Mechanical Engineer''''''''s Reference Book 2011 Part 2 doc

Mechanical Engineer''''s Reference Book 2011 Part 2 doc

Mechanical Engineer''''s Reference Book 2011 Part 2 doc

... and V2 = E2. Therefore (2. 89) 2~ ifN1@ v2 El = __ = 4.44 fN@ Similarly, for the secondary side, E2 = 4.44 fN2@ (2. 92) 2. 2. 32 Transformer losses Equations (2. 89) and (2. 90) ... can be represented using 8-bit codes as shown below: 64 32 16 8 4 2 1 bit number 7 6 5 4 3 2 1 0 27 26 25 24 23 22 21 20 Most significant bit WSBI Least sign...

Ngày tải lên: 11/08/2014, 15:20

70 210 0
Mechanical Engineer''''s Reference Book 2011 Part 14 doc

Mechanical Engineer''''s Reference Book 2011 Part 14 doc

... screed and 20 mm wood flooring 1.5 0.35 6.1-6.7 0.38 1.9 -2. 0 0.8 0.4 3.5 0.9 1.54 0 .29 0.96 5.3-5.7 0.37 0.4 3.3 1.7 1.9 1.4 0.5 1.0-1.1 0.5 0. 62 4.3 5.6 2. 5 3 .2 2. 0 6.6 ... 601-750 75 1-900 90 1-1000 1001-1500 1501 -20 00 Iron 0.100 0.050 0.030 0. 025 0. 020 0. 020 0.010 0.010 @Pm Fe) Copper 0.050 0. 025 0. 020 0. 020 0.015 0.01...

Ngày tải lên: 11/08/2014, 15:20

70 262 0
Mechanical Engineer''''s Reference Book 2011 Part 1 potx

Mechanical Engineer''''s Reference Book 2011 Part 1 potx

... 2M,, SM, and 2Mz. Then for equilibrium the following conditions must hold: 2Fx =2Fy =2Fz =O (1.1) ZMx = 2My = ZMz = 0 (1 .2) If th’e conditions in equations (1.1) and (1 .2) ... For a V-notch of included angle 28 : = 2. 36Cd(tan 0)H' (1. 62) For a 90" notch: $' = 2. 36C,H2' (1.63) V = 2. 953Cd(B - 0.2H) el5 - id)'I (1.65) o...

Ngày tải lên: 11/08/2014, 15:20

70 269 0
Mechanical Engineer''''s Reference Book 2011 Part 3 ppsx

Mechanical Engineer''''s Reference Book 2011 Part 3 ppsx

... Rhodium - iridiudrhodium 0 -20 00 6 mV at 120 0°C tungsten - 5% rhenium/ tungsten - 26 % rhenium 0 -23 00 9 mV at 500°C tungsten/molybdenum 125 0 -26 00 5 mV at 20 00°C 1 ai cn 0 > ... 105-1 02 10 A Simple, robust io5-10 5 B Good general-purpose lo5-lo2 5-10 A Simple, direct reading 105-10-3 5-10 C Wide range. Used for 103-10 -2 10 -20 C...

Ngày tải lên: 11/08/2014, 15:20

70 316 0
Mechanical Engineer''''s Reference Book 2011 Part 4 pot

Mechanical Engineer''''s Reference Book 2011 Part 4 pot

... V .24 , which defines the in- terchange circuits and their functionality. Thus V .24 can be considered a subset of the full RS232C standard. In Europe the other components of RS232C are ... V .28 for the electrical characteristics and IS0 21 10 for the pin connector allocations. The terms RS232C and V .24 are often interchanged, and for practical purposes an Disk storage 4...

Ngày tải lên: 11/08/2014, 15:20

70 247 0
Mechanical Engineer''''s Reference Book 2011 Part 5 pot

Mechanical Engineer''''s Reference Book 2011 Part 5 pot

... 160 180 180 20 0 20 0 22 5 22 8 28 0 25 0 28 0 28 0 315 315 355 355 400 IM) 450 450 500 Grade 500 560 560 630 630 710 710 800 800 900 900 loo0 1m 1 120 1 120 125 0 1750 1400 ... 1 120 125 0 1750 1400 1400 1M 1M 1800 1600 2WO 2m 22 40 22 40 25 00 28 00 28 00 28 00 3150 Table 6.3 Furrdornenrol 1 9; S7 ~ 5” 2 5 3 p 5 E 1: .$ /i...

Ngày tải lên: 11/08/2014, 15:20

70 327 0
Mechanical Engineer''''s Reference Book 2011 Part 6 pps

Mechanical Engineer''''s Reference Book 2011 Part 6 pps

... LM6) give dark films 20 14C-T4, 20 24C-T4 Group 2 LMCM, LM2-M 6060-T6, 6061-T6, LM16-TF, LM13-M 6065-T6, 60 82- T6, LM21-M, LM 22- TB, LM24-M 6463-T6 LM27-M, LM31-M LM2O-M Weathers as above ... C101, C1 02, C104 C1 02, C104, CZ107, CZ 121 , CZ 12. 5, NS101. NS1 02, NS111, NS1 12 C101, C1 02. C104 PB1 02, CA103 cz 121 C101. C1 02. C104, C106 C106, C107 (21 04, C107. CZ10...

Ngày tải lên: 11/08/2014, 15:20

70 393 0
Mechanical Engineer''''s Reference Book 2011 Part 7 ppt

Mechanical Engineer''''s Reference Book 2011 Part 7 ppt

... index 2 Flammability - 120 0 .24 99 >lo16 155 -20 0 2. 1 2. 05 0.00 02 0.00 024 .00004 >300 - - 0.36 60-80 >io13 2. 35 70 0 .20 85-189 2 x 10'6 120 -160 2. 1 2. 1 0.00 02 ... 0.95 1.70 2. 01 2. 63 0.44 0.75 6.44 3.50 0 .25 0 .22 9.8 6.5 6 15 18 18 12 60 0.8 1.4 3.4 3 2. 6 9 6 2. 4 0.35 0.9 27 3.1 2. 5 2. 5 2....

Ngày tải lên: 11/08/2014, 15:20

70 317 0
Mechanical Engineer''''s Reference Book 2011 Part 8 potx

Mechanical Engineer''''s Reference Book 2011 Part 8 potx

... we have: (a) 4Mb = Wl (b) 2M, = Wl (c) (d) (e) (f) 2M, + 4Mb = 3Wl 2Mb + 2M, = wl 2Mb f 2M, = 2w1 4Mc + 2Mb = 3Wl W Figure 8 .23 Rectangular portal frame These ... From equilibrium, uxx -I a,, ax - a’ a.9 = + sin20 -I rxy sin26 (8.3) rO = rxy cos28 - sin26 (8.4) 2 2 a, - a 2 Equations (8.3) and (8.4) describe the stresse...

Ngày tải lên: 11/08/2014, 15:20

70 342 0
Mechanical Engineer''''s Reference Book 2011 Part 9 pptx

Mechanical Engineer''''s Reference Book 2011 Part 9 pptx

... (100) to 140 (140) to 20 0 (20 0) to 28 0 - - - - - - 40 (40 to 100 40 (40) to 100 (100) to 140 (140) to 20 0 (20 0) to 400 - - - (50) to 140 (140) to 20 0 20 0 - - - 40 (40) ... OOG25 000 20 0000 Pulp and papermaking industry 100 000 300000 Power station plant, mine pumps and mine ventilator fans t 40_F -20 0000 20 0000 20 000 300000 30000...

Ngày tải lên: 11/08/2014, 15:20

70 341 0
w