Process Control Systems Episode 8 doc
process control systems application design and adjustment
... 182
Pairing Controlled and Manipulated Variables
188
Decoupling Control Systems 198
Summary 202
References 202
Problems
203
8.
Feedforward Control
204
The Control System as a Model of the Process
206’
Applying ... 228
Problems 228
APPLICATIONS
9.
Control of Energy
Transfer 233
Heat Transfer
23.4
Combustion Control
241
Steam-plant Control Systems 243
Pumps and Compresso...
Advances in Flight Control Systems Part 1 doc
...
DAP
=
A
11
A
12
2A
16
B
11
B
12
2B
16
A
12
A
22
2A
26
B
12
B
22
2B
26
A
16
A
26
2A
66
B
16
B
26
2B
66
B
11
B
12
2B
16
D
11
D
12
2D
16
B
12
B
22
2B
26
D
12
D
22
2D
26
B
16
B
26
2B
66
D
16
D
26
2D
66
⎡
... Uninhabited Aerial Vehicles (UAVs)
5
Conventionally Attached Piezoelectric Actuators:
N
M
⎧
⎨
⎩
⎫
⎬
⎭
CAP
=
A
11
A
12
0 B
11
B
12...
Advances in Flight Control Systems Part 2 doc
... Tsach et al., 20 03, Ren and Beard, 20 04, Wegener et al., 20 04, Ren and
Atkins, 20 05, No et al., 20 05, Clough, 20 05, Papadales et al., 20 05, Narasimhan et al., 20 06,
Kaminer et al., 20 07). Other ... the
tracking controllers. Singh (20 03) uses a combination of sliding-mode control and adaptive
control.
In this chapter an integrated, though cascaded Lyapunov-based adap...
Proakis J. (2002) Communication Systems Engineering - Solutions Manual (299s) Episode 8 docx
... −
√
10 · 1.256 = −3.97 18
ˆx
5
= −ˆx
12
= −
√
10 · 0.9424 = −2. 980 1
ˆx
6
= −ˆx
11
= −
√
10 · 0.65 68 = −2.0770
ˆx
7
= −ˆx
10
= −
√
10 · 0. 388 1 = −1.2273
ˆx
8
= −ˆx
9
= −
√
10 · 0.1 284 = −0.4060
The resulting ... −a
9
= −
√
10 · 0.2 582 = −0 .81 65
a
8
=0
The quantized values are
ˆx
1
= −ˆx
16
= −
√
10 · 2.733 = 8. 6425
ˆx
2
= −ˆx
15
= −
√
10 · 2.069 = −6.54 28
ˆx
3
= −ˆx
14
= −
√...
Process Control Systems Episode 2 pps
... gain at
70
=
2. 5~~
be 1.0:
G(+!!=lO
1 2
P .
Substituting for the dynamic gains of
~~
and
72,
Substituting
2. 5~~
for
TV,
2. 5 ~2
2. 5 ~2
P = 100
~
~
2TTl
2lrr2
r=1s;
(1 .25 )
This is the ... Fig. 2. 1. As a
40 1 Understanding Feedback Control
Since
72
= 2,
n2
+ n
4 +2
3
zz-=
2 2
and
3:
= (2. 618)(0.3 82) = 1.00
With three capacities of time constant
7,
T...
Process Control Systems Episode 4 ppt
... 0
125
-36
P
127r&,
158
220
361
llOTd/T,
127
196
22%,/T,
2 54
540
Process
70
Gain
4. OOsd
0.64rd/r,
4. 80 0.76
6.00
0.95
8.00 1.27
-__
3.197d
0.517&1
4. 00 0. 64
5.37 0.86
2.867d
0 .45 rJn
4. 00 0. 64
6.79
1.08
Perform-
ance,
PR/100
m
4 .52sd2/rl
3.65
4. 58
0.9772/71
0.81
0.96
2. ... 0.86
Interacting
three-mode
_-
?
1
,
D
0
0
0
0
__-
0,907d
0. 64
0. 54
,Controller
R...
Process Control Systems Episode 6 pot
... prime variable.
Secondary
Controller
Primary
controller
FIG 6. 1. Cascade control resolves the process
into two parts, each within a closed loop.
1 56 1 Multiple-loop Systems
The vector gain of ... constant
gain for the primary loop.
RATIO CONTROL SYSTEMS
In a ratio control system, the true controlled variable is the ratio K of
two measured variables X and Y:
K=;
(6. 3)
Contr...
Process Control Systems Episode 7 ppsx
... its
control systems ought never to interfere with this aspiration.
Multivariable Process Control
I
1 97
FIG 7. 7. The effect of m2 on
cl
de-
pends on the ratio of their periods.
Equation (7. 20) ... expanded in Chap. 7,
Multivariable Process Control.
But the deepest penetration into the
194
1
Multiple-loop Systems
component blending system be as follows:
am
-I-
bm
(...
Process Control Systems Episode 8 doc
... Manipulated
variable
-
c
*
Process
Controlled
variable
*
I
I
FIG 8. 1. The control system embodies a for-
ward flow of information.
Feedforward Control
I
223
MzY
FIG 8. 17. The complete control
system for ... Appara-
tus, British Patent No. 86 0, 485 , February 8, 1961.
3.
MacMullan,
E. C., and F. G. Shinskey: Feedforward Analog Computer Control
of a Superfractionator, Cont...
Process Control Systems Episode 9 pps
... WCCC/WHCH)
(9. 11)
(9. 12)
To envision what effect flow rates have upon exit temperature, Eg. (9. 11)
is
plot’ted
in Fig. 9. 4 with the same abscissa and parameter that were
used in Fig. 9. 3.
FIG 9. 4. ... with Eq. (9. 11) yields:
THI
-
THZ
1
THI
-
TCI
=
CH/AkH -k
96
ãk ( WHCH/WCCC)(CC/A~C -k
35)
(9. 13)
A plot of Eq. (9. 13) for conditions of
CH/AkH
= Cc/Akc = 1 is given...
Process Control Systems Episode 12 pdf
... balance:
V(1
-
y) = F(l
-
2)
(12. 7)
The combination of Eqs. (12. 5) through (12. 7) permit’s solution for the
value of the manipulated variable L required to control either y or
2,
the
other ...
-Y)
(12. 8)
n’otice
the resemblance of Eq. (12. 8) to
t’he
feedforward control
equat’ion
for binary distillation.
As in distillation, there is a relationship between
y
and
Z,
of...
Process Control Systems Episode 13 docx
... 124
on-off, 131
with differential gap, 132
in dual-mode systems,
137 -141
limit cycle due to, 131
with proportional time, 133 , 134
with reset and derivative, 135
three-state, 134 , 135
peak-seeking, ... 278
discontinuous, 149
for pH control, 279
dual-mode, 136 -144
on-off, 131
with differential gap, 132
proportional time, 133 , 134
three-state, 134 , 135
Nonlinear...
Industrial Control Wiring Guide 2E Episode 8 doc
... layout of the wiring that is
critical to avoid interference and this will have been
worked out by the designer. This aspect of wiring
concerns the EMC regulations.
᭹ The layout of such wiring should ... the
system, for example power wiring that could be
carrying high currents at 415 volts. Signal wires that
may be connected to sensors and to the input terminals
of a programmable contr...