... (5)(5) = 25 . 22 . 26 . If x – 8 is 4 greater than y + 2, then x – 8 = y + 2 + 4.x – 8 = y + 6x = y + 14Since x + 12 = (y + 14) + 12 = y + 26 , then x + 12 is 26 greater than y. 23 . 42. First, ... 5)(x – 4)xy 123 45671 2 345–1 2 –3–1 2 3–4–5–6–7xy 123 45671 2 345–1 2 –3–1 2 3–4–5–6–7–THE SAT MATH SECTION– 124 5658 SAT2006[04](fin).qx 11 /21 /05 6:44 PM Page 124 Sometimes, you ... choose.2p + q = 11 becomes q = 11 – 2p 2. Second, substitute 11 – 2p for q in the otherequation and solve:p + 2( 11 – 2p)= 13p + 22 – 4p = 13 22 – 3p = 13 22 = 13 + 3p9= 3pp = 33. Now substitute...