Aircraft Structures 1 2011 Part 9 doc

... from Eqs (i), (ii) and (iii) in Eq. (9. 69) we have 2Ak = [ 61 25 x 1. 15 ~1 dsl + 2( 312 .5 - 4.02s2)2.5ds2 200 1 + jy 2( 1 1 1. 5 + 12 .54 1. 5 ds3 Evaluation of Eq. (iv) gives ... +420 600 10 6 x IO6 22.6 4 +228 600 31 x lo6 12 .3 5 + 25 620 0.4 x lo6 1. 3 6 -204 640 27 x 10 6 -11 .0 7 - 396 640 10 0 x 10 6 - 21. 4 8 -502 8 50 214...

Ngày tải lên: 12/08/2014, 03:20

... d2pB.f 13 ~ 213 DC 4000 80 000 PB,f13 11 3 pDsf 1 32 013 320 PD,f 1 32 013 320 1 48 013 240 BA 4000 60 000 2pB,f/3 213 pD,f 0 0 0 0 FC 4000 10 0 000 0 0 C = 12 68 C = ... CB 800 20 86.6 + R/2 11 2 17 32 + 10 R 87.6 -1. 8 BD 800J3 30 -J3R/2 -J3/3/2 20J3R CD 800 20 R 1 40R 2 .1 AD 800 20 RI2 11 2 IOR 1 .o C = -268 + 12 9. 2R...

Ngày tải lên: 12/08/2014, 03:20

... New York, 19 53. McGraw-Hill Book Company, New York, 19 59. Company, New York, 19 61. P.5 .1 Ans. a,,,,, = f600N/mm2, = f300N/mm2. P.5.2 For the plate and loading of problem P.5 .1 find the ... 03 4 2 $PCRTnZA: U + V = -En A, - - n =1 41 n =1 413 (6. 51) Assigning a stationary value to the total potential energy of Eq. (6. 51) with respect to each coeff...

Ngày tải lên: 12/08/2014, 03:20

... described in Chapter 9. Ans. (a) 3. 09 x 10 4N, (b) 1. 78 x 10 4N, 1. 19 x 10 4N. P.6.22 A simply supported beam has a span of 2.4m and carries a central concentrated load of 10 kN. The flanges ... (6 .11 7), (6 .11 8) and (6 .11 9) for q, FT and FB at = td 2w sin 2a (1 -$tan@) 1 tan@ FT=-[z+?( W )] d cos @ 1 - -tan@ FB=-[z-F( W )] d cos...

Ngày tải lên: 12/08/2014, 03:20

... between the curves, i.e. only 1 in 10 00 falls outside, they represent the 99 .9% confidence limits. If 99 .99 999 % of results lie between the curves only 1 in lo7 results will fall outside ... 8000 i x 1. 223 x 602 x 14 .5 N = 1. 113 L ipV2S cL= From Fig. 8 .10 (a), a = 13 .75" and CM,cG = 0.075. The tail arm I, from Fig. 8 .10 (b), is 1 =4 .18 co...

Ngày tải lên: 12/08/2014, 03:20

... panel 21 is qZl. Then from symmetry and using the results of Table 10 .3 49 8 = 49 IO = ql6 1 = q2 1 q32 = qS7 ‘?loll = q1 516 = 30.3 + q 21 q43 = q76 = 411 12 = q1 415 ... 0 = 8 .14 x lop9 t 2 .1 mm 2 .1 mm 1. 2mm 1 11 11 .2 mm Fig. P .9. 21 P .9. 22 A single cell, thin-walled beam with the double trapezoidal cross-section s...

Ngày tải lên: 12/08/2014, 03:20

... potential energy 68, 71, 73-6, 14 4 -9, gradient 10 7 -9 86 -9 16 5 -9 of a thin plate 14 7, 17 0 Twist and warping of a closed section beam 303, 304, 3 09 -15 Unit load method 68, 10 0-2, 342-4,404, ... complete diagonal tension 18 9- 94 diagonal tension factor 19 4 effect of taper 19 6 incomplete diagonal tension 19 4-6 loading (buckling stress) ratio 19 5 Titani...

Ngày tải lên: 12/08/2014, 03:20

... exercise should be daily part of school. Others think that the entire day should be spent on academics. I agree with the former and believe that physical education should be a part of every school ... they know what their children are thinking, they should listen TOEFL Outlines ( 1 – 50 ) TOEFL question # 41: You have been told that dormitory rooms at your university must be shar...

Ngày tải lên: 15/12/2013, 12:15

... was funded, in part, by the National Natural Science Fund of China (10 90 40 39, 10 525 416 , 10 99 010 1, and 91 0 210 14), Key Project Sponsored by the National Education Ministry of China (10 8058), Research ... Er 3+ AMP 1 AMP 2 50Ω PD FBG 3 Cir 3 IF 2 EDFA 2 EDFA 1 Attn 1 Attn 2 BS IF 1 Cir 1 Cir 2 FBG 1 FBG 2 PC PBS 99 % Bias 10 V out 10 Er 3+ LD Er 3+ Er 3+ AMP...

Ngày tải lên: 19/06/2014, 21:20

... Shepherd & Lapple, 19 39; Lapple, 19 51; Barth, 19 56; Tengbergen, 19 65; Sproul, 19 70; Leith & Licht, 19 72; Blachman & Lippmann, 19 74; Dietz, 19 81 and Saltzmann, 19 84) to predict the ... Computational Fluid Dynamics 254 Shepperd and Lapple ( 19 39) , Casal and Martinez ( 19 83), Dirgo ( 19 88), Coker ( 19 93 ), as well as with CFD predictions using the k-ε...

Ngày tải lên: 21/06/2014, 18:20