david roylance mechanics of materials Part 4 pot
david roylance mechanics of materials Part 4 pot
... Advanced Strength of Materials, McGraw-Hill, New York, 1952
12
The Kinematic Equations
David Roylance
Department of Materials Science and Engineering
Massachusetts Institute of Technology
Cambridge, ... mathematician Simeon Denis Poisson, (1781–1 840 ).
6
SHEAR AND TORSION
David Roylance
Department of Materials Science and Engineering
Massachusetts Institute of Technolo...
david roylance mechanics of materials Part 9 pot
...
Node # DOF 1 DOF 2 DOF 3 DOF 4 DOF 5 DOF 6
1 000000
2 0.013333 -0.03219 0000
3 0.02 -0.0 843 79 0000
4 000000
5 -0.0066667 -0.038856 0000
Element Stresses
1: 40 00
2: 2000
3: -2828 .4
4: 2000
5: ... =
k
(1)
11
k
(1)
12
k
(1)
13
k
(1)
14
00
k
(1)
21
k
(1)
22
k
(1)
23
k
(1)
24
00
k
(1)
31
k
(1)
32
k
(1)
33
+ k
(2)
11
k
(1)
34
+ k
(2)
12
k
(2)
13
k
(2)
14
k...
david roylance mechanics of materials Part 1 docx
... result
can also be written
7
ATOMISTIC BASIS OF ELASTICITY
David Roylance
Department of Materials Science and Engineering
Massachusetts Institute of Technology
Cambridge, MA 02139
January 27, ... Newtons. Also using A = πd
2
/4 to compute the diameter rather than the
area, we have
d =
4A
π
=
4P
f
πσ
f
=
4 × 10000(lb)
π × 600 × 10
6
(N/m
2
) × 1 .44 9 × 10
4
lb/in
2...
david roylance mechanics of materials Part 2 pdf
... 22–33
aramid 1 24 3.6 2.3 1 .45 86 2.5 22–33
boron 40 0 3.5 1.0 2 .45 163 1 .43 330 44 0
HS graphite 253 4. 5 1.1 1.80 140 2.5 66–110
HM graphite 520 2 .4 0.6 1.85 281 1.3 220–660
Of course, these materials ... neck.
5
INTRODUCTION TO COMPOSITE MATERIALS
David Roylance
Department of Materials Science and Engineering
Massachusetts Institute of Technology
Cambridge, MA 02139...
david roylance mechanics of materials Part 5 ppt
... +
∂u
∂y
dy
13
Transformation of Stresses and Strains
David Roylance
Department of Materials Science and Engineering
Massachusetts Institute of Technology
Cambridge, MA 02139
May 14, 2001
Introduction
One of the most ... RAR
−1
x
y
γ
xy
3
The Equilibrium Equations
David Roylance
Department of Materials Science and Engineering
Massachusetts Institut...
david roylance mechanics of materials Part 6 ppt
... 0
000.0289
e
ij
=
Σ
ij
2G
=
00.0378 0. 044 1
0.0378 0.0189 0.0567
0. 044 1 0.0567 −0.0189
The total strain is then
ij
=
1
3
kk
δ
ij
+ e
ij
=
0.00960 0.0378 0. 044 1
0.0378 0.0285 0.0567
0. 044 1 0.0567 −0.00930
If ... to 1.
2
Constitutive Equations
David Roylance
Department of Materials Science and Engineering
Massachusetts Institute of Technology
Cambridge,...
david roylance mechanics of materials Part 7 ppsx
... variation of stress as a function of height in a beam of
irregular cross section. Another common design or analysis problem is that of the variation of stress not
only as a function of height ... Strain, McGraw-Hill,
New York, 1989.
9
Beam Displacements
David Roylance
Department of Materials Science and Engineering
Massachusetts Institute of Technology
Cambridge, MA 0213...
david roylance mechanics of materials Part 8 doc
... matrix:
0.1185E+12 0.1653E+10 0.2 942 E+ 04 -0.2798D+11 0.0000D+00 0.7354D+03
0.1653E+10 0.1185E+12 0.1389E+06 0.0000D+00 0.2798D+11 0. 347 3D+05
0.2 942 E+ 04 0.1389E+06 0 .48 00E+10 0.7354D+03 0. 347 3D+05 0.0000D+00
-0.2798E+11 ... −
a
2
r
2
+
σ
2
1+
3a
4
r
4
−
4a
2
r
2
cos 2θ
σ
θ
=
σ
2
1+
a
2
r
2
−
σ
2
1+
3a
4
r
4
cos 2θ (19)
τ
rθ
= −
σ
2
1 −
3a
4
r
4
+
2a
2...
david roylance mechanics of materials Part 10 ppt
... x=1.19 644 y=-0 z=0
3 x=0.9 845 62 y=0.167939 z=0 constraint=free
4 x=0. 940 6 34 y=0.335 841 z=0
5 x=1.07888 y=0.235833 z=0
.
.
.
72 x=3.99602 y=3.01892 z=0
73 x=3.99602 y=3.51 942 z=0
74 x=3.33267 y =4 z=0
75 ... (3,1)
13
ENGINEERING VISCOELASTICITY
David Roylance
Department of Materials Science and Engineering
Massachusetts Institute of Technology
Cambridge, MA 02139
Octobe...
david roylance mechanics of materials Part 11 ppsx
... Plastic Flow
David Roylance
Department of Materials Science and Engineering
Massachusetts Institute of Technology
Cambridge, MA 02139
October 15, 2001
Introduction
In our overview of the tensile ... 0
◦
C for the polyurethane of
Prob. 18 gives the following values of E
rel
(t)atvarioustimes:
log(t, min) E
rel
(t), psi
-6 56,280
-5 22,880
-4 4 ,45 0
-3 957
-2 578
-1 48 1
0...