Engineering Materials vol 1 Part 1 docx
Engineering Materials vol 2 Part 1 doc
... 397 17
0.5 30 10 0 11 90 12 1 20
0.5 30 10 0 11 20 85 19
0.4 > ;10 0 17 28 450 89 13
0.5 > ;10 0 16 00 420 22 14
0.2 > ;10 0 15 50 450 11 12
0 .1 0.5 45 933 917 240 24
0 .1 0.45 45 915 24
0 .1 0.25 10 –50 ... coefficient
(MK
−
1
)
0.3 80 18 09 456 78 12
0. 21 140 17 65 482 60 12
0 .1 0.2 20–50 15 70 460 40 12
0 .1 0.2 50 17 0 17 50 460 40 12
0 .1 0.5 50 1...
Engineering Materials vol 2 Part 12 docx
... of structural materials
Material
E
r
s
r
y
K
IC
r
Woods 20–30 12 0 17 0 1 12
Al-alloy 25 17 9 8 16
Mild steel 26 30 18
Concrete 15 3 0.08
274 Engineering Materials 2
Fig. 25 .10 . Cell wall ... 0 .1 0.3 4 0.2 23 12 0.05 1. 2
Mahogany 0.53 13 .5 0.8 90 46 0.25 6.3
Douglas fir 0.55 16 .4 1. 1 70 42 0.34 6.2
Scots pine 0.55 16 .3 0.8 89 47 0.35 6 .1
Birch 0.62 16 .3 0....
Engineering Materials vol 2 Part 14 docx
... E
w||
= 11 .6 GPa, E
w⊥
= 0. 71 GPa and
ρ
w
= 0.39 Mg m
−3
. Equations
(28.22) and (28.23) then give us the following data.
f
||
(s
1
) ≈ 59 236 5 31 944 14 75 212 4 28 91 etc.
! 217 868 19 53 3472 ... A, pure B and pure C.
1. 8 (a) 1.
(b) 2.
(c) 1.
(d) 2.
1. 9 (a) 2.
(b) 63%, 37%.
(c) 95%, 5%.
(d) 0%, 10 0%.
1. 10 (a) 50%, 50%, 300°C.
(See Fig. A1.4.)
Fig. A1.4.
(b) Liqui...
Engineering Materials vol 2 Part 2 doc
... diagram at 18 3°C and connects (Sn) of 2.5 wt% lead, L of 38 .1% lead and (Pb) of
81% lead. Just above 18 3°C an alloy of tin + 38 .1% lead is single-phase liquid (Fig. 3.5).
Just below 18 3°C it is ... wt% lead + 98 wt% tin,
(b) one phase (just),
(c) 2 wt% lead,
(d) 10 0 wt% (Sn).
16 Engineering Materials 2
back to b.c.c. at 13 91 C; and titanium changes from c.p.h. to b.c.c. at 8...
Engineering Materials vol 2 Part 3 pot
...
at 10 00 K) 6 × 10
3
Solidification or melting (1 C departure from
T
m
) 8 to 22
Polymorphic transformations (1 C departure from
T
e
) 1 to 8
Recrystallisation (caused by cold working) 15
Precipitate ... we put r
1
= r
2
/2
in eqn. (5. 31) we get ∆A = −4
πγ
(−0 .17
r
2
2
). If
γ
= 0.5 J m
−2
and r
2
= 10
−7
m our two
precipitates give us a free work of 10
14
J, or abo...
Engineering Materials vol 2 Part 4 doc
... at annealing temperature
(°C) (minutes)
600 18 0 0
16 0 10
13 5 20
11 5 30
11 5 60
620 18 0 0
16 0 4
13 5 9
11 5 13
11 5 26
645 18 0 0
16 0 1. 5
13 5 3.5
11 5 5
11 5 10
Estimate the time that it takes for recrystallisation ... perhaps
910 °C. At 910 °C the critical radius is
r*
910
=
2
914 273
914 910
γ
αβ
∆H
( )
( )
+
−
=
2
γ
αβ
∆H
× 297. (8.4)
But at 900...
Engineering Materials vol 2 Part 5 pps
... alloys 2.7 71 25–600 26 3 .1 1.5 9–220 15 0–250
Mg alloys 1. 7 45 70–270 25 4.0 2 .1 41 16 0 15 0–250
Ti alloys 4.5 12 0 17 0 12 80 27 2.4 1. 1 38–280 400–600
(Steels) (7.9) ( 210 ) (220 16 00) 27 1. 8 0.75 28–200 ... alloy were aged at 15 0°C for
Table 10 .5 Yield strengths of work-hardened aluminium alloys
Alloy number
s
y
(MPa)
Annealed “Half hard”“Hard”
11 00 35 11 5 14 5
3...
Engineering Materials vol 2 Part 6 pot
... 0.60 1. 20 0.30 1. 50
C 0.36 0.70 1. 50 0.25 1. 50
D 0.40 0.60 1. 20 0 .15 1. 50
E 0. 41 0.85 0.50 0.25 0.55
F 0.40 0.65 0.75 0.25 0.85
G 0.40 0.60 0.65 0.55 2.55
11 6 Engineering Materials 2
Fig. 11 .3. ... 88.9%; Fe
3
C, 11 .1% .
·
·
700
600
500
400
300
200
10 0
0
10 0
1
10
10
2
10
3
10
4
Time(s)
M
F
M
50
M
S
a
b
1%
50% 99%
d
cf
e
Temperature (˚C)
·
·
·
·
·
·
·
·
·...
Engineering Materials vol 2 Part 7 pps
... K
−
1
) coefficient (K)
(K) (MK
−
1
)
10 0.7 (10 00) 990 1 8.5 84
10 0.8 (11 00) 800 1 4.0 280
– 1. 0 (14 00) 800 1 3 220
–– – 510 70 1. 2 10 00
10 3–5 2323 (14 70) 795 25.6 8.5 15 0
40 – 311 0 – 14 22 ... 14 22 84 4.3 300
40 4 217 3 – 627 17 3.2 500
10 4 12 2843 – 670 1. 5 8 500
10 5 –– 710 20–25 3.2 510
40 0.2 – 1. 8 10 14 #
<50
40 0.2 –– 210 14
$
– 0.9 –––8 #
1...
Engineering Materials vol 2 Part 9 pps
... has units of poise (P) or 10
1
Pa s. Glasses are worked in the temperature range in
which their viscosity is between 10
4
and 10
7
poise (Fig. 19 .8).
212 Engineering Materials 2
The best way ... (
η
= 10
13
poise) there is still enough fluidity to relax internal stresses in about
19 2 Engineering Materials 2
We may now specify the dimensions of the window. Inverting...