 × 298)/96485 = f. log(6.53 × 10 –5 ) = g. 10...

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... 0.05. Analyst A Analyst B 86.82 81. 01 87.04 86 .15 86.93 81. 73 87. 01 83 .19 86.20 80.27 87.00 83.94 t XX snn exp (/ / ) .(//) .= − + = − + = AB pool A B 11 3 11 7 3 0 81 0 0459 1 7 1 5 13 4 s nsns nn pool A A B B AB = −+− +− = −+− +− = ()() ()(. ... DC, 19 88. 14 . Long, G. L.; Winefordner, J. D. Anal. Chem. 19 83, 55, 712 A–724A. 4 M REFERENCES 14 00-CH04 9/8/99 3:55 PM...

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... W x b S samp 1. 6667 0.2500 1 62.4746 0.8000 5.0000 0.5000 2 82.7 915 1. 0000 8.3333 0.7500 3 10 3 .10 85 1. 2000 9.5507 0.8 413 11 .6667 1. 0000 analyte-free c 0 .10 00 18 .16 00 1. 4870 19 .9333 1. 6200 Calibration ... 10 mL) mL 5.00 mL + 5.00 mL) –3 14 00-CH05 9/8/99 3:59 PM Page 11 3 13 0 Modern Analytical Chemistry 5 E KEY TERMS aliquot (p. 11 1) external...

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... PO w aHPO K K K K K K 55 55 24 34 10 0 10 590 10 16 9 10 10 0 10 711 10 14 1 10 14 6 9 14 3 12 == × × =× == × × =× + []. . –– HO 3 14 7 1 00 10 1 00 10 + =×=× *The use of a p-function to express a concentration is covered in Chapter ... – – – HO 3 813 8 14 8 10 6 32 10 4 5 10 0 10 6 32 10 1 00 10 0 10 6 32 10 18 6 10 + = ×× +× × +× =× [ ] ( ....

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... mL (0.0438) (10 .00 mL mL 1 100 0 10 0 0 0 996= + = D = ××× × ×+××× = −− −− (. )(. )(. )(. ) (. )(. ) (. )(. )(. ) . 25 10 70 10 50 10 10 10 10 10 010 2 510 5 010 10 10 0 0438 16 4 5 2 4 2 42 2 16 52 42 Extraction ... 9.0 5.7 1. 0 4.8 9.5 5.5 1. 5 5.2 10 .0 6.5 2.0 5.2 10 .5 6.0 2.5 5.6 11 .0 5.8 3.0 5.4 11 .5 6.0 3.5 5.4 12 .0 5.6 4.0 4.4 12 .5 5.6 4.5 4.8 13 .0 5.4 5....

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... (g) (g) 0–2 1. 590 43. 21 52 .10 49.49 2–4 1. 745 40.62 48.83 46.00 4–6 1. 619 41. 23 52.86 47.84 6–8 1. 611 42 .10 50.59 47 .13 8 10 1. 658 43.62 51. 88 47.53 10 12 1. 628 43.24 49.45 45. 31 12 14 1. 633 43.08 ... McCleary, D. L. J. Chem. Educ. 19 93, 70, 17 2 17 3. 18 . Yao, S. F.; He, F. J.; Nie, L. H. Anal. Chim. Acta 19 92, 268, 311 – 314 . \\ 8J REFERENCES 14 00-CH08 9/9...

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