david roylance mechanics of materials Part 1 docx
david roylance mechanics of materials Part 1 docx
... ET
m
∆H α
L
GPa (Mpsi)
◦
C kJ/mol 10
−6
,
◦
C
1
Pb 14 (2) 327 5.4 29
Al 69 (10 ) 660 10 .5 22
Cu 11 7 (17 ) 10 84 13 .5 17
Fe 207 (30) 15 38 15 .3 12
W 407 (59) 3 410 32 4.2
The system will generally ... ELASTICITY
David Roylance
Department of Materials Science and Engineering
Massachusetts Institute of Technology
Cambridge, MA 0 213 9
January 21, 2000
Introduction
Thi...
david roylance mechanics of materials Part 13 docx
... 0.2 012 0 .19 89 0 .19 65
1. 2 0 .19 42 0 .19 19 0 .18 95 0 .18 72 0 .18 49 0 .18 26 0 .18 04 0 .17 81 0 .17 58 0 .17 36
1. 3 0 .17 14 0 .16 91 0 .16 69 0 .16 47 0 .16 26 0 .16 04 0 .15 82 0 .15 61 0 .15 39 0 .15 18
0.4 0 .14 97 0 .14 76 0 .14 56 ... 0 .14 76 0 .14 56 0 .14 35 0 .14 15 0 .13 94 0 .13 74 0 .13 54 0 .13 34 0 .13 15
1. 5 0 .12 95 0 .12 76 0 .12 57 0 .12 38 0 .12 19 0 .12 0...
david roylance mechanics of materials Part 2 pdf
... 22–33
aramid 12 4 3.6 2.3 1. 45 86 2.5 22–33
boron 400 3.5 1. 0 2.45 16 3 1. 43 330–440
HS graphite 253 4.5 1. 1 1. 80 14 0 2.5 66 11 0
HM graphite 520 2.4 0.6 1. 85 2 81 1.3 220–660
Of course, these materials ... U(kJ/mol) U
expt
LiF 2 01. 4 6. 710 e+ 01 1.750 -10 14
NaCl 282.0 2.400e+ 01 1.750 -764
KBr 329.8 1. 480e+ 01 1.750 -663
The column labeled U
expt
lists experiment...
david roylance mechanics of materials Part 4 pot
... Strength of Materials, McGraw-Hill, New York, 19 52
12
The Kinematic Equations
David Roylance
Department of Materials Science and Engineering
Massachusetts Institute of Technology
Cambridge, MA 0 213 9
Septemb ... Simeon Denis Poisson, (17 81 18 40).
6
SHEAR AND TORSION
David Roylance
Department of Materials Science and Engineering
Massachusetts Institute of Technolo...
david roylance mechanics of materials Part 5 ppt
... +
∂u
∂y
dy
13
Transformation of Stresses and Strains
David Roylance
Department of Materials Science and Engineering
Massachusetts Institute of Technology
Cambridge, MA 0 213 9
May 14 , 20 01
Introduction
One of the most ... displacements.
x
=
O
1
B
1
− OB
OB
= O
1
B
1
− 1
=
1+ 2
∂u
∂x
+
∂u
∂x
2
+
∂v
∂x
2
1
Using the series expansion
√
1+ x =1+ x/2+x...
david roylance mechanics of materials Part 6 ppt
... axes is then
S = RA
1
R
1
SA =
.8830 × 10
10
− .19 70 × 10
10
− .12 22 × 10
−9
− .19 71 × 10
10
.2072 × 10
−9
−.83 71 × 10
10
− .12 22 × 10
−9
−.8369 × 10
10
−.2905 × 10
−9
Note that this ... E
2
=4,G
12
=2.8(allGPa)and
ν
12
=0.25. The compliance matrix S in the 1- 2 (material) direction is:
S =
1/ E
1
−ν
21
/E
2
0
−ν
12
/E
1
1/E
2
0...
david roylance mechanics of materials Part 7 ppsx
... equation:
q(x)=R
a
x
1
+R
b
x−7.5
1
+R
c
x 15
1
− 10 x
0
V (x)=−
q(x)dx = −R
a
x
0
− R
b
x − 7.5
0
− R
c
x − 15
0
+10 x
1
M(x)=−
V(x)dx = R
a
x
1
+ R
b
x − 7.5
1
+ R
c
x − 15
1
−
10
2
x
2
EIy
(x)=
M(x)dx ... Eqn. 5 to obtain
∂M
∂P
=
1
2
x
1
−x−
L
2
1
Then
δ
P
=
1
EI
L
P
2
x
1
− Px −
L
2
1
1
2
x
1
−x−
L...
david roylance mechanics of materials Part 8 doc
... 0.2548E -10 -0. 215 0E -15 0.3253D -18 -0.7 218 D -10 -0 .12 28D -15
-0 .16 39E -16 -0. 215 0E -15 0.2083E-09 -0.6022D -16 -0 .12 28D -15 0.2228D -19
0.7 218 E -10 0 .10 84E -18 -0.6022E -16 0.3058D-09 -0.4265D -11 -0 .19 67D -15
0.6 214 E-22 ... strain
14
Sbar :=
.8828 10
10
− .19 68 10
10
− .12 22 10
−9
− .19 69 10
10
.20 71 10
−9
−.8370 10
10
− .12 22 10
−9
−....
david roylance mechanics of materials Part 9 pot
... =
k
(1)
11
k
(1)
12
k
(1)
13
k
(1)
14
00
k
(1)
21
k
(1)
22
k
(1)
23
k
(1)
24
00
k
(1)
31
k
(1)
32
k
(1)
33
+ k
(2)
11
k
(1)
34
+ k
(2)
12
k
(2)
13
k
(2)
14
k
(1)
41
k
(1)
42
k
(1)
43
+ k
(2)
21
k
(1)
44
+ ... Displacements
Node # DOF 1 DOF 2 DOF 3 DOF 4 DOF 5 DOF 6
1 000000
2 0. 013 333 -0.03 219 0000
3 0.02 -0.084...
david roylance mechanics of materials Part 10 ppt
... load=load_case _1
8 nodes=[68,58,67]
9 nodes=[57,58,68] load=load_case _1
10 nodes=[57, 51, 58]
11 nodes=[52, 51, 57] load=load_case _1
12 nodes=[37,39,52] load=load_case _1
13 nodes=[39, 51, 52]
.
.
.
11 6 nodes=[2,3 ,1]
material ... nodes=[2,3 ,1]
material properties
steel E=2.05e +11 nu=0.33 t =1
distributed loads
load_case _1 color=red direction=GlobalY values= (1, 1) (3 ,1)
13...
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