MATLAB Demystified phần 2 pptx
MATLAB Demystified phần 2 pptx
... =
64 2 3 61 60 6 7 57
9 55 54 12 13 51 50 16
17 47 46 20 21 43 42 24
40 26 27 37 36 30 31 33
32 34 35 29 28 38 39 25
41 23 22 44 45 19 18 48
49 15 14 52 53 11 10 56
8 58 59 5 4 62 63 1
This ... works as follows:
AB
aa
aa
bb
bb
.*
(
=
⎛
⎝
⎜
⎞
⎠
⎟
⎛
⎝
⎜
⎞
⎠
⎟
=
11 12
21 22
11 12
21 22
aab ab
ab ab
11 11 12 12
21 21 22 22
)( ) ( )( )
()()()()
⎛
⎝
⎜
⎞⎞
⎠
⎟
We...
MATLAB Demystified phần 4 pptx
... be:
sigma =
3.3307
>> mu
mu =
24 .6538
23 23 .5 24 24 .5 25 25 .5 26 26 .5 27
0
0 .2
0.4
0.6
0.8
1
x
exp(−(x 25 )
2
)
Figure 4-8 A bell curve with a mean of 25 years
CHAPTER 3 Plotting and Graphics ... elements repeated by
frequency:
raw =
Columns 1 through 18
17 17 18 21 21 21 24 26 28 28
28 28 31 31 33 34 34 37
Columns 19 through 26
37 37 39 40 40 43 43...
Accounting Demystified phần 2 ppt
... 31,
20 02, the Balance Sheet would be as on December 31, 20 02.
You can state the date in a variety of formats. All of the follow-
ing are acceptable:
As on December 31, 20 02
December 31, 20 02
On ... income 85,500
Less: Dividends 35,500
Ending balance, December 31, 20 02 $150,000
1 028 8$ $CH2 08 -29 -03 08:31:03 PS
20
Accounting Demystified
page (with each page being a differe...
Accounting Demystified phần 4 pptx
... 1,000 35 35,000 1,000
Jan. 5 1 ,25 0 40 50,000 2, 250
Jan. 7 500 1,750
Jan. 8 750 1,000
Jan. 9 2, 000 42 84,000 3,000
Jan. 10 1,000 2, 000
Total 4 ,25 0 169,000 2, 250 2, 000
goods sold will be an expense ... ם 1 ,25 0):
Total inventory value $85,000
Total units 2, 250
Weighted average $ 37.78
1 028 8$ $CH8 08 -29 -03 08:31:18 PS
60
Accounting Demystified
1/07/ 02 Cost of goods sold...
Accounting Demystified phần 10 pptx
... 34
general ledger, 17–19, 22 23
impact on specific accounts,
16
journal entries, 14–15
posting, 17–19, 22 23
in trial balance, 19 20
in wrong column, 22 23
1 028 8$ INDX 08 -29 -03 08:30:56 PS
159
Glossary
Last-in, ... method,
62 63
credits
cash account, 33–34
general ledger, 17–19, 22 23
impact on specific accounts,
16
journal entries, 14–15
posting, 17–19, 22 23
in trial balance,...
Engineering Matlab Problem Solving phần 2 pptx
... base 2 value 00110101, denoted by
53
10
= 00110101
2
In base 10, this means
53
10
=5×10
1
+3× 10
0
Similarly,
00110101
2
=0× 2
7
+0× 2
6
+1× 2
5
+1× 2
4
+0× 2
3
+1× 2
2
+0× 2
1
+1× 2
0
= 32
10
+16
10
+4
10
+1
10
Thus, ... cosines: a
2
= b
2
+ c
2
− 2bc cos α
Law of tangents:
a −b
a + b
=
tan
1
2
(α −β)
tan
1
2
(α + β)
Included angles: α + β + γ = π radians = 1...
MATLAB Demystified phần 1 pps
... 1.10 52 1 .22 14 1.3499 1.4918 1.6487
1. 822 1 2. 0138 2. 225 5 2. 4596
Column 11
2. 7183
Or we could have y = x
2
:
>> y = x ^2
y =
Columns 1 through 10
0 0.0100 0.0400 0.0900 0.1600 0 .25 00
0.3600 ... Function 25 7
Quiz 25 8
CHAPTER 11 Working with Special Functions 25 9
Gamma Functions 25 9
Bessel Functions 26 6
The Beta Function 27 4
Special Integrals 27 6
Legen...
MATLAB Demystified phần 3 ppt
... linspace(0 ,2* pi);
>> plot(x,cos(x)),axis([0 2* pi –1 1])
Figure 3 -23 We overwrite the previous plot by typing plot[x, sin(x)]
Figure 3 -22 A plot of cos(x) generated using the linspace command
62
... [0:0.01:5];
>> y = exp(–1 .2* x).*sin (20 *x);
>> subplot(1 ,2, 1)
By passing (1, 2, 1) to subplot, we have told MATLAB that we are going to create
an array with 2...
MATLAB Demystified phần 5 pps
... write:
>> eq = 'x ^2 + x – 2^ (1 /2) ';
Next we call solve to fi nd the roots:
>> s = solve(eq)
s =
–1 /2+ 1 /2* (1+4 *2^ (1 /2) )^(1 /2)
–1 /2 1 /2* (1+4 *2^ (1 /2) )^(1 /2)
To determine the numerical ... solve(eq)
s =
2
–1
–1
−6 −4 2 0 2 4 6
−5
0
5
10
15
20
25
30
35
40
45
x
x
2
+ x − 2
1 /2
Figure 5-5 A plot of the quadratic equation solved in Examp...
MATLAB Demystified phần 6 pps
... look at the data points returned by the ode23 solver:
y =
2. 0000
2. 1593
2. 5110
2. 8080
2. 9848
2. 9169
2. 6344
2. 2 123
1.7999
1.45 12
1.18 92
1.0 323
1.0115
1.1536
1.4337
1.7689
1.9996
With ... the solution to
dy
dt
ty= 2
2
with initial conditions given by
y(0) = 0 .2, . . . , 2. 0 in increments of 0 .2
−4 −3 2 −1 0 1 2 3 4
0
0.5
1
1.5
2
2.5
t
1/(t
2...