Illustrated Sourcebook of Mechanical Components Part 1 pptx
Illustrated Sourcebook of Mechanical Components Part 1 pptx
... 10 9.8666 10 8.6666 10 9.7333 11 1.8666 11 2.9333 11 4.0000 11 5.0666 11 6 .13 33 11 7.2000 11 8.2666 iio.8ooo 10 9 .11 54 11 0 .18 23 11 1. 24 91 11 2. 315 8 11 3.3826 11 4.4495 11 5. 516 3 11 6.58 31 ... 11 6.58 31 11 7.6499 11 8. 716 6 11 0 11 7.3333 11 9.3333 11 9.7834 11 1 11 8.4000 12 0.4000 12 0.8503 11 2 11 9.4666 12 1.4666 12 1. 917 0 11 3 12 0...
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Illustrated Sourcebook of Mechanical Components Part 4 pptx
... that of the toothed clutch of Example 11 . SOLUTION 11 1. Line 11 1 through these values for 0 and p on the nomogram gives a value for K of 0.2. Torque transmitting capacity of flat-face ... for K of 3 approximately. EXAMPLE 11 1. Find the value of K for a flat-face (8 equals 90 deg) friction clutch, the face material of which has a coefficient o...
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Illustrated Sourcebook of Mechanical Components Part 2 potx
... previously computer on page 87. vz = 1 v1 1 - 3.7 x 10 -5 = 1. 000?037 Pima Ti( Vz - VI) = (15 .5)(20) (1. 000,037 - lj = 310 (0.37) (10 -4) = 0. 011 in lb/sec It is safe to assume ... = 11 0 in lb/sec; therefore the effi- ciency of the tape drive is 11 0 - 0.022 I - 11 0 1 - 0.00022 or 99.98% This example shows why X-Y curve plotters and oth...
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Illustrated Sourcebook of Mechanical Components Part 3 docx
... = a[l -1/ 1 - (l/ar)] (11 ) where r = 1 + D1/8HC3 = 1 + m c = Dz/D1 a = Ll/L2 The ratio in, which is equal to D1/8HC3, is the ratio of the torsional stiffness of the shaft ... g. 13 -11 1 this Brown Engineerillg Coinpany couplillg 1kxihiIit)- is increased by addition of 1) ufler-slots in the lami- nated leather. These slots also aid in the absorp...
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Illustrated Sourcebook of Mechanical Components Part 5 pdf
... 9-49 FIG. 10 -For permanent assemblies where split forming die can be applied on one or both sides of sheet. FIG. 11 -For attachment of recessed, solid metallic or non-metallic parts in thick-sectioned ... thick-sectioned cylindrical parts. FIG. 12 -For closing the end(s) of cylin- drical parts. “Toothed” section permits removal of cap, “solid’ section does not. F...
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Illustrated Sourcebook of Mechanical Components Part 6 pps
... gaskets 1 to 52 1 to7 I 1/ 16 l/4 11 8 8 to 14 313 2 15 to27 1/ 8 28 to 52 I 3 /16 I For Static Seals I For Dynamic Seals 0.07 010 .003 I 0. 015 0 .10 3 l0.003 0. 017 0 13 9f0.004 ... 0. 210 =1= 0.005 0.032 0.275%0.006/ 0.049 I- 0 .13 9&0.004 0.022 I CI IC -0.005 I 1- 0 0 01 -1- 1- 0.052 I 0. 010 I 0.057 0.083 0. 010 0 090 0 .11...
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Illustrated Sourcebook of Mechanical Components Part 7 potx
... hole in spring end. ILLUSTRATED SOURCEBOOK of MECHANICAL COMPONENTS SECTION 15 12 Ways to put Balls to Work 15 -2 15 -4 Rubber Balls Find Many Jobs 15 -6 Multiple Use of Balls in Milk ... 15 -8 Use of Balls in Reloading Press 15 -10 Nine Types of Ball Slides for Linear Motion 15 -12 Unusual Applications of Miniature Bearings 15 -14 Roller Contact Bearing M...
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Illustrated Sourcebook of Mechanical Components Part 8 doc
... 11 v . g (1. 16) (15 ) (11 .5X106) 10 10 min - Step 2-Find the wire size, Eq 10 Step 3Solve for the number of ac- tive coils, Eq 5 = 7.5 4 (0 .16 ) N= __- (0 .092)2 (13 2) Step Malculate ... for Spring Pins 17 -8 Uses of Split Pins 17 -10 Design Around Spiral-Wrapped Pins 17 -12 A Penny-wise Connector - The Cotter Pin 17 -14 Alternates for Doweled Fast...
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Illustrated Sourcebook of Mechanical Components Part 9 pps
... Z 0 1 - COS [2~(0. 315 )] ] 3.73 COS [Zn(0. 315 )] V = 56.3 in./sec 3: A= The acceleration is found from Eq 2(2r)(l - 0 .13 4) ah 11 3.5" 0.052 (1 - 0 .13 4 COS 11 3.5')' ... LB PSI 4000 Over 210 .000 4000 1 su.ou0 4000 I20,OOO 4000 90,000 4000 h0,000 Threaded Components 19 -15 3. . FOR BOLT DiAMIETERS, 11 4 IN. TO 21...
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Illustrated Sourcebook of Mechanical Components Part 10 potx
... plane of the outer facing sheet. Again reverting to a mechanical joint, Fig. 13 is a composite of two types of panel connection to the spar cap. The double joint takes all kinds of ... pins, shouldered shafts ond similar parts. 13 most hopper feeds, random selec- tion of chance-orientated parts necessitates further machinery if parts must be fed in only one s...
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