Introduction to Contact Mechanics Part 10 ppsx

... view Section view −3 −2 −1 0 0. 300 0.2 50 0.2 00 0 .100 0.050 0.025 0. 010 z/a 0 .100 0.05 0 10. 3 Indenter Types 177 contact with the specimen is given by sin β = a/R, which for β = 22° gives a/R = 0.375. It is interesting to note ... is large in comparison to the size of the radius of circle of contact, then one may consider the mean contact pressure to be independent...

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... 438 Index limitations of, 109 wear particle analysis, 205 Total acid number, 204 Total base number, 204 Total plant predictive maintenance, 70, 352 U Ultrasonic monitoring, 111, 256, 400 types ... stands. 18.7.4 Customer Focus The priority of everyone in the maintenance improvement program must be the inter- nal customer. The maintenance department’s customer is the machine operator. Oper-...

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... in which case the standard 1.2 .10. 5 Axis-symmetric coordinate system: 3 dimensions (1.2 .10. 4b) (1.2 .10. 4c) (1.2 .10. 4d) (1.2 .10. 5a) (1.2 .10. 5b) (1.2 .10. 5c) 1.2 Elasticity 19 quantity) ... losses due to heat, sound, etc.). The resulting two separated atoms have the potential to form bonds with other atoms. The atoms, now separated from each other, can be co...

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... geometry factor, and c is the crack half-length. K 1 is called the “stress intensity factor.” There is an impor- tant reason for the stress intensity factor to be defined in this way. For a particu- lar ... the strength of a particular structure was not appreciated by engineers. These failures led to the emergence of the field of “fracture mechanics. ” Fracture mechanics attempts...

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... to the stress field at A, and the stress intensity fac- tor due to those forces is: () 12 1 12 π − ⎛⎞ = ⎜⎟ + ⎝⎠ B B F cb K cb c (2.5.2b) Due to the additive nature of stress intensity factors, ... strain fracture toughness.” 2.5.2 Calculating stress intensity factors from prior stresses Under some circumstances, it is possible 10 to calculate the stress intensity factor for a...

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... 5.1 10 −57 m −2 Pa −m , log 10 D = 102 .6, n = 17. ______ Elastic Indentation Stress Fields 78 v. The integral of the pressure distribution within the circle of contact with respect to ... attribut- ing a quadratic function to represent the profile of the two opposing surfaces and gave particular attention to the case of contacting spheres. Condition 4 above, taken tog...

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... “The Hertz contact problem with finite friction,” J. Elastoplast. 5 3–4, 1975, pp. 297–319. 10. J. Tseng and M.D. Olson, “The mixed finite element method applied to two- 11. N. Okamoto and M. ... surface since the radius of curvature is assumed to be large in comparison to the area of contact. ______ 6.2 Contact Between Elastic Solids 103 Table 6.1 Equations for surface...

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... 0.01 0 .10 1.00 10. 00 c/a 0.01 0 .10 1.00 10. 00 G/2γ @P = P a 0.00 0.01 0 .10 1.00 10. 00 c/a 0.01 0 .10 1.00 10. 00 (b) 1.2 1.6 Elastic-Plastic Indentation Stress Fields 142 attempts to resume ... mean contact pressure and a is the radius of circle of contact) . Substituting this value of B into Eqs. 8.2.1a to 8.2.1d and normalizing to mean contact pressure p and ra...

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... 0 −4 −3 −2 −1 0 (a) (b) (c) 0.005 − 0 . 3 00 − 0.200 0.005 0 . 0 1 0 0. 010 0 .0 05 0 . 020 0.02 0 0.00 5 − 0.0 25 − 0.050 − 0. 1 00 0. 010 0.0 05 − 0.20 0 − 0 .100 − 0 .060 − 0 .040 − 0 .020 − 0. 010 − 0.008 − 0.006 − 0.004 − 0. 002 0 . 0 02 0.004 0 .006 0.008 − 0.3 00 − 0. 200 − 0. 150 − 0. 100 − 0.050 0.0 2 0 0. 0 10 − 0 .5 00 − 0 . 2 50 − 0 .10 0 − 0.1 00 − 0.050 − 0.005 − 0. 02...

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