Aircraft Structures 1 2011 Part 6 ppt

... in Example 6 .1 and are listed below A = 60 0mm2 Zxx = 1. 17 x 10 6mm4 J = 800mm4 = 0 .67 x 10 6mm4 I? = 2488 x 10 6mm6 Zo = 5.32 x 10 6mm4 Problems 203 Fig. P .6 .14 If the ... 0 (6 .11 8) Taking moments about B wz - FTd COS @ + $gttd2 Cos2 a = 0 (6 .1 19) Solving Eqs (6 .11 7), (6 .11 8) and (6 .11 9) for q, FT and FB a...

Ngày tải lên: 12/08/2014, 03:20

... Table 10 .3 49 8 = 49 IO = ql6 1 = q2 1 q32 = qS7 ‘?loll = q1 5 16 = 30.3 + q 21 q43 = q 76 = 411 12 = q1 415 = 53.5 + 9 21 q54 = 965 = 912 13 = q13 14 = 66 .0 ... :) + 0.8 X 14 9 .6 ( ;;) 2+- 6 6 B1 = loo+ i.e. Oa8 14 9 .6 ( 2+- ;if::) x 2 = 2 16 .6mm2 6 B1 = 10 0 + Similarly B2 = 2 16 .6mm2, B3 = 2...

Ngày tải lên: 12/08/2014, 03:20

... 4000 -60 000 -2pB,f/3 - 213 0 0 16 0 0 FD 4000J2 -80000J2 -d2PB.f/3 - ~ 213 0 0 64 0J 213 0 CB 4000 80 000 PB,f/3 11 3 EB 4000 20 000 2PB,f 13 213 0 0 16 013 0 0 0 - 16 0J2/3 ... d2pB.f 13 ~ 213 DC 4000 80 000 PB,f13 11 3 pDsf 1 32 013 320 PD,f 1 32 013 320 1 48 013 240 BA 4000 60 000 2pB,f/3 213 pD,f 0 0 0 0 FC 4000 10 0 000...

Ngày tải lên: 12/08/2014, 03:20

... 9 .1) d4v EI.y.x - = w dz4 (6. 65) Also, the equation for the buckling of a pin-ended column about the Cx axis is (see Eq. (6 .1) ) (6. 66) 16 4 Structural instability Y+ Fig. 6 .10 ... Eq. (6. 60) and putting a12(' -4 [12 (1 - d)]'-" =a yields or, in a simplified form (6. 61 ) (6. 62) where 0 = aKnI2. The constants ,6& apos; an...

Ngày tải lên: 12/08/2014, 03:20

... 8000 i x 1. 223 x 60 2 x 14 .5 N = 1. 113 L ipV2S cL= From Fig. 8 .10 (a), a = 13 .75" and CM,cG = 0.075. The tail arm I, from Fig. 8 .10 (b), is 1 =4 .18 cos(a-2)+0.31sin(a-2) ... into Eq. (8 .12 ) we have =nW or dividing through by 4pV2S We now obtain a more accurate value for CL from Eq. (iv) 1. 35 4 .12 3 CL = 1. 113 x 0.075 = 1. 088 givin...

Ngày tải lên: 12/08/2014, 03:20

... 32.3 3 +420 60 0 10 6 x IO6 22 .6 4 +228 60 0 31 x lo6 12 .3 5 + 25 62 0 0.4 x lo6 1. 3 6 -204 64 0 27 x 10 6 -11 .0 7 -3 96 640 10 0 x 10 6 - 21. 4 8 -502 8 50 214 x IO6 -27.0 9 ... area about boom 9 (6 x 64 0 + 6 x 60 0 f2 x 62 0 + 2 x 850)J = 64 0 x 12 00 + 2 x 60 0 x 11 40 +2 x 60 0 x 960 +2 x 60 0 x 768 +2x62...

Ngày tải lên: 12/08/2014, 03:20

... volumetric strain 26 Strain energy 68 - 71, 14 2, 14 3, 16 6 in simple tension 69 Strain gauge rosette 29 Stress 3 - 16 as a tensor 5 complex stress systems 10 - 16 components at a point 4, 6 definition ... shear strain 16 , 18 , 19 strain gauge rosette 29 strains on inclined planes 21, 22 Strain 16 -32 5 86 Index Materials of aircraft construction 21 1-...

Ngày tải lên: 12/08/2014, 03:20

... 34 0 .67 65 3 319 .5 21. 0 46. 7 20% 17 .84 2803.7 23 34 0 .67 65 4 328.5 22.2 45.0 20% 17 .84 269 7.8 23 34 0 .67 65 5 333 .6 21. 6 43.4 20% 17 .84 260 6.4 23 34 0 .67 65 6 337.4 20.7 42.2 20% 17 .84 25 31. 6 35 ... 358 .1 538 ()PkPa 15 64 0 13 730 3820 366 0 (/)hkj kg 10 75 .6 3430.2 311 6. 2 3534.9 (/) x ekjkg 2 41. 9 14 39.3 11 09.8 13 45.9 (/)mkg h  84...

Ngày tải lên: 19/06/2014, 11:20

... (GHz) 0 19 2.2 -12 .7 -22 2 -27.3 223.4 -14 .6 -17 17 .9j 2.5 - 21. 8 224.2 -14 .9 -13 .6 17 j 3 -18 .1 224.8 -15 .2 -11 .4 16 j 3.5 -15 .5 225.2 -15 .5 -9.8 15 j Table 3 .1 Pole -Zero analysis ... 50.8 16 .7 16 .9 2.2 1 150 Design[2] 18 0nm-CMOS 61 7.2 8.2 70.2 9 250 Design[3] 18 0nm-BiCMOS 54 9.2 17 13 7.5 4 500 Design[4] 18 0nm-CMOS 51 30.5...

Ngày tải lên: 19/06/2014, 21:20

... Proposed Algorithms Method 1 Method 2 Fixed Threshold Method 2 k-Means 1 22 25 29 20 2 8 10 10 6 3 11 1 11 1 11 3 10 7 4 30 26 32 28 5 19 19 21 19 6 0 0 0 0 Table 1. Counting results using ... 2, (19 87), pp. 13 8 -14 1. Yuen, T. G. & Agnew, W. F. (19 95). Histological evaluation of polyesterimide-insulated gold wires in brain. Biomaterials, Vol. 16 , N...

Ngày tải lên: 21/06/2014, 19:20