Engineering Materials vol 1 Part 12 ppt
Engineering Materials vol 1 Part 12 ppt
...
1. 09
1. 18
1. 71
1. 66
3.03
1. 18
1. 40
1. 20
1. 80
1. 53
1. 80
1. 59
17 26
13 56
12 34
933
600
17 53
21 73
21 63
27 41
2883
32 71
3683
21 4
12 4
76
69
Id
19 6
13 0
r
00
360
18 0 ... a [11 01, a
[11 11
and a [ 211 1 direction.
(d) The slip planes of f.c.c. copper are the
(11 11
planes: sketch the atom
arrangement in these planes and mar...
Engineering Materials vol 1 Part 5 ppt
... one problem
1
16
Engineering
Materials
1
/
E
Fig.
11 .6.
The
condition
for
necking.
If
these are differentiated and substituted into the necking equation we get
(11 .5)
In other ... is found at
45"
to
the tensile axis,
and
has
a
value
of
u/2.
1
12
Engineering Materials
1
Fig.
11
.l.
A
tensile stress,
F/A,
produces a shear stress,
T,
on an...
Engineering Materials vol 1 Part 1 docx
...
18 00-2500
5000 -1 5000
8000 -1 2000
12 00-2000
13 00-3000
18 00-2300
12 00 -1 250
11 50 -12 00
910 -12 00
91 0-930
12 00 -1 A00
11 00 -14 00
2500-3200
12 00 -1 800
680 -1 200
1
10 0-3000
1
000 -13 00 ...
3750- 810 0
41 25-4800
2700-3750
7500-22500
12 000 -1 8000
18 00-3000
19 50-4500
2700-3450
18 00 -1 875
17 25 -1 800
13 65 -1 800
13 65...
Engineering Materials vol 1 Part 3 doc
...
2.4-2.5
1. 4-2.2
2.2
2.3
2.0
1. 85 -1. 9
1. 74 -1. 88
1. 55 -1. 95
1. 8
1. 3 -1. 6
1. 5 -1. 6
1
.l -1. 5
1. 4
1
.l -1. 4
1
.l -1. 3
1. 2 -1. 3
1. 2
1
.l -1. 2
1
.o -1. 1
0.94-0.97
0.92
0.83-0. 91
0. 91
0.88-0. 91 ...
Alumina, A1203
Alkali halides
Magnesia, MgO
22.7
21. 4
13 .4 -1 9.6
19 .3
18 .9
14 .0 -1 7.0
16 .6 -1 6.9
10 .0 -1 3.7
1 1...
Engineering Materials vol 1 Part 4 potx
...
2.5
2.7
2.5
2.0
1. 85
0.6
0 .1
1. 5
1. 54
0.58
0.53
0.48
0.45
0 .15
0 .13
0 .1
3
0 .1
1
19 9
53
50
45
42
15
13
12
10
0.95
1. 1
0.95
0. 91
1
.o
0.4
1. 1
6.8
0.36
The yield ...
55
11 -55
45-48
7-45
19 -36
26- 31
20-30
20-30
6-20
1- 10
0.2 -1
0
1
-
-
-
10 0
200-400
40-70
300
60
35-55
14 -70
14 -60
33-36
58
37
30
20
4...
Engineering Materials vol 1 Part 6 ppsx
...
between eqns
(12 .1)
and
(12 .4)
gives
uy
66t 6
X
6.35
X
2
E
1
12 7
X
12 7
-
>-=
=
4.7
x
10 -3.
(12 .8)
Case studies in yield-limited design
12 1
Fig.
12 .2.
Stresses ...
M
=
4.rrr2tp (12 .11 )
so
that
M
t
=
4dp
Substituting for
t
in eqn.
(12 .8)
we find that
(12 .12 )
(12 .13 )
Case studies in yield-limited design
12 5
Ta...
Engineering Materials vol 1 Part 7 ppsx
... cause blunting.)
16 0
Engineering Materials
1
14 00
r
,
Pressure vessel steel
K,,
=
I70
MN
m
32
\
cry
=
10 00
MN
rn
\
\
E
800
-
10 00
200
-
0
01
01
1
10
10 0
Crack
size, ...
Buttenvorths, 19 73, Chap.
9.
T.
V.
hggan and
J.
Byrne,
Fatigue as a Design Criterion,
Macmillan, 19 77.
19 96.
15 2
Engineering Materials
1
1
Fast
fractu...
Engineering Materials vol 1 Part 8 pps
...
25
1
91. 7
13 5
15 0
19 7
14 2
10 9
270
460
556
326
84
14 7
76
16 8
14
19 .1
14 .9
16 .9
16 .6
15 .9
17 .5
9.3
17 .5
18 .3
21. 8
17 .9
17 .7
28.0
23.9
5.6
9.7
5 .1
11 .6
1
.o ...
31 10
3073
2750-2890
2650-27 41
2682-2684
2700
2323
21 73
214 8
2050- 21 25
2042
17 70 -1
935
18 09
15 70 -1 800
16 50 -1 768
15 50 -1 726
17 00...
Engineering Materials vol 1 Part 9 pot
... long
very long
2
x
10 6
1
06
1. 8
x
lo5
>io5
210 4
16 00
> ;1
OOO
> ;1
OOO
13 36
12 34
933
21 73
31
10
505
16 83
15 57
2042
923
692
21 48
3 71
337
Ni
cu
Fe
co
Ti ...
composition)
begins
to
limit
performance
500
1
I
I I
I
1
19 50 19 60 19 70
19 80
19 90
2000
2 010
Year
Fig.
20.7.
Temperature evolution and future ma...
Engineering Materials vol 1 Part 10 docx
...
Corrosion Engineering,
McGraw
Hill,
19 67,
Chap.
11 .
D.
R.
Gabe,
Principles
of
Metal Surface Treatment and Protection,
2nd edition, Pergamon Press.
19 78.
21
8
Engineering Materials
1 ... contamination.
2
C
-
TemperaturdK
2000
15 00
12 00
10 00
I
II
I1
I
I
I
\
I
I
I
I
I
I
I
I
4
6
8
10
1
O~IT/K-'
Fig.
22 .1.
The
way
in
which...
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