Mechanics of Materials 1 Part 5 pps

... 0.02 25+ 0.06 258 x 0 . 15 El x 0. 01 +0.06 258 (-0 .1) 1 =- { (1. 25 x 2. 25 W+6. 25 x 1. 5H)- (1. 25 W-6. 258 )) EI x 10 3 1 { (2. 81 W + 9.3 758 ) - (1. 25 W - 6. 258 ) 1 - EI x 10 3 ... EI x 10 3 1 =- (1. 56 W+ 15 .6 258 ) EI x 10 3 Now the total horizontal deflection of A = 0 -3 .12 5 W+ 5. 2088 + 1. 56 W+ 15 .6...

Ngày tải lên: 10/08/2014, 12:21

... 0 1 2 2 3 4 5 6 0 10 0~ 6= 600 10 0x12 =12 00 12 00 13 20 14 40 16 80 19 56 - 72 69 69 68 66.3 61. 6 54 .5 - 10 0 10 0 12 12 12 12 12 - 3.2 6.2 51 . 3 55 .6 59 .1 64 .1 66.0 ... moments of area about the base. (10 0 x 10 0 x 50 )10 -’- (50 x 50 x 25 )10 -’ = (10 0 x 10 0- 50 x 50 )j x lo-’ 50 0000 - 6 250 0 = (lo...

Ngày tải lên: 10/08/2014, 12:21

... 0,)' + 4~2 ~1 336 Mechanics of Materials $13 .7 re I up =ux uq =uy =o r,, :O 1 1 1 I 1 I I O0 45& quot; 90" 13 5& apos; 18 0" 2 25& apos; 270" 3 15 ' ? 3"8 ... T. (14 .16 ) Similarly, (14 .17 ) 358 Mechanics of Materials Fig. 13 .36. Therefore at the junction of web and flange 75 x 10 3 x 0.07...

Ngày tải lên: 10/08/2014, 12:21

... 14 0)2} 5. 76 x 10 4 = f C1.96 + 0.203 + 3.4 21 lo4 n2 2 x 5. 76 x 10 4 n2 = = 2.063 5. 583 x lo4 n = 1. 44 The required factor of safety is now 1. 44. Example 15 .2 A steel ... of Fracture Mechanics (Butterworths, London), 19 73. 416 Mechanics of Materials 4 15 .13 lead to the adoption of higher values. Since this could well result i...

Ngày tải lên: 10/08/2014, 12:21

... Introduction 11 .1. 1 The SIN curve 1 1. 1.2 PISIN curves 1 1 .1. 3 Effect of mean stress 1 1 .1. 4 Effect of stress concentration 11 .1. 5 Cumulative damage 1 1. 1.6 Cyclic stress-strain 1 1 .1. 7 ... eqns. ( 1 .12 ) and (1 .13 ) gives (1. 14) and combining eqns. (1 .lo) and (1. 1 1) gives I, + I,, = I, + I, (1. 15) Substitution into eqns. (1....

Ngày tải lên: 10/08/2014, 12:21

... del 2 (11 t dsl + (12 t dS2 ~ ) = pdsl .dS2 2 2 Fatigue, Creep and Fracture 50 1 a- da = i 1 (1 12~&iii)~.* 0.0 05 = 14 .8( -11 .88 + 11 78) = 11 56 cycles. Example 11 .13 In ... + C) 10 23 (1, 3000 + C) = 10 73 (1, 50 0 + C) 10 23(8.0064 + C) = 10 73(6. 214 6 + C) 819 0 .5 + 10 23C = 6668.27 + 10 73C 15 22.23 = 50 C C = 30.44. 5...

Ngày tải lên: 10/08/2014, 12:21

... University Press, New York, 19 98. Hertzberg, R.W., Deformation and Fracture Mechanics of Engineering Materials, 3rd ed., Wiley, New York, 19 89. x Chapter 1 Introduction 1. 1. HISTORICAL BACKGROUND Fatigue ... consideration in the disciplines of solid mechanics or strength of materials. In fact, one of the earliest researchers to address the topic was Wöhler [1] , who, in...

Ngày tải lên: 03/07/2014, 20:20

... Fatigue Limits 33 800 10 00 12 00 14 00 16 00 18 00 10 3 10 4 10 5 10 6 10 7 10 8 10 9 10 10 Surface initiation Subsurface initiation Stress amplitude (MPa) Cycles to failure SUJ2 R = 1 Figure 2.8. Fatigue ... different from that at the subsurface has been a common 0 200 400 600 800 10 00 12 00 10 3 10 4 10 5 10 6 10 7 10 8 10 9 10 10 10 11 Surf...

Ngày tải lên: 03/07/2014, 20:20

... −3 01 9E +11 0 1 5 95 6E +14 0 5 −4 91 0E +12 08 −7 51 9E +11 0 10 20 30 40 50 010 20304 050 59 Hz HCF data Alternating stress (ksi) Mean stress (ksi) R = 1 R = –0.33 R = 0.8 R = 0 .5 R = 0 .1 46 ... Number of tests k m Walker exponent, w A R ≤−0 1 @ 59 Hz 24 5. 83E16 −7 17 0 16 5 C R ≤−0333 @ 59 HzR= 0 1 @ 370–400 Hz 20 7.63E16 −698 03 817 52 Introduct...

Ngày tải lên: 03/07/2014, 20:20

... specimens. 56 Introduction and Background 0 0 .5 1 1 .5 2 1 –0 .5 0 0 .5 1 Haigh equation k 1 = 0.0, k 2 = 1. 0 k 1 = 0. 25, k 2 = 0. 75 k 1 = 0 .5, k 2 = 0 .5 k 1 = 0. 75, k 2 = 0. 25 k 1 = 1. 0, k 2 ... function of mean stress can give guidance on the role that residual stress can play in altering the fatigue Characterizing Fatigue Limits 59 0 0.2 0.4 0.6...

Ngày tải lên: 03/07/2014, 20:20