Plastics Product Design Part 4 ppt

Self Organizing Maps Applications and Novel Algorithm Design Part 4 ppt

Self Organizing Maps Applications and Novel Algorithm Design Part 4 ppt

... attention 145 Self- Organization and Aggregation of Knowledge Self Organizing Maps - Applications and Novel Algorithm Design 132 Kohonen Layer (30 x 30 units) Input Layer (40 x 48 units) Grossberg ... multi-media 9 Self Organizing Maps - Applications and Novel Algorithm Design 138 0 20 40 60 80 100 120 00.511.522.533. 544 .555.566.5 Frequency...

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Handbook of Materials for Product Design Part 1 pptx

Handbook of Materials for Product Design Part 1 pptx

... xi Chapter 1. Ferrous Metals 1. 1 1. 1 Introduction 1. 1 1. 2 The Structure of Iron 1. 2 1. 3 Steelmaking 1. 6 1. 4 Carbon and Alloy Steels 1. 11 1.5 Selection of Alloy Steels 1. 29 1. 6 Selection ... – 414 0 0.38/0.43 0.75 /1. 00 – 0.80 /1. 10 0 .15 /0.25 – 414 2 0.40/0.45 0.75 /1. 00 – 0.80 /1. 10 0 .15 /0.25 – 414 5 0.43/0.48 0.75 /1. 00 – 0.80 /1. 10 0 .15 /0.25 –...

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Handbook of Materials for Product Design Part 2 pptx

Handbook of Materials for Product Design Part 2 pptx

... Canada (CSA) 2 France (NF) 3 120 0 1050 1350 20 17 20 24 21 17 5056 6063 6101 7075 1100 20 11 21 17 20 24 Alclad 20 24 20 17 20 18 20 14 Alclad 20 14 20 25 5454 5083 5356 5056 50 52 6063 6061 6053 3003 4043 6151 40 32 7075 Alclad ... X-8 F3 32. 0 333 A3 32. 0 354 355 C355 356 A356 357 A357 359 43 43 — B514.0 A514.0 21 4 22 0 Almag 35 603, Ternalloy 5 607, Ternalloy 7...

Ngày tải lên: 10/08/2014, 19:20

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Handbook of Materials for Product Design Part 4 doc

Handbook of Materials for Product Design Part 4 doc

... beam for heat; for aluminum, a shielding gas is also used. Equipment is costly. 02Kissell Page 149 Wednesday, May 23, 2001 9:52 AM 2.165 Nondirectional textured M40 M41 M42 M43 M 44 M45 M46 M47 M4X Unspecified Extra ... strength of 20 24- T4 and 6061-T6 bolts. Machine screw nuts and other styles of small nuts [1 /4 in. (6 mm) and smaller] are usually made of 20 24- T4. Flat washe...

Ngày tải lên: 10/08/2014, 19:20

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Handbook of Materials for Product Design Part 7 ppt

Handbook of Materials for Product Design Part 7 ppt

... modulus, 106 psi 0° 262.2 177 .6 7. 00 271 .5 181.3 7. 11 251.9 173 .8 6.85 219.6 181.8 6 .78 224.2 1 87. 9 6.82 216.1 170 .6 6 .75 193.2 165.0 6.95 196 .7 173 .8 7. 18 198.2 154 .7 6.80 Bearing ultimate stress, ... at 4% elong. ksi 0° 77 .3 20.5 80.9 21.5 74 .8 19.1 68.8 17. 7 71 .4 19 .7 65.3 17. 2 53.6 17. 0 54.6 18.5 52.1 15.8 Interlaminar shear ultimate stress, ksi 0°...

Ngày tải lên: 10/08/2014, 19:20

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Handbook of Materials for Product Design Part 12 ppt

Handbook of Materials for Product Design Part 12 ppt

... practice of a few coating manufacturers who add small amounts of a more expensive, better performing resin to a less expen- sive, poorer performing resin and call the product by the name of the former. ... resin type determines the performance properties of a coating, it is used most often. Table 9.6 shows the physical, environmental, and film-forming characteristics of coatings by...

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Handbook of Materials for Product Design Part 13 ppt

Handbook of Materials for Product Design Part 13 ppt

... be administered within four hours of plating, at a temperature of 200 to 230°C, for a period of from 8 to 24 hr (time depends on tensile strength). 81 In spite of efforts to eliminate hydrogen embrittlement, given ... The Substitution of IVD Aluminum for Cadmium, McDonnell Aircraft Company, P. O. Box 516, St. Louis, MO 63166 and C. J. Carpenter, Department of the Air Force, H...

Ngày tải lên: 10/08/2014, 19:20

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Handbook of Materials for Product Design Part 14 pptx

Handbook of Materials for Product Design Part 14 pptx

... 11 .14 shows correct and in- correct methods of mechanical fastening of plastic parts using this hardware. Inserts into the plastic part can be effectively used to provide the fe- male part of ... mold- ing. 11.8.2 Design for Self-Assembly It is often possible and desirable to incorporate fastening mechanisms in the design of the molded part itself. The two most common me...

Ngày tải lên: 10/08/2014, 19:20

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Modern Plastics Handbook 2011 Part 4 ppt

Modern Plastics Handbook 2011 Part 4 ppt

... 48 78 Tension set (%) 10 24 40 Tear strength, pli 73°F (23°C) 175 350 44 0 (79) (177) (227) 212°F (100°C) 52 150 220 (11) (66) (1 04) Brittle point, °F (°C) 40 Ϫ33 Ϫ31 ( 40 ) (Ϫ28) (Ϫ36) 0267 146 _Ch03_Harper ... materials are ■ Insensitivity to humidity ■ Long-term performance 4. 14 Chapter Four 0267 146 _Ch 04_ Harper 2/ 24/ 00 4: 57 PM Page 4. 14 engine mounts because NR isolates...

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Plastics Engineered Product Design Part 4 potx

Plastics Engineered Product Design Part 4 potx

... plane. 102 Plastics Engineered Product Design Impact Impact loading analysis may take the form of design against impact damage requiring an analysis under highate loading or design for acceptable ... factor limiting any particular friction force application is heat dissipation. This is true if the application of the fiction loads is 1 34 Plastics Engineered Product...

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Plastics Engineered Product Design Part 10 ppt

Plastics Engineered Product Design Part 10 ppt

... requirements for a product design, resulting in maximizing the design efficiency in meeting product requirements. The computer is able to convert a design into a fabricated product providing ... at least 15%. Under the ideal molding conditions 346 Plastics Engineered Product Design - the efficient design of a product that can be manufactured, assembled...

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Plastics Product Design Part 2 pdf

Plastics Product Design Part 2 pdf

... Polytetrafluoroethylene 116 130 175 21 5 26 0 26 0 400 330 24 0 26 6 347 41 9 500 500 755 626 The T, is dependent on the processing pressure and the time under heat, particularly during a slow ... going from the product design through production. Examples of potential cost reductions include. (1) redesign product with thinner walls to reduce production cos...

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Plastics Product Design Part 4 ppt

Plastics Product Design Part 4 ppt

... - v120,) E22 1 e, = - 6, G (2 -42 ) (2 -43 ) (2 -44 ) (2 -45 ) (2 -46 ) Substituting Eq. 2-35, 2-36, and 2-37 into 2 -44 , 2 -45 , and 2 -46 results in, e, = - (cos2 6- v12 sin2 ... = E22 1 e, = - (sin @cos 6)ol G (2 -47 ) (2 -48 ) (2 -49 ) Finally, substituting Eqs. 2 -47 , 2 -48 , and 2 -49 and 2 -41 , 2 -42 , and 2 -43 into Eqs. 2-29,2...

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Plastics Product Design Part 6 pptx

Plastics Product Design Part 6 pptx

... 2 56 171 128 102 85 64 43 288 192 144 115 96 72 48 320 213 160 128 107 80 53 384 2 56 192 154 128 96 64 4 16 277 2 06 166 139 104 69 Most failures with the slender columns occur ... 0.047 0. 062 5 0.078 0.083 0.125 0.1875 1 .o 1.5 1.75 2.0 2.25 2.5 3.0 3.25 128 85 64 51 43 32 21 192 128 96 77 64 48 32 224 149 112 90 75 56 37 2 56 171 128...

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Plastics Product Design Part 9 pptx

Plastics Product Design Part 9 pptx

... coefficients on the composite optimum design? as design variables for the multilayered-filamentary composite? composite optimum design? 334 Plastics Engineered Product Design important that the ... many different plastics have been used in designs in successful products in both fresh and the more hostile seawater. Boats have been designed and fabricated since at least t...

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