Principles of Engineering Mechanics (2nd Edition) Episode 4 pot

... moment of external forces = C moment of (mass x acceleration) = moment of the rate of change of = rate of change of the moment of or momentum momentum We may n~~ke use of ... methods The magnitude of 4 is C’C 4. 7 BC 0.19 4 = - = - = 24. 7 rads2 To determine the sense of 4 we note that the normal component of urn is c’c in t...

Ngày tải lên: 12/08/2014, 16:21

... Moment of inertia of a body about an axis 77 Figure 6.8 = (pLdrrdO)r2 hence for the whole body 2lr a pLr3 drd9 IGz= Io Io = 1,“ pLr3dr2.rr = pL2.rra4 14 = 4. rrpLa4 The mass of ... 6.16 The track of the wheels of a vehicle is 1 .4 m and the centre of gravity G of the loaded vehicle is located 92 Energy k. e. = 4M (O x B ) - (W x B) +...

Ngày tải lên: 12/08/2014, 16:21

... centre of mass G falls through a vertical distance ~ (4. 675)~ = 45 .0 J ho = (AG)(sin 0, - sin45") b) The free-body diagram on the left of Fig. 8.19 is for a fixed quantity of fluid. ... velocity at t = 6.728 s is given by v = +[O+ 11.63 +4( 2.1 24+ 6.117+9. 842 ) + 2 (4. 159 + 8.008)] = 36.1 mls Example 8.7 A sphere of mass ml is moving at a...

Ngày tải lên: 12/08/2014, 16:21

... BC and CD as shown in Fig.7 .42 . Each has a length of 0.5m and a mass of 2.0kg. A torsion spring (not shown) at A has a stiffness of 40 Ndrad, one end of the spring being fixed and ... consequence of equations 8.8 to 8.10 is the relationship which exists between the velocity of approach and the velocity of recession of the points of contact. Velocity of...

Ngày tải lên: 12/08/2014, 16:21

... -3.01 -45 .00 which makes the curve pass through the critical 2/r -6.99 -63 .43 4/ 7 - 12.30 -75.96 1 o/r -20. 04 - 84. 29 Once scales for the graphs have been chosen, all of the graphs of ... three 1/(107) -0. 04 -5.71 particular values of K are sketched in Figs 1/ (4~ ) -0.26 - 14. 04 10.31(a), (b) and (c). 1 /(2 7) -0.97 -26.57 In Fig. 10.31(b) a value of...

Ngày tải lên: 12/08/2014, 16:21

... phase margin of 45 " this value of I G(jw) 1 should be unity so C needs to be reduced by a factor of 4. 4 64. This gives C = 10 14. 4 64 = 2. 24. Example 10.7 Figure 10.51(a) shows ... 1 .42 7 rads the phase angle C$ = -135.02". Using the value of C = 10 as in a) above we find that the corresponding value of 'I G(jw) 1 is 4. 4 64. For...

Ngày tải lên: 12/08/2014, 16:21

... the yz plane (1 2. 64) The proofs of these two theorems are similar to those given for moments of inertia in section 6.3. Using the definition of second moment of area equation 12.62 ... of cross-section as shown in Fig. 12. 24. The applied in a plane normal to the axis of the shaft. elemental shear force is In the case of beams the loading is transverse to the a...

Ngày tải lên: 12/08/2014, 16:21

... 1.385 ds2, 0 .43 6 ds2 4. 1 87.0 N m anticlockwise 4. 2 4. 3 21.0 kN, 3 .49 kN, 14. 4 kN 5.9 a) 0.5 rads anticlockwise, 4. 4 a) (-2lOi+505Oj) N, 4. 5 a) 190N h 52", 4. 7 -30kN, ... anticlockwise 8.16 a) (-11.311' +4. 69j) ds2, 8.17 20 .44 kN 8.1 (2 348 1'- 540 j+ 3924k) N 8.7 a) 11.4kN, 8.11 (23.4k) rads', b) (- 54. 4i-tO.23) N, (9.37...

Ngày tải lên: 12/08/2014, 16:21

... Rcose = 49 41~0 ~41 " = 3729.0 m y = Rsin8 = 49 41sin41" = 3 241 .0 m so A is located at point (3729, 3 241 ,800.2) m. For point B, r= 7037m, 8 = 73 .4& quot;, 4 = 1.3"; ... XY z (44 - 1 jk - AxB= A, A, A, (4. 3) Fx Fy Fz Bx By Bz 4. 5 Couple From Fig. 4. 4 we note that by the definition of the vector product of two vectors, e...

Ngày tải lên: 27/06/2014, 05:20

... acceleration of B, aB , can be scaled from the figure. + 1.5(3)(-0. 342 3+ 0. 940 j) % = VA +%/A % = 4i + (0.34i+ 4. 01j) thus = (4. 34i +4. 91.) m/s2 The speed of B is the magnitude of VB ... = 49 41.0 m x = Rcose = 49 41~0 ~41 " = 3729.0 m y = Rsin8 = 49 41sin41" = 3 241 .0 m so A is located at point (3729, 3 241 ,800.2) m. For poi...

Ngày tải lên: 27/06/2014, 18:20