ENVIRONMENTAL ENGINEER’S MATHEMATICS HANDBOOK - CHAPTER 6 potx

... 2330 2 3 360 3 264 0 4 2755 5 2 860 6 265 0 7 2340 8 2350 9 2888 10 2330 7-Day Moving Ave. for Day 7 2330 3 360 = ++2 264 0 2755 2 860 265 0 2340 7 ++++ = 2705 mg/L 7-Day Moving Ave. for Day 8 3 360 264 0 = ++ 22755 ... 0.01 10 .6 0 .6 0. 36 9.5 –0.5 0.25 11.5 1.5 2.25 9.5 –0.5 0.25 10.0 0 0 9.4 –0 .6 0. 36 3.99 +3s+2s+sM−s−2s−3s 95. 46% 68 . 26% 99.74% s = − − ∑ (X X)2 n1 X X = 1...

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... ft 26 ft) (3.7 psi) (2.31 ft/ps=++ ii) =+1 26 ft 8.5 ft = 134.5 ft L 168 1_book.fm Page 349 Tuesday, October 5, 2004 10:51 AM © 2005 by CRC Press LLC 366 ENVIRONMENTAL ENGINEER’S MATHEMATICS HANDBOOK 15.4.5.1 ... (8.34 lb/day)) = 10 lb/day Polymer L 168 1_book.fm Page 369 Tuesday, October 5, 2004 10:51 AM © 2005 by CRC Press LLC 360 ENVIRONMENTAL ENGINEER’S MATHEMATICS HA...

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... 452 16. 6.2 Hydraulic Loading Rate 452 16. 6.3 Soluble BOD 453 16. 6.4 Organic Loading Rate 455 16. 6.5 Total Media Area 4 56 16. 6 .6 Modeling RBC Performance 4 56 16. 6.7 RBC Performance Parameter 4 56 16. 7 ... 16. 7 .6 Gould Biosolids Age 462 16. 7.7 Mean Cell Residence Time (MCRT) 463 16. 7.8 Estimating Return Rates from SBV 60 (SSV 60 ) 465 16. 7.9 Biosolids...

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... 3.14 0.01 56= ×× V 14.72 ft 2 = 24 in. 2 12 in.÷= VH r 2 =×π V96in. (12 in.) 2 =×π L 168 1_book.fm Page 61 Tuesday, October 5, 2004 10:51 AM © 2005 by CRC Press LLC 66 ENVIRONMENTAL ENGINEER’S MATHEMATICS ... (18 m)= C 56. 52 m= C6ft=×π C 3.14 6 ft=× C 18.84 ft= Area L W=× L 168 1_book.fm Page 57 Tuesday, October 5, 2004 10:51 AM © 2005 by CRC Press LLC 72 ENVIRONMENTAL ENGINEER’...

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... 10 –3 1 .65 × 10 –1 Chloroform 4.8 × 10 –3 2.0 × 10 –1 Cyclohexane 0.18 7.3 1,1-Dichloroethane 6 × 10 –3 2.4 × 10 –1 1,2-Dichloroethane 10 –3 4.1 × 10 –2 cis-1,2-Dichloroethene 3.4 × 10 –3 0.25 trans-1,2-Dichlorethene ... =   ∑ X w N 1       = 1 X Moles of n w = i L 168 1_book.fm Page 76 Tuesday, October 5, 2004 10:51 AM © 2005 by CRC Press LLC 84 ENVIRONMENTAL ENGINEER’S M...

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... version of the CTDMPLUS model. L 168 1_book.fm Page 91 Tuesday, October 5, 2004 10:51 AM © 2005 by CRC Press LLC 88 ENVIRONMENTAL ENGINEER’S MATHEMATICS HANDBOOK The problem — that of finding ... algorithms exist for all of them (e.g., L 168 1_book.fm Page 89 Tuesday, October 5, 2004 10:51 AM © 2005 by CRC Press LLC 90 ENVIRONMENTAL ENGINEER’S MATHEMATICS HANDBOOK tra...

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... 62 .4 1.94 130 61 .5 1.91 40 62 .4 1.94 140 61 .4 1.91 50 62 .4 1.94 150 61 .2 1.90 60 62 .4 1.94 160 61 .0 1.90 70 62 .3 1.94 170 60 .8 1.89 80 62 .2 1.93 180 60 .6 1.88 90 62 .1 1.93 190 60 .4 1.88 100 62 .0 ... 1.191=×× Wt of water 12 10 gal/day 8.34 lb/ga 6 =× × ll 1.0× Dosage wt of F/wt of water= = ×× × 66 .2 8.34 1.191 12 x 10 8.34 lb/gal 6 ×× 1.0 = 6. 58 10 6 =...

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... EPA45 0-2 -8 0-0 63 , February 1980. %EA %O 0.5 %CO 0. 264 %N (%O 0.5 2 – 2 – 2 – = %%CO) ()100 L 168 1_book.fm Page 162 Tuesday, October 5, 2004 10:51 AM © 2005 by CRC Press LLC 160 ENVIRONMENTAL ENGINEER’S ... math- ematics and processes. L 168 1_book.fm Page 151 Tuesday, October 5, 2004 10:51 AM © 2005 by CRC Press LLC 1 56 ENVIRONMENTAL ENGINEER’S MATHEMATICS HAN...

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... Institute (APTI), EPA45 0-2 -8 1-0 05. USEPA-81/05 (1981). Control of gaseous emissions, Course 415, USEPA Air Pollution Training Institute (APTI), EPA45 0-2 -8 1-0 06. USEPA-84/03 (1984). Wet scrubber ... (assuming all the steam is condensed) q = (66 0 lb/min)(1Btu/lb – °F)(212 – 160 )°F = 34,320 Btu/min ∆T lm = [(212 – 120) – ( 160 – 60 )]/In[(212 – 120)/( 160 – 60 )] = 96 F A...

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... air at 4 46 F 1.75 10 lb/ –5 °= × fft-sec P p 2 .65 (62 .4) 165 .4 lb/ft 3 == QQ(T/T) asas = =++70 .6( 4 46 460 )/(32 460 ) = 130 acfs η [gp (d ) / 36 )(BL/Q) pp 2 = (32.2)( 165 .4)(10.8)(15)(d ) /[( 36) (1.75 p 2 =×× ... nn)(1/44,200)(kW-min/ft-lb )(1/0.55) f ×(0. 06) ($/kWh)(1 /60 )(h/min)] 0.002 p $/min= ∆ (0.143) p/( p 5) 0.002 p∆∆ ∆+= ∆p 66 .5 lb /ft 12.8 in. H O f 2 2 == η 66 .5/ (6...

Ngày tải lên: 11/08/2014, 17:20