Materials Science and Engineering - Electronic and Mechanical Properties of Materials Part 2 pot
Materials Science and Engineering - Electronic and Mechanical Properties of Materials Part 1 doc
... R c2 & R c3 ⇒ therefore no IR contribution to V 23 R s ( 2- 3 ) = v 23 /I = σ -1 (d 23 /A) = ρ (d 23 /A) (Note: ρ-resistivity is inverse of σ−conductivity) © H.L. Tuller -2 0 01 3 .22 5 20 ... Measurements - Wafers I V d d R R+dR x j = I /2 R 2 ; V = IR = Iρd/A = jρd V 23 = ⌠ 2d (I /2 R 2 ) ρ dR = (- Iρ/ 2 R) 2d = Iρ/4πd ⌡ d d ρ = (2 d/I)...
Ngày tải lên: 11/08/2014, 14:20
Materials Science and Engineering - Electronic and Mechanical Properties of Materials Part 5 ppt
... conduction band or valence band by using a modified expression for the energy of an electron in the H atom 22 22 4 6.13 8 nnh me E o n −== ε 2 * 22 222 4* 22 2 4 16.131 88 2 2 εεεε ... ∂ type,-pin type,-nin 2 2 2 2 Assuming low-level injection, t n t n t n t n o ∂ ∆∂ ≈ ∂ ∆∂ + ∂ ∂ = ∂ ∂ therefore materialtype-nin materialtype-pinG 2...
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Materials Science and Engineering - Electronic and Mechanical Properties of Materials Part 10 pps
... / 27 . 02. 2001 S 121 9a S 121 9b S 121 9c S 121 9d resistance / Ohm M 9710746 20 V Datum: 23 . 02. 2001 - 27 . 02. 2001 Steuerdatei: allgas_h2.st g Meßprotokoll: 27 3 Schematic of Gas Sensor Structure 3 .22 5 12 © ... 12 13 10 -7 10 -6 10 -5 10 -4 Y-cut σ 0 = 2. 1 S cm -1 E A = 105 kJ mol -1 10 4 /T [1/K] σ [S cm -1 ] 900 800 700 600 500...
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Materials Science and Engineering - Electronic and Mechanical Properties of Materials Part 9 pps
... (Ωcm) -1 ) T = 800 °C log(pO 2 / bar) 0.995 1,005 -1 6 -4 0 -5 -4 -3 -2 -1 0 1 donor acceptor -2 0 -1 2 -8 donor doped acceptor doped 2 3 .22 5 15 Designer Wavelengths Variation of ... (1999). 185 3 .22 5 6 © H.L. Tuller -2 0 01 Oxygen Sensor in Thick Film Technology 3 3 .22 5 25 3-Way Catalyst Conversion Efficiency 3 .22 5 26 P...
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Materials Science and Engineering - Electronic and Mechanical Properties of Materials Part 3 pot
... ) ] ) 13 3 .22 5 25 Representation of E,k for 1-D Material m p m k E 22 22 2 == h E k ∆k =2 /L Quasi-continuous k m k E m k dk dE ∆=∆ = 2 2 h h states electrons E n E n-1 E n+1 m=+1 /2 ,-1 /2 All e- in box ... π ψψψ ψψψ sin2 cos2 =−= =+= ±= a kkk oi π 2 =−=∆ © E. Fitzgerald-1999 4 3 .22 5 23 Particle in Box zkykxkAzyx n 321 sinsinsin),,( ⋅⋅= ψ 2 3 2...
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Materials Science and Engineering - Electronic and Mechanical Properties of Materials Part 6 pps
... when you join these together? © E. Fitzgerald-1999 3 .22 5 12 - - + + + + Holes diffuse Electrons diffuse + + + + - - - - + + + + - - + + + + An electric field forms due to ... Fitzgerald-1999 7 3 .22 5 13 Joining p and n E c E F E v p n Carriers flow under driving force of diffusion until E F is flat - - + + + + Holes diffuse Electro...
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Materials Science and Engineering - Electronic and Mechanical Properties of Materials Part 8 pdf
... 1 2 1 , 2 2 + + = − − += ∴ ∞∞ ∞ 2 2 , 1 22 2 2 s oiT T s r ε ε ωω ω ω εε εε ε r ω ω T n 2 =ε ∞ ε s © E. Fitzgerald-1999 ) ) ] 3 .22 5 18 ... polarizability ωτ ε ε ε α εεωτ ωτε α χχε i n n N n i N n so r o DC sor o DC oer − − += ∴ +==<< − +=++= 1 3 , ,1 )1(3 1 2 2 2 2 We can write this in terms of a real and...
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Materials Science and Engineering - Electronic and Mechanical Properties of Materials Part 4 pps
... approximated as free • Their properties can still be viewed as free e- if an ‘effective mass’ m* is used π/a −π/a 2 2 2 * * 22 2 k E m m k E ec ec ∂ ∂ = = h h 2 2 2 * * 22 2 k E m m k E ev ev ∂ ∂ = = h h Note: ... to the next band are free carrier- like with mass, m* © E. Fitzgerald-1999 3 6 3 .22 5 11 Nearly-Free Electron Model (still 1-D crystal) m p m k E 22 22 2 ==...
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Materials Science and Engineering - Electronic and Mechanical Properties of Materials Part 11 potx
... B 2 2 4 4 444~ = Φ = ===Φ L increased by ~χ due to magnetic material Material Type χ Paramagnetic +10 -5 -1 0 -4 Diamagnetic -1 0 -8 -1 0 -5 Ferromagnetic +10 5 2 ... 1 tc dEV dEEdS tc BdS tc EdS t B c E B B B ∂ Φ∂ −=⋅= ⋅=×∇ ≡Φ ∂ Φ∂ −= ∂ ∂ −=×∇ ∂ ∂ −=×∇ ∫ ∫∫∫ ∫∫∫∫ l l Φ===⋅= ∂ ∂ == ∂ ∂ = ∂ ∂ = ∂ ∂ −= ∂ Φ∂ −= ∂ ∂ = ∂ Φ∂ ==Φ...
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Materials Science and Engineering - Electronic and Mechanical Properties of Materials Part 2 pot
... Fitzgerald-1999 3 .22 5 12 Waves in Vacuum 0, =ρ J 00 ; εεµµ == 2 2 00 2 t E E ∂ ∂ =∇ µ Wave Equation For typical wave: trik eEE ω−⋅ = 0 πνωλπ 2; 2 == k 2 00 2 ωεµ= k ( 21 ... 2 0 0 2 0 0 0 0 0 0 22 2 1 )( c i c i c k i cc k ε ωσ ε ωσ ωε σ ω ωε σ ω ωε ω δ ωµσσω ε δ ooo o i c k 2 2 1 2 === © E.A. Fitzgerald-...
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