Aircraft Structures 1 2011 Part 3 docx

... 16 0J2 /3 0 FB 4000J2 -20000J2 d2pB.f 13 ~ 2 13 DC 4000 80 000 PB,f 13 11 3 pDsf 1 32 0 13 32 0 PD,f 1 32 0 13 32 0 1 48 0 13 240 BA 4000 60 000 2pB,f /3 2 13 pD,f 0 0 0 0 FC 4000 10 0 ... 800J3 30 50 - J3R/2 -J3 /3/ 2 -2000 + 20J3R 48.2 CB 800 20 86.6 + R/2 11 2 17 32 + 10 R 87.6 -1. 8 BD 800J3 30 -J3R/2 -J3 /3/ 2 20J3R CD 800...

Ngày tải lên: 12/08/2014, 03:20

... thus integration of the above expression yields (5.47) 4ab 3c, 03 U+V=TC D"" EA; nz =1. 3, 5 n =1: 3, 5 ni =1, 3, 5 n =1, 3: 5 - From the principle of the stationary value of the total ... principal stresses. Ans. 13 .1 Nm/mm, 1. 9Nm/mm, a = - 31 . 7", a = +58 .3& quot;, *786N/mm2, fl 14 N/mm2. A plate 10 mm thick is subjected to bending momen...

Ngày tải lên: 12/08/2014, 03:20

... - FB) COS /3 - gttd COS' = 0 (6 .11 8) Taking moments about B wz - FTd COS @ + $gttd2 Cos2 a = 0 (6 .1 19) Solving Eqs (6 .11 7), (6 .11 8) and (6 .11 9) for q, FT ... 0.48 0. 51 0. 53 Note that a is the angle of diagonal tension measured from the spanwise axis of the Am. 1. 2mm, 13 0As/(l +0. 011 3As), 238 910 Nmm. beam, as in the usual nota...

Ngày tải lên: 12/08/2014, 03:20

... 8000 i x 1. 2 23 x 602 x 14 .5 N = 1. 1 13 L ipV2S cL= From Fig. 8 .10 (a), a = 13 .75" and CM,cG = 0.075. The tail arm I, from Fig. 8 .10 (b), is 1 =4 .18 cos(a-2)+0 .31 sin(a-2) ... into Eq. (8 .12 ) we have =nW or dividing through by 4pV2S We now obtain a more accurate value for CL from Eq. (iv) 1. 35 4 .12 3 CL = 1. 1 13 x 0.075 = 1. 0...

Ngày tải lên: 12/08/2014, 03:20

... idealization 33 3 Table 9 .1 0 Boom 0 B [mm2) 0 uz (N/mm2) 1 +660 640 278 x lo6 35 .6 2 +600 600 216 x IO6 32 .3 3 +420 600 10 6 x IO6 22.6 4 +228 600 31 x lo6 12 .3 5 + 25 ... AI2, A 23 and A34 from Eqs (i), (ii) and (iii) in Eq. (9.69) we have 2Ak = [ 61 25 x 1. 15 ~1 dsl + 2( 31 2 .5 - 4.02s2)2.5ds2 200 1 + jy 2( 1 1 1. 5...

Ngày tải lên: 12/08/2014, 03:20

... (kNm) 1 -10 0 0 .1 -0.05 -10 5 -10 1 .3 0.6 0 .3 3 -3 2 - 13 3 0 -0.05 0 6.7 -17 7 .3 0 0 .3 0 0 3 -10 0 -0 .1 -0.05 10 5 -10 1 .3 0.6 0 .3 -3 3 4 10 0 -0 .1 0.05 -10 5 10 1 .3 0.6 ... Table 10 .3 49 8 = 49 IO = ql6 1 = q2 1 q32 = qS7 ‘?loll = q1 516 = 30 .3 + q 21 q 43 = q76 = 411 12 = q1 415...

Ngày tải lên: 12/08/2014, 03:20

... planes 10 , 11 , 12 -14 tensile stress 3 Stress analysis of aircraft components 36 2- 432 cut-outs in wings and fuselages 415 -25 fuselages 37 4-80 bending 37 5, 37 6 shear 37 6-9 torsion 37 9, 38 0 ... section beams 30 7 -16 Bredt-Batho theory 30 7-9 condition for zero warping 31 5 , 31 6 displacements 30 9 -15 Neuber beams 31 6 shear flow distribution 30 7 war...

Ngày tải lên: 12/08/2014, 03:20

... Science, 35 , pp .3 21- 33 9. Sterman J. D., (19 89b). Deterministic chaos in an experimental economic system, Journal of Economic Behavior and Organization, 12 , pp .1- 28. Sterman J. D., (19 89c). ... Operational Research, 17 7, pp .10 44 -10 61. Wikner J., Towill D. R., Naim M., (19 91) . Smoothing supply chain dynamics, International Journal of Production Economics, 22, pp.2 31...

Ngày tải lên: 20/06/2014, 04:20

... Science, Vol. 6, pp. 34 3 -35 5, 2006. [2] Caine, N. (19 80). The rainfall intensity-duration control of shallow landslides and debris flows, Geografiska Annaler, Vol. 62A, pp. 23- 27, 19 80. [3] Christanto, ... parameters) 0. 03, 0.5 k AP (no. of encoded packets per AP) 36 00 R (bit-rate) 6, 11 , 12 , 24 Mbit/s T SF (superframe duration) 10 0 ms τ HO (handover time) 0.5 s P PL (packet-l...

Ngày tải lên: 21/06/2014, 23:20