Wankat & Oreovicz - Teaching Engineering Episode 4 potx
... Instructor-lead discussions. C. Student-centered Discussions. 118 CHAPTER 7: NONTECHNOLOGICAL ALTERNATIVES TO LECTURES Teaching Engineering - Wankat & Oreovicz methods are one of the appropriate teaching ... Conducting Discussions 1 14 CHAPTER 7: NONTECHNOLOGICAL ALTERNATIVES TO LECTURES Teaching Engineering - Wankat & Oreovicz CHAPTER 7 NONTECHNOLOGICAL ALT...
Ngày tải lên: 12/08/2014, 08:22
... CREATIVITY 83 Teaching Engineering - Wankat & Oreovicz C - combine R - reverse E - expand A - alter T - tinier I - instead of V - viewpoint change I - in another sequence T - to other uses Y - yes! ... do Creativity FIGURE 5-1 CONCEPT MAP OF PROBLEM SOLVING. Reprinted with permission of CEE, 13 , 132, (1979). 64 CHAPTER 4: COURSES:...
Ngày tải lên: 12/08/2014, 08:22
... only 9.2 .4. Advantages and Disadvantages of Laboratory Courses 206 CHAPTER 10: ONE-TO-ONE TEACHING AND ADVISING Teaching Engineering - Wankat & Oreovicz 10 .4. 1. Undergraduate Research 10 .4. 2. ... behaviorItem TABLE 1 0-2 COMPARISON OF LECTURING AND TUTORING 10.2.3. Goals of Tutoring 1 94 CHAPTER 10: ONE-TO-ONE TEACHING AND ADVISING Teaching Engineering -...
Ngày tải lên: 12/08/2014, 08:22
Wankat & Oreovicz - Teaching Engineering Episode 8 ppsx
... 10: ONE-TO-ONE TEACHING AND ADVISING Teaching Engineering - Wankat & Oreovicz Eng. Educ., 71, 159 (Nov. 1980). Palmer, P. J., To Know as We Are Known: A Spirituality of Education, Harper-Collins, ... end of the student’s career. 12.3. TEACHING ETHICS 2 34 CHAPTER 11: TESTING, HOMEWORK, AND GRADING Teaching Engineering - Wankat & Oreovicz McKeachie, W. J.,...
Ngày tải lên: 12/08/2014, 08:22
Wankat & Oreovicz - Teaching Engineering Episode 10 pps
... position 14. 2.3. Implications for Engineering Educa- tion 272 CHAPTER 14: MODELS OF COGNITIVE DEVELOPMENT: PIAGET AND PERRY Teaching Engineering - Wankat & Oreovicz This position has some built-in ... but retention (hence long-term learning) is 15.3. KOLB’S LEARNING CYCLE 2 94 CHAPTER 15: LEARNING THEORIES Teaching Engineering - Wankat & Oreovicz Motivati...
Ngày tải lên: 12/08/2014, 08:22
Wankat & Oreovicz - Teaching Engineering Episode 11 pps
... and improve engineering education. In particular, the research on right- and left-brain functioning 15.5. CHAPTER COMMENTS CHAPTER 16: EVALUATION OF TEACHING 311 Teaching Engineering - Wankat & Oreovicz available ... Tenure CHAPTER 17 PROFESSIONAL CONCERNS TEACHING ENGINEERING 308 CHAPTER 16: EVALUATION OF TEACHING Teaching Engineering - Wankat & Oreovic...
Ngày tải lên: 12/08/2014, 08:22
COMPUTATIONAL MATERIALS ENGINEERING Episode 4 potx
... Tools vanilla boundary-site n-fold-way parallel gg-exp1 gg-exp2 gg-exp3 grain-size make-movie FIGURE 3-2 5 Suggested data structure for Potts model simulations. FIGURE 3-2 6 Identification of boundary ... divided by N. A schematic representation of a boundary-site algorithm is shown in Figure 3-2 7. PROBLEM 3-2 4: Boundary-Site Algorithm Write a Boundary-site algorithm to simulate nor...
Ngày tải lên: 13/08/2014, 08:21
Standard Handbook of Engineering Calculations Episode 4 potx
... 600-r/min 36-tooth 1.75-in (4. 4-cm) face-width 14. 5° full-depth 6-in (15.2-cm) pitch-diameter pinion driving a 150-tooth 1.75-in (4. 4-cm) face width 14. 5° full-depth 25-in (63.5-cm) pitch-diameter gear ... = 1728.15 in 4 (71,931.0 cm 4 ). For the 36-in (91 . 4- cm) gear, I i = 36 4 /35.997 = 46 ,659.7 in 4 /in (7 64, 615.5 cm 4 /cm) of length. With a 3-in (7.6-cm) face width, I...
Ngày tải lên: 12/08/2014, 07:22
Engineering Mathematics 4 Episode 4 potx
... 1 or n P r = n! .n − r /! Thus, 4 P 2 D 4 3 D 12 or 4 P 2 D 4! 4 2! D 4! 2! D 4 ð3 ð2 2 D 12 Problem 19. Evaluate: (a) 7 C 4 (b) 10 C 6 (a) 7 C 4 D 7! 4! 7 4 ! D 7! 4! 3! D 7 ð6 ð5 4 ð3 ð2 4 ð3 ð23 ð2 D ... 1.92e 5.76 5 3 sin 1 D 46 3.7 Thus, r 3 D 3 19.35 46 3.7 D 3C 0. 042 D 3. 042 D 3. 04, correct to 3 significant figure Similarly, r 3 D 3. 042 f3. 042 ...
Ngày tải lên: 13/08/2014, 08:21
ADVANCED THERMODYNAMICS ENGINEERING phần 4 potx
... V-0-X-Y and availability stream availability at state 1 (h 1 – h 0 – To (s 1 – s 0 )) is given by area B-E-0-V+V-0-X-Y and at state 2 by area (E-F-0-V+V-0-A-Q) thus, the area E-F-C-B-+Q-A-X-Y ... (w 2 h v2 + h a2 ) - (w 1 h v1 + h a1 ) - (w 2 - w 1) h f5 )/(h f3 - h f4 ) = ((0.025×2565.3+35 )-( 0.005× 2538.1+20) – (0.02)×1 04. 9)/(188 .45 - 1 04. 9) = 0.7 9...
Ngày tải lên: 08/08/2014, 15:21