Robotics Episode 5 pptx

... “bios.h.” FIGURE 3. 45 Above shows the connections of the null modem using an RS 232D connector. 9 8 7 6 1 2 3 4 5 5 9 4 8 3 7 6 1 2 ROBOTICS 128 pneumatic actuator in Figure 3.49 is shown in Figure 3 .50 with ... 16 x 2 1 GND 2 Vcc 3 Vo 4 RS 5 RW 6 E 7 D0 8 D1 9 D2 10 D3 11 D4 12 D5 13 D6 14 D7 15 Vb1 16 Vbo 1 2 3 4 5 6 7 8 9 13 25 14 1 +5V 10k 17 BASIC ELECTRONICS 131 A majo...

Ngày tải lên: 12/08/2014, 16:21

... 200 L (50 gal) 0.2 % 0.3 % 0 .5 % 0.3A Asphalt at temperatures greater than 50 ° C 0.3 % 0.3 % 0 .5 % 0 .5* Petroleum products delivered from small capacity (at 4 L/min (1 gpm) through 1 15 L/min ... Motor-fuel device 15, 16, 17 Nonautomatic 18 Normal tests 13 Operating requirements 5, 7 Parallax 5 Power loss 5 Price contract sales 6, 7, 17 Primary indicating element 3...

Ngày tải lên: 12/08/2014, 07:22

... the harmonics have frequencies of 50 MHz, 75 MHz, etc., and the oscilloscope's response at these frequencies will be very low indeed. Even an ideal 25 MHz squarewave will look tolerably ... single-ended (unbalanced) 50 ~ ouput suitable for connection to any oscilloscope's Y input channel. The P6046 provides 10 000:1 CMRR at 50 kHz and no less than 1000:1 even at...

Ngày tải lên: 12/08/2014, 16:21

... 36 5. 08 350 -55 8 350 -55 8 25 25 12 180 (62% Cu) Outokumpu flash furnace 5. 8 tonnes of reverts 60 tonnes anodes, cathodes, molds, reverts, etc. 180 56 3 0 .5 1 8.6 1. 75 3.91 ... 0-0.1 0 0-0.004 0-0 .5 ; FeLh cu Total Fe Si02 (e+$) A1203 CaO MgO ZnO H20 Flux 70-98 0-10 0 -5 0-2 0 1 -5 Converter slag 4-8 35- 50 15- 30 20- 25 0 -5...

Ngày tải lên: 13/08/2014, 05:20

... +E n I n  ℓ n 0  ∂ 2 Z n ∂x 2  2 dx =[X I Z I Z ′ I X J Z k Z ′ J ]        K 11 K 12 K 13 K 14 K 15 K 16 K 21 K 22 K 23 K 24 K 25 K 26 K 31 K 32 K 33 K 34 K 35 K 36 K 41 K 42 K 43 K 44 K 45 K 46 K 51 K 52 K 53 K 54 K 55 K 56 K 61 K 62 K 63 K 64 K 65 K 66               X I Z I Z ′ I X J Z J Z ′ J        where ... see Figure 3. 15. As in [3.9...

Ngày tải lên: 13/08/2014, 05:22

... r 2 F 21  −s, s + 1 2 , 1,r 2  J 0 (k n r) dr. (3.3 .55 ) Equation 3.3 .55 is now solved to yield B m .Next,wecompute A n from Equa- tion 3.3 .50 . Finally u(r, z)follows from Equation 3.3.47. Figure ... 133 −1 −0 .5 0 0 .5 1 −1 −0 .5 0 0 .5 1 −0.2 0 0.2 0.4 0.6 0.8 1 x y u(r,θ ) Figure 3.4.1:Thesolutionu(r, θ)tothe mixed boundary value problem posed in Example 3.4.1 with α = π/4andb =0...

Ngày tải lên: 13/08/2014, 05:22

... CVI-3 PI-0 PI-1 PI-2 .< K 48 1 55 9 460 59 0 56 8 463 647 736 P 1.13 1 .55 1 .55 1.62 1.60 1 .56 1.70 1.79 KIP 428 36 1 297 364 355 297 381 411 1 65 are expected to enable the use of ... 289(x) E? h4 200 U(x) B H1 1.32 50 2(X) H2 1.48 52 8(X) H3 1 .59 56 4CX) 380(X) C 357 oc) C 355 (X) C ., H 2.00 mixj C * A: V, = 25% , p = 055 g/cm3....

Ngày tải lên: 13/08/2014, 08:21

... of mid-ordinate 15 ° 10 sin 15 ° D 2 .58 8 V 45 ° 10 sin 45 ° D 7.071 V 75 ° 10 sin 75 ° D 9. 659 V 1 05 ° 10 sin 1 05 ° D 9. 659 V 1 35 ° 10 sin 1 35 ° D 7.071 V 1 65 ° 10 sin 1 65 ° D 2 .58 8 V Sum of mid-ordinates ... speed/time is shown in Fig. 20.3. 30 25 Graph of speed/time 20 15 Speed (m/s) 10 5 0 12 3 Time (seconds) 45 6 2 .5 4.0 7.0 15. 0 5. 5 8. 75 10. 75...

Ngày tải lên: 13/08/2014, 08:21

... In the same high speed 126 Tool damage 0 5 10 15 0 5 10 15 0 0.1 0.2 0.3 0.4 0 20 40 60 80 Real cutting time (min) Real cutting time (min) 150 m min -1 150 m min -1 236 m min -1 Turning Milling 236 ... and Inconel 718 0. 05 0.02 0.1 0.2 0 .5 1.0 2.0 5 10 20 40 60 80 99 85 Flank wear VB (mm) P10 Sintered steel P10 B1112 TiC-Al 2 O 3 ceramic Inconel 718 VB max B112 - P10, V = 200...

Ngày tải lên: 13/08/2014, 09:20