Engineering Matlab Problem Solving phần 2 pptx

... base 2 value 00110101, denoted by 53 10 = 00110101 2 In base 10, this means 53 10 =5×10 1 +3× 10 0 Similarly, 00110101 2 =0× 2 7 +0× 2 6 +1× 2 5 +1× 2 4 +0× 2 3 +1× 2 2 +0× 2 1 +1× 2 0 = 32 10 +16 10 +4 10 +1 10 Thus, ... cosines: a 2 = b 2 + c 2 − 2bc cos α Law of tangents: a −b a + b = tan 1 2 (α −β) tan 1 2 (α + β) Included angles: α + β + γ = π radians = 1...

Ngày tải lên: 12/08/2014, 16:21

... 0 0.5 1 1.5 2 2.5 3 3.5 4 4.5 5 2 0 2 4 6 8 10 12 Multiple Axis Plot x 0 0.5 1 1.5 2 2.5 3 3.5 4 4.5 5 −10 0 10 20 30 40 50 60 Figure 5.3: Plot with two polynomial ... figure(n) 97 >> x=(0:0.1:1)*pi x= Columns 1 through 7 0 0.31 42 0. 628 3 0.9 425 1 .25 66 1.5708 1.8850 Columns 8 through 11 2. 1991 2. 5133 2. 827 4 3.1416 As in addressing, (0:5) creates a vector that st...

Ngày tải lên: 12/08/2014, 16:21

... AppliedProblemSolving:RobotMotion 20 2 10 Curve Fitting and Interpolation 20 7 10.1MinimumMean-SquareErrorCurveFitting 20 7 10 .2 Applied Problem Solving: Hydraulic Engineering . 21 3 10.3Interpolation 21 5 10.4AppliedProblemSolving:HumanHearing ... Terminology . . . 12 2 Matlab Technical Computing Environment 14 2. 1 Workspace,Windows,andHelp 14 2. 2 ScalarMathematics 15 2....

Ngày tải lên: 12/08/2014, 16:21

... quotient by the conjugate of z 2 : z 1 z 2 = x 1 + jy 1 x 2 + jy 2 = (x 1 + jy 1 )(x 2 − jy 2 ) (x 2 + jy 2 )(x 2 − jy 2 ) = (x 1 + jy 1 )(x 2 − jy 2 ) x 2 2 + y 2 2 68 We can summarize the representations ... identity j 2 = −1, and writing the result in rectangular form: z 1 z 2 =(x 1 + jy 1 )(x 2 + jy 2 ) = x 1 x 2 + jx 1 y 2 + jx 2 y 1 + j 2 y 1...

Ngày tải lên: 12/08/2014, 16:21

... poly(r) a= 1.0000 -2. 0000 -3.0000 10.0000 Example 6.1 Finding the depth of a well using roots of a polynomial 118 X= -2- 10 12 -2- 10 12 -2- 10 12 -2- 10 12 Y= -1 -1 -1 -1 -1 00000 11111 22 222 After the underlying ... with Matlab: >> d = depth (2) d= 28 .6 425 >> t1 = sqrt (2* d/g) t1 = 2. 4165 >> t2 = d/c t2 = 0.0835 >>t=t1+t2 t= 2. 5000 Thus, the dept...

Ngày tải lên: 12/08/2014, 16:21

... two such simulations: 23 4 521 3314 522 5563635 150 The displayed output of the script is: 0 25 .0000 10.0000 18.9811 20 .0000 15.3773 30.0000 13 .21 96 40.0000 11. 927 7 50.0000 11.15 42 60.0000 10.6910 70.0000 ... the mean ( 2 <z< ;2) , and 99% will fall within three standard deviations of the mean (−3 <z<3). The Matlab functions for generating Gaussian random numbers are...

Ngày tải lên: 12/08/2014, 16:21

... a 11 (a 22 a 33 − a 23 a 32 ) − a 12 (a 21 a 33 − a 23 a 31 )+a 13 (a 21 a 32 − a 22 a 31 ) = a 11 a 22 a 33 − a 11 a 23 a 32 − a 12 a 21 a 33 + a 12 a 23 a 31 + a 13 a 21 a 32 − a 13 a 22 a 31 Thus, ... Thus, A. ^2 =       a 2 11 a 2 12 a 2 1n a 2 21 a 2 22 a 2 2n . . . . . . . . . a 2 m1 a 2 m2 a 2 mn       To square th...

Ngày tải lên: 12/08/2014, 16:21

... (x_1,x _2) = (6.5,0)’), text(0 .2, 2,’t=2s: (x_1,x _2) = (0 ,2) ’) Executing the script: >> robot Coefficients for theta1 motion: a= 0 .20 29 -1.0145 1.3 526 Coefficients for theta2 motion: b= 0.35 02 -1.7508 2. 3344 The ... accelerometer 22 6 0 1 2 3 4 5 6 7 −0.5 0 0.5 1 1.5 2 2.5 3 3.5 4 x 1 x 2 Path of robot hand t=0s: (x 1 ,x 2 ) = (6.5,0) t=2s: (x 1 ,x 2 ) = (0 ,2)...

Ngày tải lên: 12/08/2014, 16:21

... -5 /2/ pi*3^(1/3)*(pi ^2) ^(1/3)-5 /2* i*3^(5/6)/pi*(pi ^2) ^(1/3)] >> Rmins = double(Rmins) Rmin = 4. 923 7 -2. 4619+ 4 .26 41i -2. 4619- 4 .26 41i >> Rmin = Rmins(1) Rmin = 4. 923 7 26 4 >> E = ... cos (2* theta) B= cos (2* theta) >> B = expand(B) B= 2* cos(theta) ^2- 1 >> C = 6*((sin(theta)) ^2 + (cos(theta)) ^2) C= 6*sin(theta) ^2+ 6*cos(theta) ^2 >...

Ngày tải lên: 12/08/2014, 16:21

... this polynomial over the range of 20 -30 hours we define a ne w time vector (the independent variable) »newtime = [20 :30] newtime = 20 21 22 23 24 25 26 27 28 29 30 Use the function polyval(coefficient_vector,independent ... symbols) »t = [1:10]; »y1 = [2 4 6 8 10 12 14 16 18 20 ]; »y2 = [2 5 7 9 11 13 15 17 19 21 ]; »plot (t,y1,t,y2,'o') % note t is repeated. 0 5...

Ngày tải lên: 06/08/2014, 13:22