Hydrodynamic Lubrication 2009 Part 7 pot

Hydrodynamic Lubrication 2009 Part 7 pot

Hydrodynamic Lubrication 2009 Part 7 pot

... -2.1143 = 2 -2.4468 0. 971 2 -2.1143 2. 577 0 = 11 = 12 = 22 = 13 = 14 = 23 = 24 23.2595 -0.1 478 -8. 976 9 -9 .79 37 1.9934 -3.0892 -2.4369 -7. 7506 -0. 873 0 3.3898 2.0613 5.3423 -2 .76 28 3.0995 As an example, ... ASME, Vol. 78 , 1956, pp. 975 - 983. 12. V.T. Morgan and A. Cameron, “Mechanism of Lubrication in Porous Bearings”, Proceed- ings of Conference on Lubrication and Wear, IM...

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Hydrodynamic Lubrication 2009 Part 5 potx

Hydrodynamic Lubrication 2009 Part 5 potx

... φ = 2 √ α 2 − κ 2 tan −1 ⎡ ⎢ ⎢ ⎢ ⎢ ⎣  α − κ α + κ sin φ 1 + cos φ ⎤ ⎥ ⎥ ⎥ ⎥ ⎦ 5.2 Oil Whip Theory 77 Fig. 5 .7. Coordinates of the system (radial and circumferential direction) the bearing center. The ... on which the point falls. 5.2 Oil Whip Theory 79 negative, and the Routh–Hurwitz criterion is known as a criterion for this. In the case of Eq. 5. 57, it can be written as follows: A 0...

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Hydrodynamic Lubrication 2009 Part 6 pot

Hydrodynamic Lubrication 2009 Part 6 pot

... left part of Fig. 5.22, the equation of motion of the rotor can be written as follows (the x axis is taken downward): m ¨x + k(x − x j ) = − m ¨ X B + mg (5 .75 ) m¨y + k(y − y j ) = − m ¨ Y B (5 .76 ) k(x ... m ¨ X B + mg (5 .75 ) m¨y + k(y − y j ) = − m ¨ Y B (5 .76 ) k(x − x j ) + 2P x = 0 (5 .77 ) k(y − y j ) + 2P y = 0 (5 .78 ) where ¨ X B and ¨ Y B are the vertical and horizontal acce...

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Hydrodynamic Lubrication 2009 Part 9 pot

Hydrodynamic Lubrication 2009 Part 9 pot

... =  ρ ¨ h 4h − 3ρ ˙ h 2 8h 2  (r 2 − r 2 a ) (7. 25) s/cm 2 Fig. 7. 3. Comparison of viscous, modified, and inertia solutions [7] Figure 7. 3 compares Eqs. 7. 18, 7. 22, and 7. 25 in a constant velocity squeeze in ... equations: Eqs. 7. 3, 7. 4, and 7. 5 (or Eq. 7. 6). c. Reynolds’ Equation When inertia effects can be disregarded, Reynolds’ equation can be derived. First, simplify th...

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Hydrodynamic Lubrication 2009 Part 11 pot

Hydrodynamic Lubrication 2009 Part 11 pot

... ratio c/R Length of metal L = 70 mm = 0.00 078 7 (bearing #1) Length of oil groove 60 mm (axial) = 0.00101 (bearing # 2) Width of oil groove 8 .7 mm (circum.) = 0.001 57 (bearing # 3) Oil supply pressure ... − F 1 F 0  z 0 dz µ  dz G 2 =  h 0 ρ  1 r G 0 F 0  z 0 dz µ − 1 r  z 0  1 µ  z 0 ρ( θ ) 2 dz  dz  dz G 3 =  h 0 ρrω  1 F 0  z 0 dz µ − 1  dz (8 .71 ) By means of Eq. 8 ....

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Hydrodynamic Lubrication 2009 Part 13 pot

Hydrodynamic Lubrication 2009 Part 13 pot

... Transactions, Vol 13, 1 970 , pp. 262 - 268. 17. H. Aoki and M. Harada, “Turbulent Lubrication Theory for Full Journal Bearings” (in Japanese), Journal of Japan Society of Lubrication Engineers, ... calculation conditions are as follows: D = 70 mm, L = 35 mm, c = 0. 175 mm, N = 4000 rpm, µ = 1.44 mPa·s, the axial Reynolds’ number R a = w m c/ν = 76 7 – 2540 (w m is the axial average ve...

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Applied Structural and Mechanical Vibrations 2009 Part 7 pot

Applied Structural and Mechanical Vibrations 2009 Part 7 pot

... chapter, that each eigenvector is in the form (7. 70) By virtue of eq (7. 70), the 2n×2n matrices S and S T can be partitioned into (7. 71a) and (7. 71b) where the orders of Z, Z T and diag( j ) ... by to give (7. 57a) and premultiplied by to give (7. 57b) so that eq (7. 56) becomes (7. 58) which can be compared to eq (7. 55) to conclude that the receptance matrix is written as (7. 5...

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Hydrodynamic Lubrication 2009 Part 1 docx

Hydrodynamic Lubrication 2009 Part 1 docx

... 1 37 7.1 Basic Equations 138 7. 2 Squeeze Between Rigid Surfaces 141 7. 2.1 Squeeze Without Fluid Inertia . 141 7. 2.2 Squeeze with Fluid Inertia 142 7. 2.3 Sinusoidal Squeeze Motion . . . 144 7. 3 ... Wear, and Lubrication 1 1.1 Friction,Wear,andLubrication—Tribology 1 1.2 VariousFormsofLubrication 2 1.2.1 SolidFriction 4 1.2.2 Hydrodynamic Lubrication . . . 6 1.3 Meanings of Tri...

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Hydrodynamic Lubrication 2009 Part 2 ppsx

Hydrodynamic Lubrication 2009 Part 2 ppsx

... - 70 . 3. Osborne Reynolds, “On the Theory of Lubrication and its Application to Mr.B. Tower’s Experiments”, Philosophical Transaction of Royal Society of London, Vol. 177 , Pt. 1, 1886, pp. 1 57 ... experiments and studied them theoretically. In the introductory part of his famous paper of 1886 [3] on hydrodynamic lubrication, Reynolds wrote: Lubrication, or the action of oils and...

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Hydrodynamic Lubrication 2009 Part 3 docx

Hydrodynamic Lubrication 2009 Part 3 docx

... follows: 2R  π 0  L/2 0 p cos φdzdφ + P 1 cos θ = 0 (3. 57) 2R  π 0  L/2 0 p sin φdzdφ − P 1 sin θ = 0 (3.58) By substituting Eq. 3.56 into the above equations and using the partial fraction decomposition method ... other symbols are the same as before: ¯x = x D , ¯z = z L , ¯ h = h c , ¯p = p µω  c R  2 (3. 67) Then, Reynolds’ equation, Eq. 3.66 can be nondimensionalized in the follo...

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