cryptography for developers 2006 phần 1 potx

cryptography for developers 2006 phần 1 potx

cryptography for developers 2006 phần 1 potx

... Chapter 1 17 404_CRYPTO_ 01. qxd 10 /27/06 4:40 PM Page 17 as 2 nd pre-image resistance (Figure 1. 4) is the inability to find two messages M1 (given) and M2 (chosen at random) such that hash (M1) = ... executed in a computer system, but they may not be reproduced for publication. 1 2 3 4 5 6 7 8 9 0 ISBN -10 : 1- 59749 -10 4-7 ISBN -13 : 978 -1- 59749 -10 4-4 Publisher: Andrew Wil...

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cryptography for developers 2006 phần 3 potx

cryptography for developers 2006 phần 3 potx

... 3.2 Sample Output of the timer_bit Routine 0 010 0 010 1 011 1 010 010 100 011 011 110 0 10 0 010 111 011 111 1 If we continued, we would likely see that there is some form of bias, but at the very least, the entropy ... 10 /30/06 12 :48 PM Page 96 11 2 sizeof(unsigned long)); 11 3 if (list->data == NULL) { goto MEM_ERR; } 11 4 11 5 err = der_oid_decode(in, inlen, 11 6 list->d...

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cryptography for developers 2006 phần 6 potx

cryptography for developers 2006 phần 6 potx

... == 0) { 11 1 sha1_compress(md, buf); 11 2 buf += 64; 11 3 md->msglen += 64; 11 4 len -= 64; 11 5 } 11 6 11 7 x = (64 - md->buflen) < len ? 64 - md->buflen : len; 11 8 len -= x; 11 9 12 0 /* copy ... proceed. 11 1 /* copy x bytes from buf to the buffer */ 11 2 for (y = 0; y < x; y++) { 11 3 md->buf[md->buflen++] = *buf++; 11 4 } 11 5 11 6 if (md->buflen ==...

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cryptography for developers 2006 phần 9 potx

cryptography for developers 2006 phần 9 potx

... (1& lt;<6) : 0) | 12 3 (((*taglen - 2)>> ;1) <<3) | 12 4 (L -1) ; 12 5 12 6 /* nonce */ 12 7 for (y = 0; y < (16 - (L + 1) ); y++) { 12 8 PAD[x++] = nonce[y]; 12 9 } 13 0 13 1 /* store len */ 13 2 len = ... Authenticate Modes 404_CRYPTO_07.qxd 10 /30/06 11 : 51 AM Page 342 404_CRYPTO_07.qxd 10 /30/06 11 : 51 AM Page 348 19 1 PAD, PAD, skey)) != CRYPT_OK) {...

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cryptography for developers 2006 phần 2 pdf

cryptography for developers 2006 phần 2 pdf

... -1; 010 } 011 012 /* store header and length */ 013 der_put_header_length(&out, ASN1_DER_OCTETSTRING, 014 noctets, outlen); 015 016 /* store bytes */ 017 memcpy(out, octets, noctets); 018 019 ... return -1; 009 } 010 011 /* store header and length */ 012 der_put_header_length(&out, ASN1_DER_BOOLEAN, 1) ; 013 014 /* store payload */ 015 *out = (bool == 0) ? 0x00...

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cryptography for developers 2006 phần 4 docx

cryptography for developers 2006 phần 4 docx

... 1 0 0 0 1 1 x 0 1 1 1 1 0 0 0 1 x 0 1 1 1 1 1 0 0 0 x 0 0 1 1 1 1 1 0 0 x 1 0 0 1 1 1 1 1 0 x 1 0 0 0 1 1 1 1 1 x 0 0 1 2 3 4 5 6 7 + 404_CRYPTO_04.qxd 10 /30/06 9:42 AM Page 14 7 ■ USB, PS/2, ... 1, 3 2,0 2 ,1 2,2 2,3 3,0 3 ,1 3,2 3,3 b b b b b b b b b b b b b b b b 0,0 0 ,1 0,2 0,3 1, 0 1, 1 1, 2 1, 3 2,0 2 ,1 2,2 2,3 3,0 3 ,1 3,2 3,3 SubB...

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cryptography for developers 2006 phần 5 ppt

cryptography for developers 2006 phần 5 ppt

... chooses. 11 0 unsigned long s0, s1, s2, s3, t0, t1, t2, t3, *rk; 11 1 int r; 11 2 11 3 rk = skey; 11 4 11 5 /* 11 6 * map byte array block to cipher state 11 7 * and add initial round key: 11 8 */ 11 9 LOAD32H(s0, ... 0x0b, 0x0c, 0x0d, 0x0e, 0x0f, 2 01 0x10, 0x 11, 0x12, 0x13, 0x14, 0x15, 0x16, 0x17, 202 0x18, 0x19, 0x1a, 0x1b, 0x1c, 0x1d, 0x1e, 0x1f }, 203 { 0x00, 0x 11, 0x22, 0x3...

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cryptography for developers 2006 phần 7 doc

cryptography for developers 2006 phần 7 doc

... < CTRLEN; x++) { 11 7 IV[x] = stream->channels[0].PktCTR[x]; 11 8 } 11 9 for (; x < 16 ; x++) { 12 0 IV[x] = 0; 12 1 } 12 2 12 3 /* set IV */ 12 4 if ((err = ctr_setiv(IV, 16 , 12 5 &stream->channels[0].skey)) ... unsigned long keylen; 10 9 unsigned char data [12 8]; 11 0 unsigned long datalen; 11 1 unsigned char tag[20]; 11 2 } tests[] = { 11 3 { 11 4 {0x0c...

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cryptography for developers 2006 phần 8 ppsx

cryptography for developers 2006 phần 8 ppsx

... 289 404_CRYPTO_06.qxd 10 /30/06 10 :20 AM Page 289 17 7 * 7, 11 , 13 , 14 , 15 */ 17 8 B[M(7)][i] = B[M(3)][i] ^ B[M(4)][i]; 17 9 B[M (11 )][i] = B[M(3)][i] ^ B[M(8)][i]; 18 0 B[M (13 )][i] = B[M (1) ][i] ^ B[M (12 )][i]; 18 1 B[M (14 )][i] ... B[M (1) ][0] >> 1; 15 8 B[M(4)][0] = B[M (1) ][0] >> 2; 15 9 B[M(8)][0] = B[M (1) ][0] >> 3; 16 0 for (i = 1; i &l...

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cryptography for developers 2006 phần 10 doc

cryptography for developers 2006 phần 10 doc

... key schedule, 18 0 18 1 key schedule, 16 9 17 4 macros, 16 8 16 9 optimization, 16 5 performance, 17 4 17 5 performance, ARM, 17 6 17 7 performance, small variant, 17 8 18 0 performance, X86, 17 4 17 6 precomputed ... math, 14 4 14 6 inverse cipher, 15 5 key schedule, 15 5 15 6, 16 5 last round, 15 5 lossy channels, 19 5 19 6 MixColumns function, 15 1 15 4 myths, 19 6 Osvik at...

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