Process Control Systems Episode 2 pps

... gain at 70 = 2. 5~~ be 1.0: G(+!!=lO 1 2 P . Substituting for the dynamic gains of ~~ and 72, Substituting 2. 5~~ for TV, 2. 5 ~2 2. 5 ~2 P = 100 ~ ~ 2TTl 2lrr2 r=1s; (1 .25 ) This is the ... in Fig. 2. 1. As a 40 1 Understanding Feedback Control Since 72 = 2, n2 + n 4 +2 3 zz-= 2 2 and 3: = (2. 618)(0.3 82) = 1.00 With three capacities of time constant 7,...

Ngày tải lên: 12/08/2014, 16:21

... respect to m2. fnl = gcl(rl - Cl) Cl = mg1X11 + 77zzg2~ 12 Cl(l + gclglX11) = ~lgclgixll + 77~2gz~ 12 Differentiation of cl with respect to m2 yields dc1 -= gzx 12 dm2 1 + gelgAl1 - ... mFmz (7 .22 ) m2 is the product of the flow-controller output with the complement of the composition-controller output: m2 = mF(1 - m,) (7 .23 ) FiguT 7.9 illustrates both the cou...

Ngày tải lên: 12/08/2014, 16:21

... their slopes. For the plug-flow reactor, dy Jc (1 - y) 111 (1 - y) dT = RT2 ‘I 2 7 c E 22 1 SO 20 0 22 0 24 0 26 0 FIG 10.1. Reaction rate is pro- foundly influenced by temperature. (10.11) Temperature. ... The control system for once-through boiler must be as closely knit as the process itself. Control of Energy Transfer h P a Set boint to combustion- :ontrol system...

Ngày tải lên: 12/08/2014, 16:21

... 0.64 6.79 1.08 Perform- ance, PR/100 m 4 .52sd2/rl 3.65 4.58 0.97 72/ 71 0.81 0.96 2. 05rd2/r1 1. 62 2. 92 106 1 Selecting the Feedback Controller For Dead Time In theory, complementary feedback is capable of critically damping a process ... 0 125 -36 P 127 r&, 158 22 0 361 llOTd/T, 127 196 22 %,/T, 25 4 540 Process 70 Gain 4.OOsd 0.64rd/r, 4.80 0.76 6.00 0.95 8.00 1 .27...

Ngày tải lên: 12/08/2014, 16:21

... secondary loop will be designated g 02: it is the ratio of output c2 to input r2. The vector consists of a scalar gain Go2 and a phase angle c#+,~. c2 EC&P go2 = T, = 1 + g,g, (6.1) The ... as the input to a controller is e - Controller c not recommended. Nonlinear Control Elements I 141 Linear 0’ Time, set 60 40 0 Time, set FIG 5 .22 . The nonlinear two-mode contro...

Ngày tải lên: 12/08/2014, 16:21

... Fig. 8. 12. 7 FIG 8. 12. The location of the peak +P in the uncompensated response 0.5 transient can be used to infer the required compensation. 0 0 .2 0.5 1.0 2. 0 5.0 Tf/r2 22 4 1 Multiple-loop Systems Tz ... Manipulated variable - c * Process Controlled variable * I I FIG 8.1. The control system embodies a for- ward flow of information. Feedforward Control I 22 3 MzY FIG 8.1...

Ngày tải lên: 12/08/2014, 16:21

... 7.716 X IOeG ft/rpm2, and kz = 0.01 ft/gpm2; N = 3, 120 rpm. HHP at 3, 120 rpm is 0.6 32 HP; at 3,600 rpm it is 0.948 HP. Chapter 10 10.1 Tc = T - RT=/E = 20 6 .2 F. lo .2 TT = -3 min; 70 ... composition 20 , in order to control the concentrat,ion of cxtract,cd product. If this is indeed the case, Eqs. ( 12. 2G) and ( 12. 27) may be solved for R in terms of yl: B =...

Ngày tải lên: 12/08/2014, 16:21

... exchangers, 20 9 -21 1, 22 3, 22 4 lag in, 22 2 of liquid level, 20 7, 20 8 load response with, 21 7 material balance in, 20 6 optimizing, 175, 22 5 payout of, 22 7 of pH, 27 8 -28 2 set-point response with, 22 2 square-root ... distillation, 29 8, 29 9, 305 in drying, 345, 346 by feedforward, 20 9 -21 1, 22 3, 22 4 in fired heaters, 24 3 in heat exchangers, 23 6 -23 9 in r...

Ngày tải lên: 12/08/2014, 16:21

... 110. 52 110. 52 2 120 .0 121 .0 122 .04 122 .14 122 .14 5 150.0 161.05 164.53 164.86 164.87 10 20 0.0 25 9.37 27 0.70 27 1.79 27 1.83 20 300.0 6 72. 75 7 32. 81 738.70 738.91 30 400.0 1744.94 1983.74 20 07.73 20 08.55 ... 130.7 6.1 20 01 177.1 1.6 1991 136 .2 3.1 20 02 179.9 2. 4 19 92 140.3 2. 9 20 03 184.0 1.9 1993 144.5 2. 7 20 04 188.9 3.3 20 05 195.3 3.4 Source: Mon...

Ngày tải lên: 06/08/2014, 15:20