Introduction to Contact Mechanics Part 5 pdf

... ) (g) 0.1 25 0.1 25 0 .50 0 − 0. 250 0.000 0 .2 5 0 − 2 5 .000 − 10.0 0 0 − 5. 00 0 − 2 .50 0 2 5 .0 15. 0 10.0 8.0 6.0 4 .0 3 .0 2 . 0 1. 5 1 . 0 0 . 8 0 . 6 0 . 4 0.2 0 . 1 0.4 0.6 0.8 1.0 1 .5 2.0 3 .0 4 .0 6. 0 2.0 1. 5 1 .0 0 .8 − 1 .50 0 − 5. 000 − 2 .50 0 − 1 .50 0 − 1 .0 00 − 0 . 50 0 − 0. 250 − 0. 100 − 0 . 0 2 5 0. 250 0 . 5 0 0 0. 250 − 10.00 − 7 .50 −...

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... losses due to heat, sound, etc.). The resulting two separated atoms have the potential to form bonds with other atoms. The atoms, now separated from each other, can be considered to be a “surface.” ... directions on a particular atom, and the atom takes up an equi- librium position within the material. Now consider an atom “B” on the surface. Such an atom is attracted by the many ato...

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... experimental work at the U.S. Naval Research Laboratory in Washington, D.C. led, in 1 957 4 , to a theoretical formulation of fracture that continues to find wide application. Irwin showed that the ... geometry factor, and c is the crack half-length. K 1 is called the “stress intensity factor.” There is an impor- tant reason for the stress intensity factor to be defined in this wa...

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... fatigue of glass I,” J. Appl. Phys. 29 11, 1 958 , pp. 154 9– 155 3. 5. R.J. Charles, “Static fatigue of glass II,” J. Appl. Phys. 29 11, 1 958 , pp. 155 4– 156 0. 6. R.E. Mould and R.D. Southwick, “Strength ... factors, the total stress intensity factor at crack tip A shown in Fig. 2 .5. 2c due to forces F A and F B , where F A = F B = F, is : 12 11 1 12 2 2 2 π ⎛⎞ =+= ⎜⎟ − ⎝⎠ AB...

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... 3103MPa Bonded (a) d r (mm) 0. 05 0.1 0.2 0.4 µ = 0 Eqn. Surface radial displacements Bonded r/a (b) Punch p m σ r 0. 05 0.1 0.2 0.4 Eqn. 1 0.0E+0 −4.0E−4 −8.0E−4 −1.2E−3 −1.6E−3 0 .5 0 −0 .5 −1 −1 .5 −2 0.0 0 .5 1.0 1 .5 0.0 0 .5 ... 0.4 c/a 0.00 0. 05 0.10 0. 15 0.20 0. 25 σ 1 /p m 0.0 0.1 0.2 0.3 0.4 c/a 0.00 0. 05 0.10 0. 15 0.20 0. 25 (a) 0.0011 φ(c/a) 1.1 1.6 Auerbach ran...

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... (m 3/2 ) 0.2 0.3 0.4 0 .5 a = 0.6 mm Punch 0.000 0.004 0.008 0.012 Indenter radius (m) 0 50 0 1000 150 0 2000 250 0 Minimum critical load (N) Sphere (a) 0 50 0 1000 150 0 2000 250 0 Minimum critical load ... 4 r −4 −3 −2 −1 0 z (c) − 0 . 3 0 0 − 0 . 2 0 0 − 0 .1 0 0 − 0 .0 5 0 − 0. 0 2 5 − 0 . 1 0 0 − 0. 05 0 − 0. 0 10 − 0.00 5 0 . 0 0 0 0 . 0 0 0 0 . 0 2 5 0. 013 0 . 0 0 6 0...

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... 0 −4 −3 −2 −1 0 (a) (b) (c) 0.0 05 − 0 . 3 00 − 0.200 0.0 05 0 . 0 1 0 0.010 0 .0 05 0 . 020 0.02 0 0.00 5 − 0.0 25 − 0. 050 − 0. 1 00 0.010 0.0 05 − 0.20 0 − 0.100 − 0 .060 − 0 .040 − 0 .020 − 0.010 − 0.008 − 0.006 − 0.004 − 0. 002 0 . 0 02 0.004 0 .006 0.008 − 0.3 00 − 0. 200 − 0. 150 − 0. 100 − 0. 050 0.0 2 0 0. 0 10 − 0 .5 00 − 0 . 2 50 − 0.10 0 − 0.1 00 − 0. 050 − 0.0...

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... 0.0 35, 0. 05, 0.07, 0.09, 0.10, 0.13. Distances are expressed in terms of the contact radius a = 0.3 15 mm for the elastic case of P = 1000 N. 0 1 2 r/a −3 −2 −1 0 −1 .5 −1.0 −0 .5 0.0 (a) Top ... view Section view −3 −2 −1 0 0. 300 0.2 50 0.2 00 0.100 0. 050 0.0 25 0.010 z/a 0.100 0. 05 0 10.3 Indenter Types 177 contact with the specimen is given by sin β = a/R, which f...

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... factor, 31-33, 50 , 51 , 52 , 54 stress corrosion theory, 50 , 51 , 54 , 56 stress deviations, 8, 25 stress equilibrium, 23 stress intensity factor, 37, 40-47, 50 , 53 , 54 , 55 , 58 , 61, 73, 117, ... diameter 58 130 0.06 1.71 76 196 439 0.08 2.28 180 464 1040 0.10 2. 85 352 907 2032 0.12 3.43 607 156 7 0.14 4.00 9 65 2488 0.16 4 .57 1440 0.18 5. 14 2 050 0.20 5. 71 2...

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