compilers principles techniques and tools phần 2 docx

... left operand, 2 is evaluated, and then the right operand. The constant 2 generates no three-address code, and its r-value is returned as a Constant node with value 2. The right operand a ... 2. 6 Exercise 2. 6.1 : Extend the lexical analyzer in Section 2. 6.5 to remove com- ments, defined as follows: Simpo PDF Merge and Split Unregistered Version - http://www.simpopdf...

Ngày tải lên: 12/08/2014, 11:20

... grammar of Exercise 4 .2. 2(c). d) The grammar of Exercise 4 .2. 2 (d) . e) The grammar of Exercise 4 .2. 2(e). f) The grammar of Exercise 4 .2. 2(g). ! ! Exercise 4.4 .2 : Is it possible, by ... parsers and show the parsing tables. You may left-factor and/ or eliminate left-recursion from your grammars first. a) The grammar of Exercise 4 .2. 2(a). b) The grammar of Exercise...

Ngày tải lên: 12/08/2014, 11:20

... 38 2 A Simple Synt ax-Direct ed Translator 39 2. 1 Introduction 40 2. 2 Syntax Definition 42 2. 2.1 Definition of Grammars 42 2. 2 .2 Derivations 44 2. 2.3 Parse Trees 45 2. 2.4 ... 2. 2.5 Associativity of Operators 48 2. 2.6 Precedence of Operators 48 2. 2.7 Exercises for Section 2. 2 51 2. 3 Syntax-Directed Translation 52 2. 3.1 Postfix Notatio...

Ngày tải lên: 12/08/2014, 11:20

... Exercise 4 .2. 2(g)] and produces the truth value of the expressions. ! Exercise 4.9 .2 : Write a Yacc program that takes lists (as defined by the grammar of Exercise 4 .2. 2(e), but with ... another label L2, and the code for S1. This SDD is L-attributed. When we convert it into an SDT, the only re- maining issue is how to handle the labels L1 and L2, which are variable...

Ngày tải lên: 12/08/2014, 11:20

... E2. The action either creates a node for E with the nodes for El and E2 as children, or it generates a three-address instruction that applies op to the addresses for El and E2 and ... Fig. 6. 32 uses s = find(m) and t = find(n) rather than m and n, respectively. The representative nodes s and t are equal if m and n are in the same equivalence class. If...

Ngày tải lên: 12/08/2014, 11:20

... node like B2, which does not have an edge B2 + B2, is not a loop, since there is no nonempty path from B2 to itself within {B2). The third loop, L = {B2, B3, B4), has B2 as its loop ... GENERATOR 547 into registers R1 and R2, and the value t produced in register R2. Notice that we can use R2 for t because the value b previously in R2 is not needed within the...

Ngày tải lên: 12/08/2014, 11:20

... Section 9 .2. 4; we repeat the argument succinctly here. Suppose we have two functions fi (2) = GI U (x - K1) and f2 (2) = G2 U (X - K2). Then f2 (fi (2) ) = G2 U ((GI ... equivalent to (G2 U (GI - K2)) U (X - (Ki U ~2) ). If we let K = Kl U K2 and G = G2 U (GI - K2), then we have shown that the composition of fl and f2, which...

Ngày tải lên: 12/08/2014, 11:20

... rl+r2 LD r2, c // r2 = c ADD rl, rl, r2 // rl = rl+r2 LD r2, d // r2 = d LD r3, e // r3 = e ADD r2, r2, r3 // r2 = r2+r3 ADD r1, r1, r2 // r1 = rl+r2 Figure ... a 2) LD R2, b LD R2, b LD R2, b 3) SUB R3, Rl, R2 SUB Ri, Ri, R2 SUB R3, Rl, R2 4) ADD R2, Rl, R2 ADD R2, Ri, R2 ADD R4, R1, R2 5) ST a, R3 ST a, R1 ST a, R3 6) ST b, R2...

Ngày tải lên: 12/08/2014, 11:20

... 23 710 learning Test 1917 21 09 6101 724 2 121 04 23 714 Number of labels 10 26 26 10 26 26 Figure 5.8 Reconstruction of the prototypes extracted for (a) the ‘0’ digit; (b) the upper-case letter ‘M’; and (c) the ... 619– 622 , 19 92. [14] Lu, Z., Chi, Z. and Shi, P. “A Background Thinning-Based Approach for Separating and Recognizing Connected Handwritten Digit Strings,” Patter...

Ngày tải lên: 14/08/2014, 11:21

... identity” in the sense of Geach (19 62) and Gupta (1980). This means that only they can bind anaphors ( (21 )), traces of various kinds, and the theta-roles of verbs ( (22 )), among other things. Chapter ... But I have already questioned the accuracy and utility of making this the fundamental distinction between verbs and other categories (section 2. 2). And indeed in all of the la...

Ngày tải lên: 24/07/2014, 02:20