Illustrated Sourcebook of Mechanical Components Part 3 docx

... Thickness of the sleeve wall J = Polar moment of inertia (for the shaft: T DI4 /32 ) JEG nD13H/4 LI = Length of shaft Lz = Length of sleeve m = D,/8HC3 = ratio of torsional ... or more projecting pins, the 3um of the radii of the pins being equal to the eccentricity of offset of the shafts. The lines of criiter between each pair of pins re...

Ngày tải lên: 11/08/2014, 08:22

... Eq 3, 4, and 5 e he hn = 1.750 - 1 .39 3 = 0 .33 5 in. = 1.2.50 - 0 .35 5 = 0.8 93 in. = 1.250 + 0 .35 3 = 1.605 in. From Eq 6 and 7 = 0.482M 1.605111 3. 1 23 X 0 .35 5 ... the geometry of the figure A = 3. 125 in.2; d = h/2 = 3. 250 in. h-d = 1.250 in.; ICQ = 1.628 h4; %B =1 .30 2 in .3 From Eq 2 3. 125 1.25 In (3i0.5)...

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... 29.8666 31 .8666 32 .2821 29 30 . 933 3 32 . 933 3 33 .35 02 22 23. 4666 25.4666 25.8714 30 31 32 33 34 35 36 37 38 39 32 .0000 33 .0666 34 . 133 3 35 .2000 36 .2666 37 .33 33 38 .4000 39 .4666 ... 21 .33 33 23. 333 3 23. 733 4 21 22.4000 24.4000 24.8026 23 24. 533 3 26. 533 3 26.9402 24 25.6000 27.6000 28.0089 25 26.6666 28.6666 29.07 73 26 27. 733 3 29...

Ngày tải lên: 11/08/2014, 08:22

... film = 3. 333 3 D, = pitch dia = 3. 4286 COS +z = 15" ;31 /i' G 0.9 639 D COS $2 3. 4286 x 0.9 639 cos +1 = 3 - - - - = 0.99145 D, - 3. 333 3 41 = 7" ;30 ' ... D:, = 3. 4286 C = - = 0.19 23 ?r P D 2.156 P = 0. 132 - - RD = 3. 2870 Base dia. = 0.9915 x 3. 333 3 = 3. 3048 Referring to Fig. 3, the sprocket tooth...

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... preventing niotion of latch C, resulting in dismgagement of thc clutch after part of the cycle until subsequent raising of block H pcrmits motioii of latch C and resumption of the cyele. ... accurate values I of torque can be easily determined. ILLUSTRATED SOURCEBOOK of MECHANICAL COMPONENTS SECTION 9 Various Methods of Locking Threaded Members L...

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... sides of sheet. FIG. 11-For attachment of recessed, solid metallic or non-metallic parts in thick-sectioned cylindrical parts. FIG. 12-For closing the end(s) of cylin- drical parts. ... Removal of the screw permits easy removal of the clampcd part. Heavy pressure toward the side of the key out of contact with the slot may permit slight movement due to the springin...

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... Pump Valves 13- 2 13- 4 13- 6 13- 8 13- 10 13- 12 13- 14 13- 16 Retaining Rings 12- 23 A = Deflection at Point A P = Load at Point B R = Radius of Ring E = Modulus of Elasticity ... 0.057 0.0 83 0.010 0 090 0.1 13 1 0 012 1 0.1 23 0.1 73 0.017 0.188 0.220 I 0.029 1 0.240 O.Il3 I I - D Groove >ength*: 3/ 32 9 13 2 31...

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... Exponds u8en hqnde is serewedon shoft * *I *1 3, , >> ", ST-BEARjNG TAKES LIGHT LOADS. ' I ILLUSTRATED SOURCEBOOK of MECHANICAL COMPONENTS SECTION 16 12 Ways ... Compute Effects of Preloaded Bearings 15-29 Compact Ball Transfer Units 15 -39 How Soft Balls Can Simplify Design 15 -32 tion and estimated Llo fatigue life? From Eq 3...

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... 6,,,,,=0.74 mm gives a maximum-load value of F,,,, =30 0 kg (6 63 lb). Thus the spring may be loaded be- tween 155 and 30 0 kg for an in- definite number of times. Moreover, if Schremmer's ... space. ILLUSTRATED SOURCE BOOK of MECHANICAL COMPONENTS SECTION 18 CAMS Generating Cam Curves 18-2 Balance Grooved Cams 18-9 Computer and N/C Simplifies Cam Design...

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... [2~(0 .31 5)] ] 3. 73 COS [Zn(0 .31 5)] V = 56 .3 in./sec 3: A= The acceleration is found from Eq 2(2r)(l - 0. 134 ) ah 1 13. 5" 0.052(1 - 0. 134 COS 1 13. 5')' = 33 20 ... magnification of 30 X, although provision is made for 50X. Using Mylar drawing film for the profile, which is to be ked to the ground-glass screen, a 30 X drawing or...

Ngày tải lên: 11/08/2014, 08:22