Fundamentals of Polymer Engineering Part 2 pdf

... 0) N N N N N N NN NN H 2 N H 2 NNH 2 NH 2 NH 2 NH 2 NH 2 NH 2 H 2 N H 2 N H 2 N H 2 N Terminal groups Initiator core ‘Dendrimers’ Generations Dendrimer repeating units 0 1 2 (1 .2. 3a) N NHC CNH CNH O O O NH 2 H 2 N NH 2 H 2 N N NH 2 NH 2 NH 3 6Chapter1 Copyright ... the branches of the hyper branched polymer (called dendrimers). In these polymers, (A...

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... Inc. 4.2AnalysisofSemibatchReactors156 4.3MWDofARBPolymerizationinHomogeneous Continuous-FlowStirred-TankReactors166 4.4AdvancedStageofPolymerization169 4.5Conclusion174 Appendix4.1:SimilaritySolutionofStep-Growth PolymerizationinFilmswithFiniteMassTransfer175 References181 Problems181 5.Chain-GrowthPolymerization188 5.1Introduction188 5.2RadicalPolymerization1 92 5.3KineticModelofRadicalPol...

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... in the auto-oxidation of Table 2. 2; TABLE 2. 2 Mechanism of Auto-oxidation and Role of Antioxidants Initiation M n À! hn P n P n þ O 2 À! P n ÀO 2 P n þ O 2 þ M n H À! M n O 2 H M n Propagation Termination Peroxide ... Inc. higherthehardnessandmodulus.Anotherfactorthatplaysamajorrolein determiningthefinalpropertyofthepolymeristhechemicalnatureofthe surface.Mineralfillerssuchasc...

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... reacted CH 2 OH groups. A þ H 2 O ! k 3 U þ FðCH 2 OHÞð3:7 :25 aÞ B þ H 2 O ! 2k 3 A þ FðCH 2 OHÞð3:7 :25 bÞ C þ H 2 O ! 2k 3 A þ FðCH 2 OHÞð3:7 :25 cÞ D þ H 2 O ! k 3 B þ FðCH 2 OHÞð3:7 :25 dÞ D þ H 2 O ... CH 2 . A þ H 2 O ! k 3 U þðCH 2 OHÞZ ð3:7 :26 aÞ B þ H 2 O ! 2k 3 A þðCH 2 OHÞZ ð3:7 :26 bÞ C þ H 2 O ! 2k 3 A þ F þðCH 2 OHÞZ ð3:7 :26...

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... 4g 1 g 3 Þ 0:5 2g 1 ð4 :2: 20aÞ d 2 ¼ g 2 ðg 2 2  4g 1 g 3 Þ 0:5 2g 1 ð4 :2: 20bÞ A 1 ¼ b 0 d 1 d 2 g 1 ð4 :2: 20cÞ A 2 ¼ b 0 þ b 1 d 1  b 2 d 2 1 d 1 g 1 ðd 1  d 2 Þ ð4 :2: 20dÞ A 3 ¼ b 0 þ b 1 d 2  b 2 d 2 2 g 1 d 2 ðd 1  ... l 0 Þð4 :2: 26Þ which can be easily integrated to give l 0 from q q 0 ¼ exp  dt V 0  ð4 :2: 27Þ where d ¼ðm 2 1 þ 4m 0 m 2 Þ 1 =2...

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... composition of the polymer. Emulsion Polymerization 339 Copyright © 20 03 Marcel Dekker, Inc. 6.AllofthetransferreactionrateconstantsK 20 toK 32 havebeenassumed tobeequal;thatis,K 20 ¼K 21 ¼K 22 ¼K 32 ¼K tr (say).Thevalueof K tr thatgivesgoodfitofthedataat60  Cis1060mL=ghr. TheordinarydifferentialequationsofTable7.3canbesolved numericallyandtheresultshavebeenplottedinFigure7....

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... Wt% 2. 800 0.0 4.014 15 .2 5.065 90.7 2. 865 0.005 4.070 18.1 5.113 92. 2 2. 929 0. 020 4. 126 21 .5 5.161 93.7 2. 9 92 0.0 52 4.1 82 25 .2 5 .20 9 94.8 3.056 0.105 4 .23 7 29 .3 5 .25 6 95.8 3.119 0.185 4 .29 2 33.7 ... angle, y (deg) 0.00 02 0.0004 0.001 0.0 02 25.8 3.49 5. 82 7.86 8.65 36.9 2. 98 4.88 7.38 8. 02 53.0 2. 19 3. 82 6.37 7.41 66.4 1.74 3. 12 5.58 6.88 90.0 1...

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... following: @f 1 @n 1 ¼ f 2 n 1 þ mn 2 ð9:3 :26 Þ @f 1 @n 2 ¼À mf 1 n 1 þ mn 2 ð9:3 :27 Þ @f 2 @n 1 ¼À f 2 n 1 þ mn 2 ð9:3 :28 Þ @f 2 @n 2 ¼ mf 1 n 1 þ mn 2 ð9:3 :29 Þ Thermodynamics of Polymer Mixtures 387 Copyright © 20 03 ... w 1 n 1 @f 2 @n 1  ð9:3 :24 Þ m 2 ¼ @G mixture @n 2 ¼ g 2 þ RT n 1 f 1 @f 1 @n 2 þ ln f 2 þ n 2 f 2 @f 2 @n 2 þ w 1 n 1...

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... ¼ð2npÞ À3 =2 ðl 2 x l 2 y l 2 z Þ À1 =2 exp À 1 2n x 2 l 2 x þ y 2 l 2 y þ z 2 l 2 z !"# dx dy dz ð10 :2: 10Þ Denoting the sum ðx 2 þ y 2 þ z 2 Þ as r 2 and recalling that l 2 x ¼ l 2 y ¼ l 2 z ¼ ... follows: n þ ¼ 1 2 ðn þ mÞð10 :2: 2Þ n À ¼ 1 2 ðn À mÞð10 :2: 3Þ For large n we can use Stirling’s formula: n! ¼ ffiffiffiffiffiffi 2p p n ð2nþ1Þ =2 e n ð10 :2: 4...

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... melting temperatures of poly(phenylene sulfide) [76]. Their data are given as follows: T c (  C) T m (  C) 26 0 28 3 26 5 28 7 27 0 29 0 27 5 29 4 28 0 29 8 What is the equilibrium melting temperature T 0 m ? 11. 12. If ... Row Nucleation in Polymers, J. Macromol. Sci. Phys., B 12, 423 – 428 , 1976. 45. Ziabicki, A., Theoretical Analysis of Oriented and Nonisothermal Crystalliz...

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