Mechanical Engineering Systems 2008 Part 10 doc
Mechanical Engineering Systems 2008 Part 10 doc
... of linear expansion for steel is 12 × 10 –6 per °C and the modulus of elasticity of the steel is 200 GPa. = ␣E = 12 × 10 –6 × 1 × 200 × 10 9 = 2.4 × 10 6 Pa = 2.4 MPa Example 5.3.8 A steel ... B A B 1.5 × 10 6 = 14.3 c × 1963 × 10 –6 + c × 200 537 × 10 –6 Hence the stress on the concrete is 6.56 MPa and that on the steel is 93.8 MPa. Example 5.3.6 A rod is formed with on...
Ngày tải lên: 11/08/2014, 15:20
Mechanical Engineering Systems 2008 Part 8 docx
... the idea of mechanical efficiency to represent how close a piece of mechanical equipment is to being ideal in energy terms. Mechanical efficiency = (useful energy out/energy in) × 100 % Machines ... nozzle if the jet velocity is 10 times the velocity of the water in the main part of the hose. (41) A jet of water, of cross-section area 0.01 m 2 and discharge rate 100 kg/s, is direc...
Ngày tải lên: 11/08/2014, 15:20
Mechanical Engineering Systems 2008 Part 1 pdf
... called measures. In French this is Mechanical Engineering Systems Richard Gentle Peter Edwards Bill Bolton OXFORD AUCKLAND BOSTON JOHANNESBURG MELBOURNE NEW DELHI 10 Thermodynamics The specific heats ... defines the ‘system’, the 2 Thermodynamics Summary Thermodynamics is an essential part of the study of mechanical engineering. It involves knowledge basic to the functioning of p...
Ngày tải lên: 11/08/2014, 15:20
Mechanical Engineering Systems 2008 Part 3 pptx
... × 0.09 2 4 × 0.11 × 3700 120 × 6 = 101 .2 kW bp = T. = 0.204 × 3700 × 2 60 =79kW m = bp ip = 79 101 .2 = 0.781 = 78.1% b = bp kg fuel/s × CV = 79 26 3600 × 42 × 10 3 = 0.26 = 26% Brake specific ... P mi = area of diagram length of diagram × spring rate = 400 50 × 1 × 10 5 =8 × 10 5 N/m 2 Indicated power = P mi A.L.n =8 × 10 5 × × 0.25 2 4 × 0.25 × 6 2 = 29 452 W per cylinder...
Ngày tải lên: 11/08/2014, 15:20
Mechanical Engineering Systems 2008 Part 4 potx
... throttle was 10 kg. After the throttle, the pressure of the steam was 1 bar and the temperature 150°C. Find the dryness fraction of the steam sample. Dryness from separator = m 1 m 1 + m 2 = 10 10 + ... x.h fg = 561 + (0.8 × 2164) = 2292.2 kJ/kg h 2 = h f + x.h fg = 417 + (0.3 × 2258) = 109 4 kJ/kg Q = 1(2292.2 – 109 4) = 1198.2 kJ/kg If the mass flow rate of steam through the heater is...
Ngày tải lên: 11/08/2014, 15:20
Mechanical Engineering Systems 2008 Part 5 pps
... superheat = 210. 63 kJ/kg Compressor work = 210. 63 – 184.03 = 26.6 kJ/kg (b) COP = h 1 – h 4 h 2 – h 1 = 124.33 26.6 = 4.67 (c) Carnot COP ref = T L T L – T H = ( 10 + 273) (45 + 273) – (– 10 + 273) = ... Figures 2.7.13 and 2.7.14. Thermodynamics 101 (8) An ammonia refrigeration plant operates between 2.265 bar and 10. 34 bar. The ammonia leaves the evaporator at 10 C and leaves the co...
Ngày tải lên: 11/08/2014, 15:20
Mechanical Engineering Systems 2008 Part 6 pdf
... Density kg/m 3 Relative density RD Dynamic viscosity Pa s or kg/m/s Air 1.3 1.3 × 10 –3 1.85 × 10 –5 Water 100 0 1 0.001 Mercury 13 600 13.6 1.55 × 10 –3 Mineral oil 900 0.9 8 × 10 –4 Hydrostatic forces on curved surfaces In the ... exposure record of what the particle does. In streamlined flow we would see that the particle followed exactly the line of flow of the liquid, as in...
Ngày tải lên: 11/08/2014, 15:20
Mechanical Engineering Systems 2008 Part 7 pptx
... section of the pipe. ⍀ 1 =8 × 10 × 0.15/(0.0025 4 ) = 9.778 × 10 10 Pa s/m 3 ⍀ 1 =8 × 8 × 0.15/(0.0015 4 ) = 60.361 × 10 10 Pa s/m 3 Total resistance = 70.139 × 10 10 Pa s/m 3 The flow rate is ... Carburettor 0.025 0.020 0.015 0. 010 0.009 0.008 0.007 0.006 0.005 0.004 0.003 0.002 Friction factor Re y nolds number Turbulent flow Turbulent flow Smooth pipes Smooth pipes 10 3 23456...
Ngày tải lên: 11/08/2014, 15:20
Mechanical Engineering Systems 2008 Part 11 pptx
... of linear expansion of 12 × 10 –6 /°C. The force compressing the copper and extending the steel is: F = (␣ A – ␣ B ) 1 E A A A + 1 E B A B = (20 – 12) × 10 –6 × 100 1 100 × 10 9 × 1 4 (0.060 2 – ... (10 × 50 3 )/12 = 0 .104 × 10 6 mm 4 . Each of the outer rectangular areas will have a second moment of area given by the theorem of parallel axes as I h = I + Ah 2 = (50 × 10...
Ngày tải lên: 11/08/2014, 15:20
Mechanical Engineering Systems 2008 Part 13 pps
... transfer: between fluids 102 during process 30 through composite wall 103 through multi-layer pipe lagging 107 108 through pipe lagging 107 through a plane wall 101 Heat transfer coefficient 102 , 103 Hooke’s ... mm 20. 165.5 mm 21. 11.7 × 10 6 mm 4 , 2.2 × 10 6 mm 4 22. 158 mm 23. d/4 24. (a) 71 mm, 74.1 × 10 6 mm 4 , (b) 47.5 mm, 55.3 × 10 4 mm 4 25. 247.3 × 10 6 mm 4...
Ngày tải lên: 11/08/2014, 15:20