... False-negative rate = FN/(TP+FN) True-positive rate = 1 – false-negative rate Identification of Patients without Disease True-negative rate (specificity) = TN/(TN+FP) False-positive ... Table 3-1 Measures of Diagnostic Test Accuracy Disease Status Test Result Present Absent Positive True-positive (TP) False-positive (FP) Negative False-negative (FN) True-negative ... a neg...
Ngày tải lên: 06/07/2014, 08:20
... in favor of the more informative posttest probability. Chapter 003. Decision-Making in Clinical Medicine (Part 6) Calculating sensitivity and specificity requires selection of a decision ... graphically as a receiver operating characteristic (ROC) curve (Fig. 3-1 ). An ROC curve plots sensitivity (y-axis) versus 1 – specificity (x-axis). Each point on the curve represents a...
Ngày tải lên: 06/07/2014, 08:20
Chapter 064. The Practice of Genetics in Clinical Medicine (Part 1) pptx
... management of Chapter 064 . The Practice of Genetics in Clinical Medicine (Part 1) Harrison's Internal Medicine > Chapter 64 . The Practice of Genetics in Clinical Medicine Implications ... genetic medicine have outpaced the translation of these discoveries into standards of clinical care. Common Adult-Onset Genetic Disorders Multifactorial Inheritance T...
Ngày tải lên: 07/07/2014, 01:20
Chapter 064. The Practice of Genetics in Clinical Medicine (Part 2) pptx
... form of a pedigree. At a minimum, pedigrees should convey health-related data on all first-degree relatives and selected second-degree relatives, including grandparents. When pedigrees appear ... first-degree relatives with breast cancer is at greater risk for a Mendelian disorder if she has a total of three female first-degree relatives than if she has a total of ten female first-degree...
Ngày tải lên: 07/07/2014, 01:20
Chapter 064. The Practice of Genetics in Clinical Medicine (Part 5) pptx
... understand the risks, benefits, and limitations of undergoing the Chapter 064 . The Practice of Genetics in Clinical Medicine (Part 5) Molecular analysis is generally more informative if testing ... decision-making process, as molecular diagnostics will likely have an impact on the entire family. Informed consent for molecular testing begins with detailed education and counselin...
Ngày tải lên: 07/07/2014, 01:20
Chapter 064. The Practice of Genetics in Clinical Medicine (Part 6) pot
... that the at-risk family members have access to the resources necessary to adhere to these recommendations. Chapter 064 . The Practice of Genetics in Clinical Medicine (Part 6) Follow-Up Care ... values factor into a particular medical decision. Nondirective counseling is particularly appropriate when there are no data demonstrating a clear benefit associated with a particular...
Ngày tải lên: 07/07/2014, 01:20
Tài liệu Master toefl vocabulary part 6 pptx
... rule for the nega- tive prefixes is il before l ; im before b , m , or p ; ir before r ; and in or un before other letters. 03_TOEFL Vocab,Ch3,2 7 -6 0 8/4/ 06, 12:30 46 42 PART III: TOEFL ... is 7. n. The correct answer is 10. o. The correct answer is 14. 03_TOEFL Vocab,Ch3,2 7 -6 0 8/4/ 06, 12:3049 46 PART III: TOEFL Vocabulary Review ○○○○○○○○○○○○○○○○○○○○○○○○○○○○○○○○○○...
Ngày tải lên: 14/12/2013, 13:15
Tài liệu Minimization or Maximization of Functions part 6 pptx
... point. ptt[j]=2.0*p[j]-pt[j]; xit[j]=p[j]-pt[j]; pt[j]=p[j]; } fptt=(*func)(ptt); Function value at extrapolated point. if (fptt < fp) { t=2.0*(fp-2.0*(*fret)+fptt)*SQR(fp-(*fret)-del)-del*SQR(fp-fptt); if ... RECIPES IN C: THE ART OF SCIENTIFIC COMPUTING (ISBN 0-5 2 1-4 310 8-5 ) Copyright (C) 198 8-1 992 by Cambridge University Press.Programs Copyright (C) 198 8-1 992 by Numer...
Ngày tải lên: 15/12/2013, 04:15
Tài liệu Integration of Functions part 6 pptx
... each array not used. 0 .67 9409 568 2,0. 865 063 366 6,0.9739 065 285}; static float w[]={0.0,0.2955242247,0. 269 266 7193, 0.2190 863 625,0.1494513491,0. 066 6713443}; xm=0.5*(b+a); xr=0.5*(b-a); s=0; Will be twice ... { sig[k][l]=sig[k-1][l+1]+(alpha[l-1]-a[k-2])*sig[k-1][l ]- b[k-2]*sig[k-2][l]+beta[l-1]*sig[k-1][l-1]; } a[k-1]=alpha[k-1]+sig[k][k+1]/sig[k][k]-sig[k-1][k]/sig[k-1][k-1];...
Ngày tải lên: 15/12/2013, 04:15