Engineering Matlab Problem Solving phần 2 pptx
Engineering Matlab Problem Solving phần 2 pptx
... base 2 value 00110101, denoted by
53
10
= 00110101
2
In base 10, this means
53
10
=5×10
1
+3× 10
0
Similarly,
00110101
2
=0× 2
7
+0× 2
6
+1× 2
5
+1× 2
4
+0× 2
3
+1× 2
2
+0× 2
1
+1× 2
0
= 32
10
+16
10
+4
10
+1
10
Thus, ... cosines: a
2
= b
2
+ c
2
− 2bc cos α
Law of tangents:
a −b
a + b
=
tan
1
2
(α −β)
tan
1
2
(α + β)
Included angles: α + β + γ = π radians = 1...
Engineering Matlab Problem Solving phần 4 pptx
... 0 0.5 1 1.5 2 2.5 3 3.5 4 4.5 5
2
0
2
4
6
8
10
12
Multiple Axis Plot
x
0 0.5 1 1.5 2 2.5 3 3.5 4 4.5 5
−10
0
10
20
30
40
50
60
Figure 5.3: Plot with two polynomial ... figure(n)
97
>> x=(0:0.1:1)*pi
x=
Columns 1 through 7
0 0.31 42 0. 628 3 0.9 425 1 .25 66 1.5708 1.8850
Columns 8 through 11
2. 1991 2. 5133 2. 827 4 3.1416
As in addressing, (0:5) creates a vector that st...
Engineering Matlab Problem Solving phần 1 doc
... AppliedProblemSolving:RobotMotion 20 2
10 Curve Fitting and Interpolation 20 7
10.1MinimumMean-SquareErrorCurveFitting 20 7
10 .2 Applied Problem Solving: Hydraulic Engineering . 21 3
10.3Interpolation 21 5
10.4AppliedProblemSolving:HumanHearing ... Terminology . . . 12
2 Matlab Technical Computing Environment 14
2. 1 Workspace,Windows,andHelp 14
2. 2 ScalarMathematics 15
2....
Engineering Matlab Problem Solving phần 3 docx
... quotient
by the conjugate of z
2
:
z
1
z
2
=
x
1
+ jy
1
x
2
+ jy
2
=
(x
1
+ jy
1
)(x
2
− jy
2
)
(x
2
+ jy
2
)(x
2
− jy
2
)
=
(x
1
+ jy
1
)(x
2
− jy
2
)
x
2
2
+ y
2
2
68
We can summarize the representations ... identity j
2
= −1, and writing the result
in rectangular form:
z
1
z
2
=(x
1
+ jy
1
)(x
2
+ jy
2
)
= x
1
x
2
+ jx
1
y
2
+ jx
2
y
1
+ j
2
y
1...
Engineering Matlab Problem Solving phần 5 pdf
... poly(r)
a=
1.0000 -2. 0000 -3.0000 10.0000
Example 6.1 Finding the depth of a well using roots of a polynomial
118
X=
-2- 10 12
-2- 10 12
-2- 10 12
-2- 10 12
Y=
-1 -1 -1 -1 -1
00000
11111
22 222
After the underlying ... with Matlab:
>> d = depth (2)
d=
28 .6 425
>> t1 = sqrt (2* d/g)
t1 =
2. 4165
>> t2 = d/c
t2 =
0.0835
>>t=t1+t2
t=
2. 5000
Thus, the dept...
Engineering Matlab Problem Solving phần 7 docx
... two such simulations:
23 4 521 3314
522 5563635
150
The displayed output of the script is:
0 25 .0000
10.0000 18.9811
20 .0000 15.3773
30.0000 13 .21 96
40.0000 11. 927 7
50.0000 11.15 42
60.0000 10.6910
70.0000 ... the
mean ( 2 <z< ;2) , and 99% will fall within three standard deviations of the mean (−3 <z<3).
The Matlab functions for generating Gaussian random numbers are...
Engineering Matlab Problem Solving phần 8 ppsx
... a
11
(a
22
a
33
− a
23
a
32
) − a
12
(a
21
a
33
− a
23
a
31
)+a
13
(a
21
a
32
− a
22
a
31
)
= a
11
a
22
a
33
− a
11
a
23
a
32
− a
12
a
21
a
33
+ a
12
a
23
a
31
+ a
13
a
21
a
32
− a
13
a
22
a
31
Thus, ... Thus,
A. ^2 =
a
2
11
a
2
12
a
2
1n
a
2
21
a
2
22
a
2
2n
.
.
.
.
.
.
.
.
.
a
2
m1
a
2
m2
a
2
mn
To square th...
Engineering Matlab Problem Solving phần 9 pot
... (x_1,x _2) = (6.5,0)’),
text(0 .2, 2,’t=2s: (x_1,x _2) = (0 ,2) ’)
Executing the script:
>> robot
Coefficients for theta1 motion:
a=
0 .20 29
-1.0145
1.3 526
Coefficients for theta2 motion:
b=
0.35 02
-1.7508
2. 3344
The ... accelerometer
22 6
0 1 2 3 4 5 6 7
−0.5
0
0.5
1
1.5
2
2.5
3
3.5
4
x
1
x
2
Path of robot hand
t=0s: (x
1
,x
2
) = (6.5,0)
t=2s: (x
1
,x
2
) = (0 ,2)...
Engineering Matlab Problem Solving phần 10 ppsx
... -5 /2/ pi*3^(1/3)*(pi ^2) ^(1/3)-5 /2* i*3^(5/6)/pi*(pi ^2) ^(1/3)]
>> Rmins = double(Rmins)
Rmin =
4. 923 7
-2. 4619+ 4 .26 41i
-2. 4619- 4 .26 41i
>> Rmin = Rmins(1)
Rmin =
4. 923 7
26 4
>> E = ... cos (2* theta)
B=
cos (2* theta)
>> B = expand(B)
B=
2* cos(theta) ^2- 1
>> C = 6*((sin(theta)) ^2 + (cos(theta)) ^2)
C=
6*sin(theta) ^2+ 6*cos(theta) ^2
>...
A Guide to MATLAB for Chemical Engineering Problem Solving phần 2 potx
... this polynomial over the range of 20 -30 hours we define a ne w
time vector (the independent variable)
»newtime = [20 :30]
newtime =
20 21 22 23 24 25 26 27 28 29 30
Use the function polyval(coefficient_vector,independent ... symbols)
»t = [1:10];
»y1 = [2 4 6 8 10 12 14 16 18 20 ];
»y2 = [2 5 7 9 11 13 15 17 19 21 ];
»plot (t,y1,t,y2,'o') % note t is repeated.
0
5...
Từ khóa:
- đồ thị smith smith chart phần 2 pptx
- lập trình giao diện gui trong matlab phần 2
- tài liệu giáo trình dạy đọc tiếng nga 2 phần 25 pptx
- tài liệu giáo trình dạy đọc tiếng nga 2 phần 26 pptx
- technology assisted problem solving packages for engineering
- advanced topics for problem solving with matlab
- phần 2
- problem solving