cryptography for developers 2006 phần 8 ppsx

cryptography for developers 2006 phần 8 ppsx

cryptography for developers 2006 phần 8 ppsx

... time. 185 zeromem(tmp, sizeof(tmp)); 186 187 /* compute product four bits of each word at a time */ 188 /* for each nibble */ 189 for (i = (BPD/4)-1; i >= 0; i ) { 190 /* for each word */ 191 for ... gcm->PC[x-1][y][z-1]; 080 } 081 gcm->PC[x][y][0] = gcm_shift_table[t<<1]; 082 gcm->PC[x][y][1] ^= gcm_shift_table[(t<<1)+1]; 083 } 084 } This code block...

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cryptography for developers 2006 phần 1 potx

cryptography for developers 2006 phần 1 potx

... HJIRTCV764 002 PO 987 3D5FG 003 82 9KM8NJH2 004 GPPQQW722M 005 CVPLQ6WQ23 006 VBP965T5T5 007 HJJJ863WD3E 0 08 2 987 GVTWMK 009 629MP5SDJT 010 IMWQ295T6T PUBLISHED BY Syngress Publishing, Inc. 80 0 Hingham ... . . . . . . . . . 187 Message Lengths . . . . . . . . . . . . . . . . . . . . . . . . . . . 188 Decryption . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 188 Perform...

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cryptography for developers 2006 phần 2 pdf

cryptography for developers 2006 phần 2 pdf

... significant bits as {{0x2A}, {0x86, 0x 48} , {0x86, 0xF7, 0x0D}, {0x02}, {0x05}}.Therefore, the full encoding for MD5 is 0x06 08 2A 86 48 86 F7 0D 02 05. Decoding is rather straightforward except the first ... 02 127 0x02 01 7F 1 28 0x02 02 00 80 –1 0x02 01 FF –1 28 0x02 01 80 –327 68 0x02 02 80 00 123456 789 0 0x02 04 49 96 02 D2 Note in particular the difference between 1 28 and...

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cryptography for developers 2006 phần 3 potx

cryptography for developers 2006 phần 3 potx

... (expected 524 287 ) Lag[ 2] = 525 284 (expected 524 287 ) Lag[ 3] = 5246 38 (expected 524 286 ) Lag[ 4] = 525564 (expected 524 286 ) Lag[ 5] = 524 480 (expected 524 285 ) Lag[ 6] = 523917 (expected 524 285 ) Lag[ ... test. Lag[ 1] = 2626 38 (expected 524 287 ) Lag[ 2] = 393 784 (expected 524 287 ) Lag[ 3] = 45 984 0 (expected 524 286 ) Lag[ 4] = 492175 (expected 524 286 ) Lag[ 5] = 5 082 32...

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cryptography for developers 2006 phần 4 docx

cryptography for developers 2006 phần 4 docx

... (seedlen) for 440 440 440 88 8 88 8 Hash_DRBG max_personalization_ < 2 35 string_length max_additional_input_length < 2 35 max_number_of_bits_per_request < 2 19 reseed_interval < 2 18 Design The ... 3.1). Table 3.1 Parameters for Hash_DRBG SHA-1 SHA- SHA- SHA- SHA- 224 256 384 512 Supported Security Strengths 80 112 1 28 192 256 highest_supported_security_ 80 112 1 28...

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cryptography for developers 2006 phần 5 ppt

cryptography for developers 2006 phần 5 ppt

... 0xec76769aUL, 021 0x8fcaca45UL, 0x1f8 282 9dUL, 0x89c9c940UL, 0xfa7d7d87UL, <snip> 077 0x038c8c8fUL, 0x59a1a1f8UL, 0x0 989 8 980 UL, 0x1a0d0d17UL, 0 78 0x65bfbfdaUL, 0xd7e6e631UL, 0x844242c6UL, 0xd0 686 8b8UL, 079 ... 0xcecececeUL, 0x55555555UL, 0x 282 8 282 8UL, 0xdfdfdfdfUL, 144 0x8c8c8c8cUL, 0xa1a1a1a1UL, 0x8 989 8 989 UL, 0x0d0d0d0dUL, 145 0xbfbfbfbfUL, 0xe6e6e6e6UL, 0x42424242UL,...

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cryptography for developers 2006 phần 6 potx

cryptography for developers 2006 phần 6 potx

... CONST64(0x 682 e6ff3d6b2b8a3), 080 CONST64(0x748f82ee5defb2fc), CONST64(0x78a5636f43172f60), 081 CONST64(0x84c8 781 4a1f0ab72), CONST64(0x8cc702 081 a6439ec), 082 CONST64(0x90befffa23631e 28) , CONST64(0xa4506cebde82bde9), 083 ... 60; x++) { 081 e = (ROL(a, 5) + F2(b,c,d) + e + W[x] + 0x8f1bbcdc); 082 b = ROL(b, 30); 083 t=e;e=d;d=c;c=b;b=a;a=t; 084 } 085 086 /* 20 rounds */ 087...

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cryptography for developers 2006 phần 7 doc

cryptography for developers 2006 phần 7 doc

... &stream->channels[0].skey))!= CRYPT_OK) { 0 78 return err; 079 } 080 081 if ((err = ctr_start(find_cipher(“aes”), tmp, 082 stream->channels[1].enckey, ENCKEYLEN, 083 0, CTR_COUNTER_BIG_ENDIAN, 084 &stream->channels[1].skey))!= ... required for the security of NMAC, the algorithm from which HMAC was derived (http://eprint.iacr.org /2006/ 043.pdf for more details)....

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cryptography for developers 2006 phần 9 potx

cryptography for developers 2006 phần 9 potx

... #endif 277 2 78 for (; y < ptlen; y++) { 279 /* increment the ctr? */ 280 if (CTRlen == 16) { 281 for (z = 15; z > 15-L; z ) { 282 ctr[z] = (ctr[z] + 1) & 255; 283 if (ctr[z]) break; 284 } 285 ... machine state (e.g., if you were using MMX). 082 /* setup dest */ 083 dst->used = pa; 084 fp_clamp (dst); 085 if (dst != B) { 086 fp_copy(dst, B); 087 } 088 } This fun...

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cryptography for developers 2006 phần 10 doc

cryptography for developers 2006 phần 10 doc

... ECC192 { 24, “ECC-192”, “FFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFEFFFFFFFFFFFFFFFF”, “64210519E59C80E70FA7E9AB72243049FEB8DEECC146B9B1”, “FFFFFFFFFFFFFFFFFFFFFFFF99DEF836146BC9B1B4D2 283 1”, “ 188 DA80EB03090F67CBF20EB43A 188 00F4FF0AFD82FF1012”, “7192B95FFC8DA 786 31011ED6B24CDD573F977A11E79 481 1”, }, #endif The ... 190–192, 201 decryption, 188 description, 186 – 187 implementation, 189 –190 initi...

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