Dynamics of Mechanical Systems 2009 Part 1 ppsx

Dynamics of Mechanical Systems 2009 Part 1 ppsx

Dynamics of Mechanical Systems 2009 Part 1 ppsx

... AAn An An=++ 11 22 33 BBn Bn Bn=++ 11 22 33 AB A A A B B B AB AB AB AB AB AB AB AB ⋅= + + () ⋅++ () =⋅+⋅+⋅ +⋅+⋅+⋅ +⋅+⋅ 11 22 33 11 22 33 11 1 1 12 1 2 13 1 3 212 1 32 3 2 23 2 3 313 1 32 3 2 nnnnnn nn ... Forces 375 11 .9 Generalized Forces: Inertia (Passive) Forces 377 11 .10 Examples 379 11 .11 Potential Energy 389 11 .12 Use of Kinetic Energy to Obtain Genera...
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Dynamics of Mechanical Systems 2009 Part 2 potx

Dynamics of Mechanical Systems 2009 Part 2 potx

... Eqs. (2 .11 .6) and (2 .11 .7). By substituting from Eqs. (2 .11 .6) and (2 .11 .7) into Eqs. (2 .11 .1) and (2 .11 .2), we obtain: (2 .11 .8) and (2 .11 .9) Hence, we have: (2 .11 .10 ) Observe that Eq. (2 .11 .10 ) ... =− AAA BBB CCC BBB CCC AAA CCC AAA BBB mp BBB AAA CCC AAA CCC BBB CCC BB 12 3 12 3 12 3 12 3 12 3 12 3 12 3 12 3 12 3 12 3 12 3 12 3 12 3 12 3 12 3 12 3 12...
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Dynamics of Mechanical Systems 2009 Part 3 pptx

Dynamics of Mechanical Systems 2009 Part 3 pptx

... ⋅       +⋅       n n nn n nn n nn n n nn n nn 1 2 31 3 12 1 23 1 3 13 1 22 nn nn 11 13 10 ⋅= ⋅= and d = 0 and 1 n n n nn n 11 31 3 dt d dt d dt ⋅⋅=−⋅ RB d dt d dt d dt ωω× = ⋅       +⋅       +⋅       n n nn n nn n nn 1 1 11 1 22 1 33 RB ddtωω× ... obtain: (4 .13 .10 ) RB ωω= + +ωωω 11 22 33 nnn R GRB RGRB rrVn V n=× =×− () ωωωω 21...
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Dynamics of Mechanical Systems 2009 Part 4 docx

Dynamics of Mechanical Systems 2009 Part 4 docx

... aNN G XZ 1 111 2 11 11 2 1 2= () − () +− − () [] l ˙˙ cos ˙ sin ˙˙ sin ˙ cosθθθθ θθθθ vn ann OO 22 1 11 1 11 1 2 13 ==−lll ˙˙˙˙ θθθ and vNN O XZ 2 11 1 =− () l ˙ cos sinθθ θ aNN O XZ 2 11 1 2 11 11 2 1 =− () +− ... + () ==−− 12 334 567 13 311 2 32 2 13 223 0 3 10 4 15 3 8 4 8 0 12 12 16 30 60 24 32 11 31 144 19 2−+nn Mnnn O =− 16 0 30 16 8 12 3 ftlb 059...
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Dynamics of Mechanical Systems 2009 Part 5 pps

Dynamics of Mechanical Systems 2009 Part 5 pps

... ab ab 11 22 33 11 22 33 11 11 1 212 13 13 212 1 2222 2323 313 1 3222 3333 0593_C07_fm Page 203 Monday, May 6, 2002 2:42 PM 230 Dynamics of Mechanical Systems where we have made use of Eqs. (7 .12 .4) ... z III III III =++ =++ =++ Innnn Innnn Innnn 1 11 1 12 2 13 3 1 2 21 1 22 2 23 3 2 3 31 1 32 2 33 3 3 PO jj PO jj PO jj III I III I III I =++= =++= =++= In i PO ij i...
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Dynamics of Mechanical Systems 2009 Part 6 pdf

Dynamics of Mechanical Systems 2009 Part 6 pdf

... 8 .10 .4 Free-body diagram of rod B 2 . nnnnnn nnnnnn 11 1 1 1 2 21 2 1 2 2 12 1 1 1 2 22 2 1 2 2 =+ =+ =− + =− + cs cs sc sc , , nc s nc s ns c ns c 1 1 11 1 12 1 2 21 2 22 2 1 11 1 12 2 2 21 2 22 =− =− =− ... nnnnnn nnnn nn 11 2 1 21 2 1 22 21 2 1 11 2 1 12 12 2 1 21 2 1 22 22 2 1 11 2 1 22 =− =+ =+ =−+ −− −− −− −− cs cs sc sc , , Fa...
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Dynamics of Mechanical Systems 2009 Part 7 pps

Dynamics of Mechanical Systems 2009 Part 7 pps

... m y ω vvv v 02 10 2 0 2 20 21 1 2 212 2 11 2 12 2 11 2 −− () +− () = () − () [] + () − () −− () [] + () ll l l llll ωω ω ω ωωωω 12 2 11 2 02 1 1 () −− () [] = () v ll lωω ω v 01 2 512 11 12= () + () llωω v 012 23= () +llωω ωω ... ii i N i i N i Gi =+⋅×+× () =       +⋅×       +× () =++ === === ∑∑∑ ∑∑∑ 1 2 1 2 1 2 1 2 1 2 0 1 2 2 11 2 1 1 2 11 2 2 vv...
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Dynamics of Mechanical Systems 2009 Part 8 docx

Dynamics of Mechanical Systems 2009 Part 8 docx

... be: (11 .7 .1) and (11 .7.2) (11 .7.3) (11 .7.4) where n 1 , n 2 , and n 3 are the unit vectors of Figures 11 .7.2 and 11 .7.3. From Eqs. (11 .4.4) and (11 .4 .15 ) we obtain the partial velocities and partial ... , x P x P x PP x P x P x P P x P x P x PP x x 1 1 2 1 3 11 1 2 2 2 3 2 3 1 3 2 3 3 3 11 2 12 2 1 00 002 00 ====+ () == ==+ () === θ θ θ l l 33 3 32 =+ () l...
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Dynamics of Mechanical Systems 2009 Part 9 potx

Dynamics of Mechanical Systems 2009 Part 9 potx

... Generalized Dynamics: Kane’s Equations and Lagrange’s Equations 419 or (12 .2 .16 ) and or (12 .2 .17 ) In Sections 11 .10 and 11 .12 , Eqs. (11 .10 . 21) , (11 .10 .22), (11 .12 .14 ), and (11 .12 .15 ), we found ... Figure P 11. 11. 9. Repeat Problems P 11. 11. 6 and P 11. 11. 7 finding the potential energies for the relative orientation angles. P 11. 11. 10: Use the results of P...
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Dynamics of Mechanical Systems 2009 Part 10 pot

Dynamics of Mechanical Systems 2009 Part 10 pot

... F(A, ψ) is: (13 .10 .14 ) Then, Eqs. (13 .10 .4) and (13 .10 .5) become: (13 .10 .15 ) and (13 .10 .16 ) Upon integration of Eqs. (13 .10 .15 ) and (13 .10 .16 ) we obtain: (13 .10 .17 ) and (13 .10 .18 ) where φ 0 is ... (13 .8 .11 ), (13 .8 .12 ), and (13 .8 .13 ) in the form of Eqs. (13 .8 .14 ), (13 .8 .15 ), and (13 .8 .16 ). The derivatives of ξ 1 , ξ 2 , and ξ 3 may be e...
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