cryptography for developers 2006 phần 3 potx
... (in[1] < 128) { 030 /* short form */ 031 len = in[1]; 032 } else { 033 /* get length of length */ 034 x = in[1] & 0x7F; 035 036 /* can we actually read this many bytes? */ 037 if (inlen <2+x){return ... x; 029 break; 030 case ASN1_DER_INTEGER: 031 x = *outlen; 032 err = der_integer_encode(*((long *)list[i].data), 033 out, &x); 034 if (err < 0) return err; 035 o...
Ngày tải lên: 12/08/2014, 20:22
cryptography for developers 2006 phần 1 potx
... own content, into a single volume for their own internal use. Contact us at sales@syngress.com for more information. Visit us at 404_CRYPTO_FM.qxd 10 /30 /06 2 :33 PM Page i xvi Contents Replay Protection ... 781-681 -35 85. 404_CRYPTO_FM.qxd 10 /30 /06 2 :33 PM Page iv 404_CRYPTO_01.qxd 10/27/06 4:40 PM Page 20 Tom St Denis, Elliptic Semiconductor Inc. and Author of the LibTom Project Si...
Ngày tải lên: 12/08/2014, 20:22
cryptography for developers 2006 phần 6 potx
... CONST64(0x 533 80d 139 d95b3df), 070 CONST64(0x650a 735 48baf63de), CONST64(0x766a0abb3c77b2a8), 071 CONST64(0x81c2c92e47edaee6), CONST64(0x92722c85148 235 3b), 072 CONST64(0xa2bfe8a14cf1 036 4), CONST64(0xa81a664bbc4 230 01), 0 73 ... CONST64(0x1e376c085141ab 53) , 077 CONST64(0x2748774cdf8eeb99), CONST64(0x34b0bcb5e19b48a8), 078 CONST64(0x391c0cb3c5c95a 63) , CONST64(0x4ed8aa4ae3418acb), 0...
Ngày tải lên: 12/08/2014, 20:22
cryptography for developers 2006 phần 9 potx
... = b; 30 0 } 30 1 30 2 if (x == 16) { 30 3 if ((err = 30 4 cipher_descriptor[cipher].ecb_encrypt( 30 5 PAD, PAD, skey)) != CRYPT_OK) { 30 6 goto error; 30 7 } 30 8 x = 0; 30 9 } 31 0 PAD[x++] ^= b; 31 1 } This ... Chapter 8 36 3 404_CRYPTO_08.qxd 10 /30 /06 11: 53 AM Page 36 3 229 ctr, CTRPAD, skey)) != CRYPT_OK) { 230 goto error; 231 } We must encrypt the CTR counter before u...
Ngày tải lên: 12/08/2014, 20:22
... user enters potentially dangerous input. 76 Part II: Building Secure Applications 08_597760 ch 03. qxp 1/11/06 9: 53 PM Page 76 recover a forgotten account password. For security’s sake, the user must first answer a question that ... Inherits=”MasterPage” %> <!DOCTYPE html PUBLIC “-//W3C//DTD XHTML 1.1//EN” “http://www.w3.org/TR/xhtml11/DTD/xhtml11.dtd”> <html xmlns=”http://w...
Ngày tải lên: 05/08/2014, 10:20
cryptography for developers 2006 phần 2 pdf
... 10/27/06 3: 40 PM Page 54 0x16. For example, the encoding of July 4, 20 03 at 11 :33 and 28 seconds would be “ 030 7041 133 28Z” and be encoded as 0x17 0D 30 33 30 37 30 34 31 31 33 33 32 38 5A. Implementation Now ... 74 75 Credential 30 0A PasswdHash 04 08 01 02 03 04 05 06 07 08 LastOn 17 0D 30 36 30 34 31 36 31 38 30 30 30 30 30 5A Valid 01 01 FF In this exam...
Ngày tải lên: 12/08/2014, 20:22
cryptography for developers 2006 phần 4 docx
... a 0,0 0,1 0,2 0 ,3 1,0 1,1 1,2 1 ,3 2,0 2,1 2,2 2 ,3 3,0 3, 1 3, 2 3, 3 b b b b b b b b b b b b b b b b 0,0 0,1 0,2 0 ,3 1,0 1,1 1,2 1 ,3 2,0 2,1 2,2 2 ,3 3,0 3, 1 3, 2 3, 3 ROL 1 ROL 2 ROL 3 a a a a a a a ... 0,2 0 ,3 1,0 1,1 1,2 1 ,3 2,0 2,1 2,2 2 ,3 3,0 3, 1 3, 2 3, 3 b b b b b b b b b b b b b b b b 0,0 0,1 0,2 0 ,3 1,0 1,1 1,2 1 ,3 2,0 2,1 2,2 2 ,3 3,0 3, 1 3, 2...
Ngày tải lên: 12/08/2014, 20:22
cryptography for developers 2006 phần 5 ppt
... = 130 Te0(byte(s0, 3) ) ^ 131 Te1(byte(s1, 2)) ^ 132 Te2(byte(s2, 1)) ^ 133 Te3(byte(s3, 0)) ^ 134 rk[4]; 135 t1 = 136 Te0(byte(s1, 3) ) ^ 137 Te1(byte(s2, 2)) ^ 138 Te2(byte(s3, 1)) ^ 139 Te3(byte(s0, ... Encryption Standard 404_CRYPTO_04.qxd 10 /30 /06 9:42 AM Page 164 eor r3, r3, r0 ldr ip, [r8, r2, asl #2] eor r3, r3, r1 ldr r2, [lr, #32 ] eor r3, r3, ip eor r3, r3, r2 We can...
Ngày tải lên: 12/08/2014, 20:22
cryptography for developers 2006 phần 7 doc
... Algorithms • Chapter 6 285 404_CRYPTO_06.qxd 10 /30 /06 10:20 AM Page 285 036 037 /* XOR inner key with 0x36 */ 038 for (i = 0; i < 64; i++) { 039 K[i] ^= 0x36; 040 } The first loop creates the outer ... 0x52, 0x72, 0xd0, 0x0e, 135 0x95, 0x70, 0x56, 0x37, 0xce, 0x8a, 0x3b, 0x55, 136 0xed, 0x40, 0x21, 0x12} }, 137 { 138 {0xaa, 0xaa, 0xaa, 0xaa, 0xaa, 0xaa, 0xaa, 0xaa, 139 0xaa,...
Ngày tải lên: 12/08/2014, 20:22
cryptography for developers 2006 phần 8 ppsx
... { 030 unsigned char PAD[16], ctr[16], CTRPAD[16], b; 031 symmetric_key *skey; 032 int err; 033 unsigned long len, L, x, y, z, CTRlen; 034 035 if (uskey == NULL) { 036 LTC_ARGCHK(key != NULL); 037 ... = pTmp[i]; 232 } 233 234 } 235 236 #endif Both implementations of gcm_gf_mult() accomplish the same goal and are numerically equivalent.The latter implementation is much faster on...
Ngày tải lên: 12/08/2014, 20:22