ENVIRONMENTAL ENGINEER’S MATHEMATICS HANDBOOK - CHAPTER 4 pptx

ENVIRONMENTAL ENGINEER’S MATHEMATICS HANDBOOK - CHAPTER 4 pptx

ENVIRONMENTAL ENGINEER’S MATHEMATICS HANDBOOK - CHAPTER 4 pptx

... Figure 4. 1a Input. Figure 4. 1b Output. L1681_book.fm Page 90 Tuesday, October 5, 20 04 10:51 AM © 2005 by CRC Press LLC 87 C HAPTER 4 Algorithms and Environmental Engineering 4. 1 ... them (e.g., L1681_book.fm Page 89 Tuesday, October 5, 20 04 10:51 AM © 2005 by CRC Press LLC 90 ENVIRONMENTAL ENGINEER’S MATHEMATICS HANDBOOK traveling salesman problem...

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ENVIRONMENTAL ENGINEER’S MATHEMATICS HANDBOOK - CHAPTER 1 docx

ENVIRONMENTAL ENGINEER’S MATHEMATICS HANDBOOK - CHAPTER 1 docx

... 141 6 .4. 3 30-Day Average Calculation 141 6 .4. 4 Moving Average 142 6 .4. 5 Geometric Mean 143 6 .4. 5.1 Logarithm (Log) Method 144 6 .4. 5.2 Nth Root Calculation Method 144 6.5 Standard Deviation 145 6.6 ... (Weir Loading Rate) 44 1 16.3 .4 Primary Sedimentation Basins 44 2 16 .4 Biosolids Pumping 44 4 16 .4. 1 Percent Total Solids (% TS) 44 4 16 .4. 2 BOD and SS Removed, Poun...

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ENVIRONMENTAL ENGINEER’S MATHEMATICS HANDBOOK - CHAPTER 2 docx

ENVIRONMENTAL ENGINEER’S MATHEMATICS HANDBOOK - CHAPTER 2 docx

... decimal: 34. 73; 34. 77; 34. 75; 34. 45; 34. 35. Solution : 34. 73 = 34. 7 34. 77 = 34. 8 34. 75 = 34. 8 34. 45 = 34. 4 34. 35 = 34. 4 Grade 140 mm 22 m 100(%)=× = × ×= 140 mm 22 1000 mm 0. 64% 100% Efficiency hp ... below. Solution: xh 20 h 4 gpm 10 gpm == x == (4) (20) 10 h8 36 180 44 50 == x (44 50)(36) 180 = x x 890= 3 .4 2 6 = x (3 .4) ( ) (2) (6)x = x = (2)(6) 3 .40...

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ENVIRONMENTAL ENGINEER’S MATHEMATICS HANDBOOK - CHAPTER 3 ppt

ENVIRONMENTAL ENGINEER’S MATHEMATICS HANDBOOK - CHAPTER 3 ppt

... 10 –1 Chloroform 4. 8 × 10 –3 2.0 × 10 –1 Cyclohexane 0.18 7.3 1,1-Dichloroethane 6 × 10 –3 2 .4 × 10 –1 1,2-Dichloroethane 10 –3 4. 1 × 10 –2 cis-1,2-Dichloroethene 3 .4 × 10 –3 0.25 trans-1,2-Dichlorethene ... of n w = i L1681_book.fm Page 76 Tuesday, October 5, 20 04 10:51 AM © 2005 by CRC Press LLC 84 ENVIRONMENTAL ENGINEER’S MATHEMATICS HANDBOOK advection will transport...

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ENVIRONMENTAL ENGINEER’S MATHEMATICS HANDBOOK - CHAPTER 5 doc

ENVIRONMENTAL ENGINEER’S MATHEMATICS HANDBOOK - CHAPTER 5 doc

... 32 62 .4 1. 94 130 61.5 1.91 40 62 .4 1. 94 140 61 .4 1.91 50 62 .4 1. 94 150 61.2 1.90 60 62 .4 1. 94 160 61.0 1.90 70 62.3 1. 94 170 60.8 1.89 80 62.2 1.93 180 60.6 1.88 90 62.1 1.93 190 60 .4 1.88 100 ... SO CaSO 2H CO 3 24 4 23 + ↔ + Ca(HCO ) H SO CaSO 2H CO 32 2 4 4 2 3 + ↔↔+ HS Cl 2HCl S 22 + ↔ +°↓ HS 4Cl 4HO HSO 8HCl 222 24 ++ → + SO H O HSO 22 23 + → HOCl H SO H SO HC...

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ENVIRONMENTAL ENGINEER’S MATHEMATICS HANDBOOK - CHAPTER 6 potx

ENVIRONMENTAL ENGINEER’S MATHEMATICS HANDBOOK - CHAPTER 6 potx

... N = +++… L(0.5 MGD) (10 mg/L) (8. 34) 41 .7 lb 1 == L(0.6 MGD) (15 mg/L) (8. 34) 75.06 lb 2 == L(0 .4 MGD) (5 mg/L) (8. 34) 16.68 lb 3 == L (41 .7 lb) 75.06 lb + 16.68 lb 3 44 .48 l 3 = = bb (C C C C ) N C 123 ... 3360 3 2 640 4 2755 5 2860 6 2650 7 2 340 8 2350 9 2888 10 2330 7-Day Moving Ave. for Day 7 2330 3360 = ++22 640 2755 2860 2650 2 340 7 ++++ = 2705 mg/L 7-Day Moving Ave. for...

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ENVIRONMENTAL ENGINEER’S MATHEMATICS HANDBOOK - CHAPTER 7 docx

ENVIRONMENTAL ENGINEER’S MATHEMATICS HANDBOOK - CHAPTER 7 docx

... Nitrogen N 2 78.0 84 780, 840 Oxygen O 2 20. 947 6 209 ,47 6 Argon Ar 0.9 34 9, 340 Carbon dioxide CO 2 0.03 14 3 14 Neon Ne 0.001818 18.18 Helium He 0.0005 24 5. 24 Methane CH 4 0.0002 2 Sulfur ... 12.0000). (3 .4 atm) (4 L) n (0.08206 L atm/mol K=××))(300 K) L1681_book.fm Page 159 Tuesday, October 5, 20 04 10:51 AM © 2005 by CRC Press LLC 1 54 ENVIRONMENTAL...

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ENVIRONMENTAL ENGINEER’S MATHEMATICS HANDBOOK - CHAPTER 8 ppt

ENVIRONMENTAL ENGINEER’S MATHEMATICS HANDBOOK - CHAPTER 8 ppt

... Institute (APTI), EPA45 0-2 -8 1-0 05. USEPA-81/05 (1981). Control of gaseous emissions, Course 41 5, USEPA Air Pollution Training Institute (APTI), EPA45 0-2 -8 1-0 06. USEPA- 84/ 03 (19 84) . Wet scrubber plan ... review, Course 5 141 2C, USEPA Air Pollution Training Institute (APTI), EPA45 0-2 -8 2-0 20. A( 34, 320 Btu/min)/[(200 Btu/ F-ft -h)(96 2 =°°°F) = 1.79 ft or 2 ft...

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ENVIRONMENTAL ENGINEER’S MATHEMATICS HANDBOOK - CHAPTER 9 docx

ENVIRONMENTAL ENGINEER’S MATHEMATICS HANDBOOK - CHAPTER 9 docx

... lb/ft-sec (USEPA- 84/ 09, p. 167) µm (1 µm = 10 –6 ) = 3. 048 × 10 5 ft (USEPA- 84/ 09, p. 183) v = 0.153g (d ) (p ) /(µ p 0.71 p 1. 14 p 0.71 0 .43 0.29 )) 0.153(32.2) [ (40 0)/(25 ,40 0)(12)] ( 0.71 1. 14 = ... /36µ)(BL/Q) pp 2 = Viscosity of air at 44 6 F 1.75 10 lb/ –5 °= × fft-sec P p 2.65(62 .4) 165 .4 lb/ft 3 == QQ(T/T) asas = =++70.6 (44 6 46 0)/(32 46 0) = 130 acfs η [gp (d )...

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ENVIRONMENTAL ENGINEER’S MATHEMATICS HANDBOOK - CHAPTER 12 docx

ENVIRONMENTAL ENGINEER’S MATHEMATICS HANDBOOK - CHAPTER 12 docx

... mi/ 640 acres = 0.7969 sq. mi Step 3. Compute mean depth: V =++× ∑ ++ h/3(A A A A ) i=0 n ii1 i i1 =++×++1/3[(510 46 0 510 46 0) (46 0 42 0 ++× +++ × + 46 0 42 0) (42 0 332 42 0 332) ((332 2 74 332 ... mi L = ×23 14. 8.60 mi 3.16 = 2.72 D V A = 22 74 acre-ft 510 acres = 4. 46 ft L1681_book.fm Page 309 Tuesday, October 5, 20 04 10:51 AM © 2005 by CRC Press LLC 306 ENVI...

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