Mechanical Engineers Reference Book 12 Part 2 pptx

Mechanical Engineers Reference Book 12 Part 2 pptx

Mechanical Engineers Reference Book 12 Part 2 pptx

... and V2 = E2. Therefore (2. 89) 2~ ifN1@ v2 El = __ = 4.44 fN@ Similarly, for the secondary side, E2 = 4.44 fN2@ (2. 92) 2. 2. 32 Transformer losses Equations (2. 89) and (2. 90) ... can be represented using 8-bit codes as shown below: 64 32 16 8 4 2 1 bit number 7 6 5 4 3 2 1 0 27 26 25 24 23 22 21 20 Most significant bit WSBI Least sign...

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Mechanical Engineers Reference Book 12 Part 1 potx

Mechanical Engineers Reference Book 12 Part 1 potx

... bh3 1 12 2r sin a r4 1 3a 4 x = -__ I,, = - (a - sin’.) r4 1 4 I,, = - (a + 2 sin's) I,, = m(b2 + c2) 1 12 I,, = m(c2 + a2) / 12 Izz = m(a2 + b2) 1 12 Circular ... 0 .2 0.4 0.6 0.8 1.0 1 .2 1.4 1.6 1.8 2. 0 2. 2 2. 4 2. 6 2. 8 3.0 3 .2 3.4 3.6 3.8 4.0 0 0.1585 0.3108 0.4515 0.5763 0.6 827 0.7699 0.8586 0....

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Mechanical Engineers Reference Book 12 Part 4 docx

Mechanical Engineers Reference Book 12 Part 4 docx

... 120 (SCA) 121 (SCB) 122 (SCF) 125 (CE) 126 140 141 1 42 Number Cable screen 1 7 Transmitted data 2 Received data 3 5 Data set ready 6 Connect data set to IineiData terminal 20 ... whereas 4/30 Computers and their application 12 3 4 5 6 7 89 101 1 121 3 0000000000000 000000000000 14 15 16 17 18 19 20 21 22 23 24 25 (Plug face) Figure 4....

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Mechanical Engineers Reference Book 12 Part 5 pot

Mechanical Engineers Reference Book 12 Part 5 pot

... -28 I 0 p' 125 0 1600 I - I - 1 - ! - !-3901 -22 01 - !-1101 - I -30 I 0 +I t: 20 00 25 00 - - - - /-480+360] - I-1301 - 1-34 I 0 25 00 3150 - - - - - 520 -29 0 ... 7/10 7.3 .21 Cast iron: general 7/ 52 7.3 .22 Grey cast iron 7/ 52 7.3 .23 Nodular graphite (‘SG’) iron 7/ 52 7.3 .24 Malleable iron 7/54 7.3 .25 Austenitic cast irons...

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Mechanical Engineers Reference Book 12 Part 8 pps

Mechanical Engineers Reference Book 12 Part 8 pps

... (Yo) 20 100 20 0 300 400 500 600 0.1 26 5 25 4 24 0 170 150 130 115 0 .2 270 25 9 23 5 1 92 177 155 135 0.5 27 2 26 1 23 5 24 0 22 0 185 158 1.0 28 6 26 9 21 1 27 5 26 0 20 5 161 The 0 .2% proof ... we have: (a) 4Mb = Wl (b) 2M, = Wl (c) (d) (e) (f) 2M, + 4Mb = 3Wl 2Mb + 2M, = wl 2Mb f 2M, = 2w1 4Mc + 2Mb = 3Wl W Figure...

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Mechanical Engineers Reference Book 12 Part 9 ppsx

Mechanical Engineers Reference Book 12 Part 9 ppsx

... 500-850 25 C500 140 -25 0 80- 140 30-80 15 VG 22 32 46 68 100 150 22 0 32 VG 46 68 100 150 22 0 320 460 68 VG 100 150 22 0 320 360 680 1000 150 VG 22 0 320 460 680 ... White-metal (Pb base) 1& ;20 7 120 160 White-metal (Sn bas:) 27 - 32 7-14 120 160 Aluminium-tin 30-60 16 160 20 0 Copper-lead 45-50 10 I90 300 Lead-bron...

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Mechanical Engineers Reference Book 12 Part 11 ppsx

Mechanical Engineers Reference Book 12 Part 11 ppsx

... 80 93 116 82 120 SIT Hvop at bp (alf) mass ("C) (kJ kg-') 427 29 2 14.9 400 (4*) 27 9 14.5 25 5 20 7 14.7 24 7 177 14.5 24 5 14 .2 300 13.9 13.9 12. 1 12. 5 a Not measurable ... 1 .24 4.40 3.06 10.31 9.00 23 .75 16.60 - 0.89 3.09 2. 22 7. 32 6.50 17.37 12. 70 53.30 Y z A 20 50 50 90 75 I25 E 125 20 0 C 20 8 40...

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Mechanical Engineers Reference Book 12 Part 14 doc

Mechanical Engineers Reference Book 12 Part 14 doc

... 5. -= v2 (2) the cube of fan size 2 Total pressure and static pressure are 6. 3= (2) directly proportional to the square of p2 fan size 5 PW 4, = I = p2 w2 p2 for a given ... conipressiblea . ,3 s-1 27 ra(Ps - Pa) Q= c3 c3 (ps + Pa) q = - . (1 + 1.5~~) I 0 c q=-’- 7; Axial bush 12s 24 9 Pa Radial bush . ., c3 12s 4= 27 ra(Ps - P...

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Mechanical Engineers Reference Book 12 Part 15 ppsx

Mechanical Engineers Reference Book 12 Part 15 ppsx

... higher Figure 16 .29 Push-bench process 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 42 43 44 45 46 Methods for Simplified Testing of ... ventilation systems). The rating of a noise under investigation 120 110 100 50 40 30 20 10 625 125 25 0 500 1000 20 00 4000 8000 Mid-frequency of octave band (Hz) Fi...

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