Mechanics Analysis 2010 Part 2 pdf
Mechanics Analysis 2010 Part 2 pdf
...
(2. 14)’ (2. 18), (2. 24X2 .26 )
and introducing shear strain
y
as
the
difference between angles
MI
L1
NI
and
MLN,
i.e., as
x
y= m
2
we can write Eq.
(2. 23)
in the following form
(2. 26) ... Russian).
38
Mechanics and analysis
of’
composite materials
where
(2. 22)
can be treated as linear strain-displacement equations. Taking
1,
=
I,
I,
=
I,
=
0
in...
Mechanics Analysis 2010 Part 1 pdf
...
of
Solids
29
2. 1.
2. 2.
2. 3.
2. 4.
2. 5.
2. 6.
2. 7.
2. 8.
2. 9.
2. 10.
2. 11.
2. 11.1.
2. 1 1 .2.
2. 11.3.
2. 12.
Stresses 29
Equilibrium Equations 30
Stress Transformation 32
Principal ...
2. 2 27 0
2. 7-3.0
130
27 50
26 70
24 40
22 20
17300
22 50
25 60
25 50
26 70
1 720 0
21 60
3500
350
3
IO
910
740
24 0
3
50
890
28 60
150
24 0
190
22 0...
david roylance mechanics of materials Part 2 pdf
... ($/kg)
E-glass 72. 4 2. 4 2. 6 2. 54 28 .5 0.95 1.1
S-glass 85.5 4.5 2. 0 2. 49 34.3 1.8 22 –33
aramid 124 3.6 2. 3 1.45 86 2. 5 22 –33
boron 400 3.5 1.0 2. 45 163 1.43 330–440
HS graphite 25 3 4.5 1.1 1.80 140 2. 5 66–110
HM ... constant dependent on the type of lattice (2 for NaCl).
Use this to obtain the relation
K
V
0
=
d
2
U
dV
2
V =V
0
=
1
9c
2
N
2
r
2
·
d
dr...
Ship Hydrostatics and Stability 2010 Part 2 pdf
... 83074
Draught
T
m
3
4
5
6
7
8
9
Displacement
volume
V
m
3
9 029
126 32
16404
20 257
24 199
28 270
324 04
Waterplane
area
AWL
m
2
3540.8
3694 .2
3805 .2
3898.7
3988.6
4095.8
424 0.4
CB
CWL CM Cp
0.505 0.594 0.890 0.568
0.915
0.931
0.943
0.951
0.957
0.9 62
Definitions, ... pattern. We can still show that the sum of
Po
7 /2
B /2
Figure 2. 2 Zoom of Figure 2. 1
30
Ship^Hydrosta...
Polyme Analysis 2010 Part 1 pdf
... and
complex morphological systems
⇒ analysis of polymer ≠ the small organic materials
⇒ Focus on viscoelasticproperties, dynamic mechanical testing.
Polymer analysis
üThe most important factor ... advantageous, particularly in the case of
tests running for a long time (creep tests)
Tests for Producing Design Data
TRƯỜNG ĐẠI HỌC BÁCH KHOA ĐÀNẴNG
KHOA HOÁ
PHÂN TÍCH POLYME
(POLYMER ANA...
Polyme Analysis 2010 Part 2 docx
... w1 h1" alt=""
Specimen Size:
üThe most common specimen for ISO 527 is the ISO 3167 Type 1A
multipurpose specimen.
üASTM D8 82 uses strips cut from thin sheet or film.
*The multipurpose test ... failure.
üFor ASTM D638, the test
speed is determined by the
material specification.
üFor ISO 527 the test speed
is typically 5 or 50mm/min for
measuring strength and
elongation
+and 1mm/min ....
Polyme Analysis 2010 Part 13 pdf
... beams
*Potassium Bromide disk
-A very small amount of the solid (approximately 1 -2 mg) is added to pure
potassium bromide powder (KBr, 20 0 mg) and ground up as fine as possible.
-This is then placed in ... chloride
circular plates to produce a thin film.
-The plates are then placed in a holder ready for analysis.
3. Thin Films
-Placing a sample in a suitable holder, such as a card wi...
Mechanics Analysis 2010 Part 5 ppt
...
4.17
150
Mechanics
and
analysis
of
composite materials
where the stiffness coefficients are
(4.71)
(4. 72)
where
,
E 12= E1~ 12+ 2G 12,
C=COS~,
s=sin4
.
El
.2
1
-
VI2V21
E1 .2
=
Dependence ... (4 .27 )
and
(4.61), (4. 62) , (4.63)
yield
1
I
1
1
El
=
alol
+
d1o2
+
no"-!
[i(biioi +cizo2)
+-(diio:+2enoioz
+e2141
,
E ~ = ~ I C T ~ + ~ ~ Q I
+no"...
Mechanics Analysis 2010 Part 6 potx
...
2( 6,lhl
+
cx2h2)
=
6,
2( q,lh,
+
qv2h2)
=
0
,
where
A,
=
hl/h,
h2
=
hz/h,
h
=
2( hl
+
h2)
.
Constitutive equations are
011 .2
=
El ,2( Ex
+
V 12. 21&y),
cy1 .2
=
E2,, ... and analysis
of
composite materials
where
EXi
=
Ex3
=
E1
KX2
=
E2, Ezi
=
E2, GXzi
=
Gxz3
=
G131 Gxz2
=
G23,
vx2i
=
vxz3
=
VI31
v ,2
=
v23
and
El,
E2, G13, G231...
Mechanics Analysis 2010 Part 8 ppt
... Fig. 5 .20 ). Then,
Eqs. (5 .28 ) yield
BII
=
I/?
=
21 .2 GPa mm,
B 22
=
1;;)
=
35.6 GPamm,
CII
=Zi:)
=
10.1
GPamm2,
C 22
=
Z;:)
=
27 .4 GPamm2,
0 12
=
1;;’
=
5.9 GPamm3,
B 12
=
1:;)
= ...
C 12
=Z[i)
=
3.3
GPamm’,
022
=I;;)
=
94 GPamm3
,
and in accordance with
Eqs.
(5.78) for
R
=
100
mm,
BI~
=
7.7 GPa mm,
E 12
=
3 .2
GPa
mm2,
822
=
35.3...
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