Mechanical Engineering Systems 2008 Part 1 pdf

Mechanical Engineering Systems 2008 Part 1 pdf

Mechanical Engineering Systems 2008 Part 1 pdf

... Figure 2.2 .1. p 1 = 2 bar p 2 = 15 bar V 1 = 0. 01 m 3 V 2 = 0.004 m 3 T 1 = 20 + 273 = 293 K T 2 =? p 1 V 1 T 1 = p 2 V 2 T 2 2 × 0. 01 293 = 15 × 0.004 T 2 T 2 = 15 × 0.004 × 293 2 × 0. 01 = 879 ... 2.2 .1 p/V diagram. Example 2.2 .1 Contents Series Preface vii 1 Introduction: the basis of engineering 1 1 .1 Real engineering 1 1.2 Units 3 1. 3 Units used in...

Ngày tải lên: 11/08/2014, 15:20

25 150 0
Mechanical Engineering Systems 2008 Part 6 pdf

Mechanical Engineering Systems 2008 Part 6 pdf

... Density ␳ kg/m 3 Relative density RD Dynamic viscosity ␮ Pa s or kg/m/s Air 1. 3 1. 3 × 10 –3 1. 85 × 10 –5 Water 10 00 1 0.0 01 Mercury 13 600 13 .6 1. 55 × 10 –3 Mineral oil 900 0.9 8 × 10 –4 Hydrostatic forces on curved surfaces In ... to metres. Head h = (13 600/850) × (245 /10 00) – 15 0 /10 00 = (16 × 0.245) – 0 .15 = 3.92 – 0 .15 = 3.77 m q F horizontal F vertica l...

Ngày tải lên: 11/08/2014, 15:20

25 287 0
Mechanical Engineering Systems 2008 Part 3 pptx

Mechanical Engineering Systems 2008 Part 3 pptx

... ΂ 1. 358V 3 16 V 3 ΃ 1. 4 = 1. 899 bar T 5 = T 4 ΂ V 4 V 5 ΃ ␥ – 1 = 15 73 ΂ 1. 358 V c 16 V c ΃ 0.4 = 586.5 K Heat energy supplied = m.c v (T 3 – T 2 ) + m.c p (T 4 – T 3 ) = 0. 717 (11 59 – 918 ) + 1. 004 (15 73 ... c p = 1. 005 kJ/kgK, ␥ = 1. 4 For combustion gases, c p = 1. 15 kJ/kgK, ␥ = 1. 33 See Figure 2.5.9. TЈ 2 T 1 = ΂ p 2 p 1 ΃ ␥ 1 ␥ , TЈ 2 = 293 × ΂ 4.04 1. 0...

Ngày tải lên: 11/08/2014, 15:20

25 366 0
Mechanical Engineering Systems 2008 Part 4 potx

Mechanical Engineering Systems 2008 Part 4 potx

... x(7. 715 ), x = 6.8435 – 0.559 7. 715 = 0. 815 h 2 = h f + x hfg = 16 3 + 0. 815 (2409) = 212 6 kJ/kg Rankine efficiency = h 1 – h 2 h 1 – h 4 = 3032 – 212 6 3032 – 16 3 = 0. 316 1 = 31. 6% Example 2.6 .11 Steam ... superheated. V 1 = 0.394 m 3 /kg p 1 V n 1 = p 2 V n 2 6 × 0.394 1. 13 = 1. 5 × V 1. 13 2 , V 2 = 1. 13 ͱ සසසසස 6 × 0.394 1. 13 1. 5 = 1. 344 m 3 (a) Examina...

Ngày tải lên: 11/08/2014, 15:20

25 431 0
Mechanical Engineering Systems 2008 Part 5 pps

Mechanical Engineering Systems 2008 Part 5 pps

... was isentropic, hЈ 2 = 14 69.9 + (5. 314 – 4.962) (5.397 – 4.962) × (16 13 – 14 69.9) = 15 85.7 kJ/kg 0.85 = hЈ 2 – h 1 h 2 – h 1 = 15 85.7 – 14 46.5 h 2 – 14 46.5 , h 2 = 16 10.3 kJ/kg Power = m(h 2 – h 1 )= 4.5 60 (16 10.3 ... T 6 ) 1 r 1 h 1 + ln r 2 r 1 k 1 + ln r 3 r 2 k 2 + ln r 4 r 3 k 3 + 1 r 4 h 0 (length, l =1) Q = 2␲.(230 – 15 ) 1 0.05 × 550 + ln 60 5...

Ngày tải lên: 11/08/2014, 15:20

25 1,5K 2
Mechanical Engineering Systems 2008 Part 7 pptx

Mechanical Engineering Systems 2008 Part 7 pptx

... for each section of the pipe. ⍀ 1 =8 × 10 × 0 .15 /(␲0.0025 4 ) = 9.778 × 10 10 Pa s/m 3 ⍀ 1 =8 × 8 × 0 .15 /(␲0.0 015 4 ) = 60.3 61 × 10 10 Pa s/m 3 Total resistance = 70 .13 9 × 10 10 Pa s/m 3 The flow rate ... pipes 10 3 234568 10 4 10 5 10 6 10 7 222333444555666888 10 8 10 8 2 2 3 3 4 4 5 5 6 6 8 8 – 0.000 01 0.00005 Laminar flow Laminar flow Relative roughn...

Ngày tải lên: 11/08/2014, 15:20

25 250 0
Mechanical Engineering Systems 2008 Part 8 docx

Mechanical Engineering Systems 2008 Part 8 docx

... acceleration then become ␻ 2 = ␻ 1 + ␣t (4 .1. 10) ␪ = ␻ 1 t + ␣t 2 /2 (4 .1. 11) ␪ = t(␻ 1 + ␻ 2 )/2 (4 .1. 12) ␻ 2 2 = ␻ 1 2 + 2␣␪ (4 .1. 13) Velocit y 0 Tim e t u v ( + )/2uv 17 4 Dynamics Adding the two ... distance it travels in the next 10 s. Velocity m/ s 0 Time/seconds t 1 t 2 s 1 4 s 2 t 3 s 3 Total area = 350 m Slope = 1. 8 m/s 2 Slope = – 2.4 m/s 2 Dynamics 17 5 Ex...

Ngày tải lên: 11/08/2014, 15:20

25 274 0
Mechanical Engineering Systems 2008 Part 10 doc

Mechanical Engineering Systems 2008 Part 10 doc

... which reaction R 1 acts gives: 12 × 5 + 10 × 10 + 15 × 15 =20R 2 Hence R 2 = 19 .25 kN. Equating the vertical components of the forces gives: R 1 + R 2 = 12 + 10 + 15 and so R 1 = 17 .75 kN. Figure ... gives: ¯ x = 30 × 30 × 15 – 20 × 10 × 25 30 × 30 – 20 × 10 = 12 .1 cm Taking moments about the x-axis gives: ¯ y = 30 × 30 × 15 – 20 × 10 × 25 30 × 30 – 20 × 10 = 12...

Ngày tải lên: 11/08/2014, 15:20

25 230 0
Mechanical Engineering Systems 2008 Part 11 pptx

Mechanical Engineering Systems 2008 Part 11 pptx

... 753.9 265.3 12 .9 17 .5 16 9 000 4480 18 8.0 686 × 254 17 0 692.9 255.8 14 .5 23.7 17 0 000 4 910 217 .0 14 0 683.5 253.7 12 .4 19 .0 13 6 000 3990 17 9.0 12 5 677.9 253.0 11 .7 16 .2 11 8 000 3480 16 0.0 Statics ... 16 .1 26.8 340 000 7990 289.0 19 4 840.7 292.4 14 .7 21. 7 279 000 6550 247.0 17 6 834.9 2 91. 6 14 .0 18 .8 246 000 5890 224.0 762 × 267 19 7 769.6 268....

Ngày tải lên: 11/08/2014, 15:20

25 222 1
Mechanical Engineering Systems 2008 Part 13 pps

Mechanical Engineering Systems 2008 Part 13 pps

... kN, F DE +23 .1 kN, F EF –23 .1 kN, F FG +23 .1 kN, F GH +11 .5 kN, F HI 11 .5 kN, F IJ +11 .5 kN, F JK 11 .5 kN, F KL +11 .5 kN, F LM 11 .5 kN, F MN + 11 .5 kN, F AN 11 .5 kN, F CD +11 .5 kN, F CF +34.6 ... kg/s 8. 0 .11 m/s 9. 0 .15 7 m/s, 1. 22 m/s 10 . 0.637 m/s, 7.07 m/s, 31. 83 m/s 11 . 13 4.7 kPa 12 . 7.62 × 10 –6 m 3 /s 13 . 208 mm 14 . 0. 015 × 10 –6 m 3 /s 15...

Ngày tải lên: 11/08/2014, 15:20

20 162 0
w