Hydrodynamic Lubrication 2011 Part 4 ppsx

... [ 24] :  r = 1 2µ ∂p ∂r z(z − h) + ρrω 2 µ  hz 4 − z 2 2 + z 3 3h − z 4 12h 2  (4. 37) G c = ρrω 2 µ h 3 40 (4. 38) If G c = 0 is assumed in Eq. 4. 34, Reynolds’ equation ignoring the centrifugal force ... µU  h 2 h 1  3h m h 2 − 4 h  dx (4. 21) = µUB h 2  h 2 h 1 ⎛ ⎜ ⎜ ⎜ ⎜ ⎝ 3 h m h 2 − 4 h ⎞ ⎟ ⎟ ⎟ ⎟ ⎠ d ¯x (4. 22) In the case of an infinitely long plane pad, substituting...

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... is 2 Foundations of Hydrodynamic Lubrication The essence of hydrodynamic lubrication was first clarified experimentally by British railroad engineer Beauchamp Tower (1 845 – 19 04) in 1883 [1][2]. ... lubrication. Recently developed theories of elastohy- drodynamic lubrication, thermohydrodynamic lubrication, turbulent hydrodynamic lubrication, and others are regarded as extension...

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... [ 24] :  r = 1 2µ ∂p ∂r z(z − h) + ρrω 2 µ  hz 4 − z 2 2 + z 3 3h − z 4 12h 2  (4. 37) G c = ρrω 2 µ h 3 40 (4. 38) If G c = 0 is assumed in Eq. 4. 34, Reynolds’ equation ignoring the centrifugal force ... exit clearance h 0 of the pad (see Fig. 4. 7). ¯r = r − R ∆R , ¯ θ = θ θ 0 , ¯ h = h h 0 , ¯p = ph 0 2 ωµR 2 (4. 43) 4. 1 Infinitely Long Plane Pad Bearings 49 4. 1.1 Basic...

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... 46 <XNLR+RUL +\GURG\QDPLF/XEULFDWLRQ :LWK)LJXUHV ABC VIII Contents 4 Fundamentals of Thrust Bearings 47 4. 1 InfinitelyLongPlanePadBearings 48 4. 1.1 BasicFormulae 49 4. 1.2 Basic Characteristics . 49 4. 2 Finite Length Plane Pad Bearings 54 4.3 Sector ... Bearings 55 4. 3.1 Reynolds’ Equation in Cylindrical Coordinates . 55 4. 3.2 Numerical Solution of a Sector Pad 57...

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... obtain the following equation: 14 2 Foundations of Hydrodynamic Lubrication ∂p ∂x = ∂ ∂y  µ ∂u ∂y  (2.6) On the further assumption that µ is constant (assumption 4) , the equation of the balance ... experiments and studied them theoretically. In the introductory part of his famous paper of 1886 [3] on hydrodynamic lubrication, Reynolds wrote: Lubrication, or the action of oils...

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... pp. 44 4 - 45 0. 13. J. Mitsui, “Method of Calculation for Bearing Characteristics”, Journal Bearing Data- book (T. Someya, Editor), Springer Verlag, Berlin Heidelberg, 1988, pp. 231 - 240 4 Fundamentals ... Sommerfeld’s condition. From Eq. 3 .42 and Eq. 3 .43 , the bearing load P 1 is obtained as: P 1 = µUL  R c  2 6κ {4 2 + π 2 (1 − κ 2 )} 1/2 (2 + κ 2 )(1 − κ 2 ) . (3 .44 ) This can...

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... κ 0 2  π 2 − (π 2 − 4) κ 0 2  π 2 − 8 π(2 + κ 0 2 )  (5.39) C xy =+ 4  π 2 − (π 2 − 4) κ 0 2 (5 .40 ) K yx =+ π  1 − κ 0 2  π 2 − (π 2 − 4) κ 0 2  1 κ 0 − 2κ 0 2 + κ 0 2 + κ 0 1 − κ 0 2  (5 .41 ) K yy = ... jour- nal center (x j , y j ) from the equation of motion Eqs. 5 .47 and 5 .48 . Thus, substitution of Eqs. 5 .49 and 5.50 into Eqs. 5 .47 and 5 .48 , respectively, use of the...

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... Analysis of Floating Bush Bearing” (in Japanese), Trans. JSME, C, Vol. 65, No. 640 , December 1999, pp. 48 40 - 48 45. 66. Y. Hori, Compilation of Manufacturers’ Data from Various Sorces (2003). 5.10 ... 1982, pp. 389 - 395. 43 . M. Akkok and C.M.M. Ettles, “Journal Bearing Response to Excitation and Behaviour in the Unstable Region”, ASLE Trans., Vol. 27, 19 84, pp. 341 - 351. 44 . H. H...

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... March 24 - 27, 1975, pp. 121 - 125 #D-5. Bulletin of the JSME 20- 141 (1977-3) pp. 381 - 387. 16. A. Hasuike and Y. Hori, “A Study on Foil Disk” (in Japanese), Trans. JSME, C, Vol. 49 , No. 44 0, April ... Vol. 94, No. 1, January 1972, pp. 93 - 100. 13. M.M. Reddi, “Finite Element Solution of the Incompressible Lubrication Problem”, Trans. ASME. F, Vol. 91, No. 3, July 1969, pp. 5 24 -...

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... consideration. 7 .4 Sinusoidal Squeeze with a Soft Surface 153 We then solve Eqs. 7 .40 and 7 .44 simultaneously under the boundary condition p N+1 = 0 (7 .46 ) using the Newton–Raphson method. Since Eq. 7 .44 includes ... Basic Equations for Thermohydrodynamic Lubrication Hydrodynamic lubrication that takes heat generation and temperature rise into con- sideration is called thermohydr...

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