Strength Analysis in Geomechanics Part 1 ppsx
Strength Analysis in Geomechanics Part 1 ppsx
... of structures Strength Analysis in Geomechanics Serguey A. Elsoufiev With 15 8 Figures and 11 Tables Contents 1 Introduction: Main Ideas 1 1 .1 Role of Engineering Geological Investigations . ... . . . . . . . . . . . . . . 16 6 1 Introduction: Main Ideas 1. 1 Role of Engineering Geological Investigations An estimation of conditions of buildings and structures installation...
Ngày tải lên: 10/08/2014, 12:21
Strength Analysis in Geomechanics Part 9 ppsx
... 2ψ) +cotχ(g µ sin 2ψ) + 4 (1 − µ)g µ cos 2ψ. (5 .11 6) Putting (3 .11 5) into (2.78) we derive (g µ sin 2ψ) +(g µ sin 2ψ) cot χ +(9µ (1 − µ) − 1/ sin 2 χ)g µ sin 2ψ + 2(2 − 3µ)(g µ cos 2ψ) =0. (5 .11 7) Combining ... (5 .12 9) σ θ =p (1 µ)(b/r) µ / (1 − β µ 1 ) (5 .13 1) where β = b/a. Putting σ θ into (2.66) we find for the dangerous (internal) surface e −αε ε =3β (1 − µ) m Ω(t...
Ngày tải lên: 10/08/2014, 12:21
Strength Analysis in Geomechanics Part 2 ppt
... compression and torsion (Fig. 1. 13) the solution of (1. 18), (1. 19) can be presented in form (M/M ∗ ) 2 +F/F ∗ = 1 (1. 20) 16 1 Introduction: Main Ideas F M l 2r M F Fig. 1. 13. Circular bar under compression ... The 1. 4 Main Properties of Soils 11 Ot 1 2 3 S Fig. 1. 9. Combined in uence of time and loading Combined In uence of Time and Loading At small loads F the settli...
Ngày tải lên: 10/08/2014, 12:21
Strength Analysis in Geomechanics Part 4 potx
... −(2p/π) 1 1 (y 2 +(x− η) 2 ) −2 dη or after integration σ y =p(υ 1 − υ 2 +0.5(sin 2υ 1 − sin 2υ 2 ))/π. (3.52) Similarly we find σ x =p(υ 1 −υ 2 +0.5(sin 2υ 2 −sin2υ 1 ))/π, τ xy = p(sin 2 υ 1 −sin 2 υ 2 )/π. ... σ r =(K 1 / √ 2πr) (1 + sin 2 (θ/2)) cos(θ/2), τ rθ =(K 1 /2 √ 2πr) sin θcos(θ/2), τ e =(K 1 /2 √ 2πr) sin θ, (3.90) u r =(K 1 /G) r/2π(0.5(κ +1) − cos 2 (θ...
Ngày tải lên: 10/08/2014, 12:21
Strength Analysis in Geomechanics Part 5 potx
... again can see that τ e in (3 .10 6), (3 .11 0) differ by a constant multiplier. 3.2 .13 Inclined Crack in Tension By a combination of the solutions in Sects. 3.2.7, 3.2 .11 a strength of a body with inclined ... =r/aandz=0are u z (ρ, 0) = 4 (1 −ν 2 )pa 1 − ρ 2 /πE(ρ ≤ 1) , σ z = 2p (1/ ρ 2 − 1 − sin 1 (1/ ρ))/π (ρ > 1) . (3 .15 0) Since near the crack edges the first me...
Ngày tải lên: 10/08/2014, 12:21
Strength Analysis in Geomechanics Part 6 ppt
... k 1 1 − (k 1 ) 2 − sin 1 k 1 = (1 k 1 )(−p − (1 − k 1 )l/4h). (4 .18 ) Then we take integral equilibrium equation at contact surface as 2Q = τ yi (1 + k 1 )l which gives 1 + k 1 = 2q where q ... rigid plates. Putting in (4 .12 ) τ = τ e sin 2ψ, σ r − σ θ =2τ e cos 2ψ (4 .13 ) a) b) P Fig. 4.4. Slip lines 4.2 Plane Deformation 10 3 0 1 1 2 1 0 11 0 0 45 90 13...
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Strength Analysis in Geomechanics Part 7 pdf
... 11 7 we have R 1 =P 1 sin α 1 − P 1 cos α 1 tan ϕ 1 − c 1 L 1 , R 2 =P 2 sin α 2 − P 2 cos α 2 tan ϕ 2 − c 2 L 2 +R 1 cos(α 1 − α 2 ) or R i =P i sin α i − P i cos α i tan ϕ i − c i L i +R i 1 cos(α i 1 − ... supposing tan(C − θ)= √ x we receive 4dln(f/D) = (1 − (m + 1) 2 + 4mx)dx/x (1 + x). (5.5) and after integration we find f=D(( √ − m +1) /( √ +m− 1) ) (m 1) /...
Ngày tải lên: 10/08/2014, 12:21
Strength Analysis in Geomechanics Part 8 docx
... m J=0.5K m +1 m(2m + 1) /f (π)/ m 1 f (π) 1 0 ( (1 −ξ)/ξ) 1/ (1+ m) dξ. Using equation J = J 1 we have K=((κ +1) πσ 2 l/4GΩ 1 (t)I 1 (m)) 1/ (1+ m) . Here I 1 (m) = (2m +1) (m +1) /f (π)/ m 1 f (π)Γ((2m +1) /(m +1) )Γ((2+m)/ (1+ m)) and ... σ θ =Kr 1/ (m +1) s(s 1) f, τ rθ =Kr 1/ (m +1) (1 −s)f (5.92) and ε θ = −0.5Ω 1 (t)K m r −m/(m +1) F m 1 (f ...
Ngày tải lên: 10/08/2014, 12:21
Lập Trình C# all Chap "NUMERICAL RECIPES IN C" part 1 ppsx
... 1, 0) (9, 4, 0) (59, 6, 5, 4, 3, 1, 0) (10 , 3, 0) (60, 1, 0) (11 , 2, 0) ( 61, 5, 2, 1, 0) (12 , 6, 4, 1, 0) (62, 6, 5, 3, 0) (13 , 4, 3, 1, 0) (63, 1, 0) (14 , 5, 3, 1, 0) (64, 4, 3, 1, 0) (15 , 1, ... single full-word exclusive-or operation: #define IB1 1 Powers of 2. #define IB2 2 #define IB5 16 #define IB18 13 1072 #define MASK (IB1+IB2+IB5) int irbit2(unsigned long...
Ngày tải lên: 01/07/2014, 10:20
A Complete Guide to Programming in C++ part 1 ppsx
... 0-7637 -18 17-3 1. C++ (Computer program language) I. Kirch-Prinz, Ulla. II. Title. QA76.73.C153 P73 713 20 01 005 .13 '3—dc 21 20 010 29 617 2090 Chief Executive Officer: Clayton Jones Chief Operating ... string, which is used to repre- sent strings. In addition to defining strings, the chapter looks at the various methods of string manipulation. These include inserting and erasin...
Ngày tải lên: 06/07/2014, 17:21